Partial derivative of a parametric surface, part 2

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  • เผยแพร่เมื่อ 23 พ.ค. 2016
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    Taking the same example surface used in the last example, we now take a look at the partial derivative in the other direction.
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ความคิดเห็น • 20

  • @IamFilter94
    @IamFilter94 7 ปีที่แล้ว +68

    2:34 that sound effect

    • @chao.j
      @chao.j 4 ปีที่แล้ว +1

      that deserves a Grammy :-D

    • @fishermanwithfishes2286
      @fishermanwithfishes2286 4 ปีที่แล้ว +4

      what you hearing is a derivative of the actually effect

    • @colemanchristy2770
      @colemanchristy2770 4 ปีที่แล้ว +7

      Turn on subtitles

  • @goclbert
    @goclbert 5 ปีที่แล้ว +24

    Vroop doop doop will now be the noise I hear whenever I do a transformation

  • @anonymous_4276
    @anonymous_4276 3 ปีที่แล้ว +3

    Thanks a lot. This entire playlist needs more attention imo. It's extremely helpful.

  • @shivammalviya3737
    @shivammalviya3737 3 ปีที่แล้ว +8

    "Vroop doop doop"

  • @haroonq7876
    @haroonq7876 4 ปีที่แล้ว +3

    Well sir once you put that (s, t) plane on the (x, y) plane you make things easy to understand, infect it tell's us these things actually means, so you have done a wonderful job.

  • @MayankGoel447
    @MayankGoel447 2 ปีที่แล้ว +3

    Finally, understood parametric curves represent 1 input, basically a 1D line stretches and curves in 3D space. Similarly, Parametric surfaces correspond to 2 inputs, a plane which bends and curves in 3D space.
    Is there a name for 3D input to 3D output transformation?

  • @randomstuff9960
    @randomstuff9960 3 ปีที่แล้ว +5

    Voiced zooming sounds...😅

  • @Promixro
    @Promixro 8 ปีที่แล้ว +1

    thanks

  • @Team-pj1nj
    @Team-pj1nj 6 ปีที่แล้ว +1

    does the gradient of vector V which can be written as [partial v partial s, partial v partial t] point to the steepest ascent? and if it is/isn't why?

  • @xeooox
    @xeooox 2 ปีที่แล้ว +1

    My right ear can do math now

  • @jeffgalef121
    @jeffgalef121 7 ปีที่แล้ว

    You stated that dv is not small because it's scaled by a very small ds. But, isn't that always the case with derivatives? That is, isn't the denominator always really small? In other cases, you still only get a really small dv/ds value.

  • @vergelimit8654
    @vergelimit8654 6 ปีที่แล้ว +1

    Is it really cheating though? Wouldn't the T/S plane be exactly where you placed it in 3d space?

    • @henitmandaliya
      @henitmandaliya 6 ปีที่แล้ว +1

      He shows transformations like this one (2-D to 3-D) using this animation to show the points on the old T/S plane being mapped onto the new 3-D space and how any movement on the old plane corresponds to movement on the new surface illustrated by the function. So no, he's not actually cheating and the T/S plane doesn't move per say but the points on it are shown to move through the transformation.

    • @adityaprasad465
      @adityaprasad465 4 ปีที่แล้ว

      The 3D space is x/y/z. There's nowhere the t/s plane "would" be, other than on a completely separate graph.

  • @gameblamerfan
    @gameblamerfan 8 ปีที่แล้ว

    sick I'am still in trigonometry :(

  • @desrucca
    @desrucca 2 ปีที่แล้ว +1

    Why dont just slice the plane like the earlier video?

    • @amineaboutalib
      @amineaboutalib ปีที่แล้ว +1

      because those were bivariate functions with one value