THANK YOU. Now it’s obvious the arc length is r*theta. I just don’t calculate arc lengths much and had forgotten. Used to the segment area of (theta/2)*r^2 but ya, r*theta because Circumference = 2*pi*r, multiplied by the theta/2*pi the segment has gone around, the 2*pi over 2*pi cancels and you’re left with r*theta.
tips for some like me who still struggle to see why the "r" is here. This "r" is not the radius of the circle, it's a variable that can take any value from 0 to R where R is the radius of the circle.
You just saved my life.... That 'r' was killing me... Now I can peacefully continue with my work.....thank you very much
LOL, you're very welcome!
😆😆same ...that "r" is the reason I'm in my bed
As someone who hasn’t taken calculus in a few years, this sprung my brain back to action, thank you.
THANK YOU. Now it’s obvious the arc length is r*theta. I just don’t calculate arc lengths much and had forgotten. Used to the segment area of (theta/2)*r^2 but ya, r*theta because Circumference = 2*pi*r, multiplied by the theta/2*pi the segment has gone around, the 2*pi over 2*pi cancels and you’re left with r*theta.
Cheers, you're very welcome!
tips for some like me who still struggle to see why the "r" is here. This "r" is not the radius of the circle, it's a variable that can take any value from 0 to R where R is the radius of the circle.
Nice!
Yeah, I like to see it as the "current radius" or "iterative radius". I don't know if it has an actual name
Thank you~ I absolutely understand! :)
Cheers you got it:)
thaks so much professor ;* :*
You're very welcome, I am just a math teacher, not a professor but thank you!
does the same apply if we are in 3d?
Underrated 😍
I agree!
Good work bro
Thank!
Thank you......😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘that 'r' thing was maddening me....Now I got that.
You're very welcome, sorry I missed this comment!
Chrystal clear, thank you!
Thanks John!
Thanks
Thanks so much.
Cheers!
Awesome. Succinct.
Great help
Cheers
much thanks
You're welcome Keaton!
YA understood now, yaaa
Thank you my dude, found this in spam for some reason!
Understood in grafh and the jacobian but not yet in algebraic
And it's killing me
@@hzkzg1614 I have a video on that!
th-cam.com/video/tVJyy6ggRMQ/w-d-xo.html
So, why does rdθ=y ?
I explained in the video, the infinitesimal rectangle is not dx by dy there is a curved part.
@@ChristGodinyouItrust Oh! Thanks a lot! Finally, figure it out.
@@Mark-vr2nx Cheers!