@@abhijeet246 i'm doing water quality modelling with qual2kw, and it requires some data that can only be achieved by manual calculations esp with some restrictions in this pandemic situation.
@@sarvanigade3266 that's good to know!!..And all the best for your exams..If you face any doubts regarding fluid mechanics and open channel flow..Write to me at abhijeet.lade@gmail.com good luck!!
Thanks for your concern sir...anyway first of al I ll try watching all the videos in this channel on fm and still if confused...I will mail you...thank you sir
Hi Faisal, the solution to your question I an writing here 1. Both Q and V are given, so we can find flow area A simply using Q = V x A So A = Q/V = 48 / 1 = 48 m2. 2. As it is a Trapezoidal section, flow area A = By + my^2. Now we are given that B/y = 2. So B = 2y. Therefore A = (2y) y + 1 x y^ 2 and A is 48 m2. Solving for y we get y = 4 m. And B = 2y = 8 m. 3. As B and y are known, we can find P directly by formula P = B + 2y√(1+m2) = 19.31 m. Therefore R = A/P = 48/19.31 = 2.48 m 4. To find bed slope S, use Manning as Manning's constant n is given n = 0.02 V = (1/n) x R^ (2/3) x S^ (1/2) 1 = (1/0.02) x 2.48 ^ (2/3) x S^(1/2) Therefore S= 0.001191
Sure.. No problem..i have covered the basic concepts of OCF in this playlist. But you can tell me the topics or problem on open channel that you want.. I will be happy to make videos on that.
m is symbol for side slope of the section. It is 1 unit vartical : m unit horizontal. For example if the side slope is 45 degrees, then slope is 1:1 so m would be 1.
About hydraulic radius and hydraulic mean depth you are telling just formula but not explaining what it mean really in practical by using that diagram. It will be better to get that original visualisation of hydraulic depth rather than a bihearted firmulae
The best description of the open channel characteristics
Thanks David! Do subscribe for more, happy learning
You are the best. I have to admit your in-depth understanding of this topic. Thank you
Thank you so much ❤❤❤
@abhijeet246 kindly prepare hydraulic design of culverts using rational methods. We will eagerly wait you
@@kntv4856i will surely try to upload on that!!
@@abhijeet246 i will be eagerly waiting
You are amazing , your student from Egypt Thank you a lot sir , much respect for your brilliant way on Teaching
Thank you so much ❤
Great Explanation, Please continue doing the same way of teaching.
Thanks❤
Thank you for your explanation. It made it so much easier to understand.
@@ricorico8786 thanks ❤️
The best Indian Teacher
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Thanks sir for giving such a great description about the elements of open channel flows
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Sir you are genius.
Thanks for the appreciation!!
thank you! this video helps me on making progresses over my thesis
Thank you so much!!
That is the topic of your thesis
@@abhijeet246 i'm doing water quality modelling with qual2kw, and it requires some data that can only be achieved by manual calculations esp with some restrictions in this pandemic situation.
@@shampoo740 sounds interesting !!!..I guess your doing hydraulic computations ...All the best!! I am glad that my videos are o some help to you
@@abhijeet246 thank you! yess i was stuck on that part and your video helps me add some options to break through this "stuck" phase :"D
Thank you so much for explaining it so well.
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Excellent explanation siirr...
Thanks Rohit !!!
Thank you so much for this nicest lecture
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great video
@@RoshanPandey-m7q thank you ❤️
Thanks for making it easier to understand
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Sir You Are Teaching The Best
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Thank u so Much.Its ReallyHelpful.
Kamal krdiya sir ji
Wow amazing
Thanks!!
Thank you for this video sir..
It made my concepts clear.
Pleasure!!
Thank you sir for this video, i was confused in these terminologies and was unable to start this topic. It was really helpful.
Pleasure Zakir!!
Greatttt...shared ittt!!!!!
Thank you Sarvani!!!
@@abhijeet246 cleared off my confusion...need your wishes for my psc ae exam upcoming😍
@@sarvanigade3266 that's good to know!!..And all the best for your exams..If you face any doubts regarding fluid mechanics and open channel flow..Write to me at abhijeet.lade@gmail.com good luck!!
Thanks for your concern sir...anyway first of al I ll try watching all the videos in this channel on fm and still if confused...I will mail you...thank you sir
@@sarvanigade3266 absolutely!!
Thank very much now i understand
Pleasure Anezwa ❤
Pls which textbook are you using for this
@@kilobyte7814 subramanya open channel hydraulics
Thank you so much sir
Enjoyed your lecture 👌
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Thank you Boss!!!
thanks sir u made it simple as water
Pleasure !!.. 🙂
Perfect.
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Thank you sir! Very helpful video!
Pleasure ❤
sir hydraulic radius or hydraulic mean depth depth same hain different( answer with reference )
Q=48m^3/sec
V=1m/sec
Side slope =1:1
n=0.02
B/D=2
S=?
P=?
It is a trapezoidal canals
Hi Faisal, the solution to your question I an writing here
1. Both Q and V are given, so we can find flow area A simply using Q = V x A
So A = Q/V = 48 / 1 = 48 m2.
2. As it is a Trapezoidal section, flow area A = By + my^2. Now we are given that B/y = 2. So B = 2y.
Therefore A = (2y) y + 1 x y^ 2 and A is 48 m2. Solving for y we get y = 4 m. And B = 2y = 8 m.
3. As B and y are known, we can find P directly by formula P = B + 2y√(1+m2) = 19.31 m.
Therefore R = A/P = 48/19.31 = 2.48 m
4. To find bed slope S, use Manning as Manning's constant n is given n = 0.02
V = (1/n) x R^ (2/3) x S^ (1/2)
1 = (1/0.02) x 2.48 ^ (2/3) x S^(1/2)
Therefore S= 0.001191
Please let me know if the answer is helpful and if you have any doubts feel free to comment.
@@abhijeet246 thank you sir
thank you sir, the video is so helpful
I am glad 😊
Why we us depth is twice
Sir can u make more videos on open channel flow for STATE LEVEL EXAMS PLZ SIR
Sure.. No problem..i have covered the basic concepts of OCF in this playlist. But you can tell me the topics or problem on open channel that you want.. I will be happy to make videos on that.
Thank you soo much sir 💗
Pleasure ❤❤
is m symbol in angle?
m is symbol for side slope of the section. It is 1 unit vartical : m unit horizontal. For example if the side slope is 45 degrees, then slope is 1:1 so m would be 1.
Thanks
Thank you sir
Pleasure!!
y is height right
Y is the flow depth
m is length
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👏👏👏
Thank you sir...
Tnx
Sir hindi
M batayiye
About hydraulic radius and hydraulic mean depth you are telling just formula but not explaining what it mean really in practical by using that diagram. It will be better to get that original visualisation of hydraulic depth rather than a bihearted firmulae
Good suggestion.. You can also share what you know.. It will be helpful to everyone..
Thank you so much sir ..❤.
Pleasure Irene ❤