Logic Puzzle 10 - Loyd's Clock

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  • เผยแพร่เมื่อ 17 พ.ย. 2024

ความคิดเห็น • 8

  • @ArjunSingh-ms1oo
    @ArjunSingh-ms1oo ปีที่แล้ว +2

    omgggggggggg took me 10 mins to figure out I needed to cut the numbers up - like instead of XI its X separately and I separately. Great question. I was wondering how I could evenly separate 19.5 since it ain't a whole number

    • @LogicPhilosophy
      @LogicPhilosophy  ปีที่แล้ว

      LOL! I was in the same boat! Kept thinking I didn't know how to do basic math.

  • @DeconvertedMan
    @DeconvertedMan ปีที่แล้ว +3

    IS IT CAKE? :D
    No, the cake is a lie. ;)

    • @LogicPhilosophy
      @LogicPhilosophy  ปีที่แล้ว +1

      LOL. I watched the first season of that show. Strangely mesmerizing!

    • @DeconvertedMan
      @DeconvertedMan ปีที่แล้ว

      @@LogicPhilosophy Its a cake! :D

  • @philosophyversuslogic
    @philosophyversuslogic ปีที่แล้ว +5

    I've got the answer! Hell, I thought I couldn't do it.
    So, first of all 78 doesn't good if to sum all the numbers, 'cause 78/4 cannot be divided as an integer. What about the numbers as IX or VI? These can be cut into two, for instance "I/X" or "V/I". That idea of cutting numbers came to me, when I blindedly wanted to divide everything into the 19 (I firstly thought I could do this). So, one number helps us to solve it - this is IX. Because if we use them separately, we can achieve 80. And 80/4 is a good one. So, what we need to do:
    a) we take IX and cut it into two I/X, and take a X
    b) then we round the next XI and VIII + I (from the previous)
    c) then XII + VII + (I from IV below, that is also should be cut into "I/V")
    d) the rest part is also sum to XX

    • @LogicPhilosophy
      @LogicPhilosophy  ปีที่แล้ว +1

      Absolutely genius! It took me forever to figure this out. It requires creative thinking rather than raw deductive power! Per your (c), you can also just use XII, I and VII instead of XII, VII and the I from VI. On a side note, I tried to see if you could cut it into five equal parts (introducing another hallucination) but couldn't get it to work. Not sure if there is an answer to that.
      On another side note, when I asked ChatGPT to try to solve the puzzle involving only three parts, here is what it said:
      "Here's one possible way to divide the clock into three parts:
      Part 1: XII (12) - I (1) - XI (11) - II (2) - X (10)
      Part 2: III (3) - IX (9) - IV (4) - VIII (8)
      Part 3: V (5) - VII (7) - VI (6)
      Let's calculate the sums for each part:
      Part 1: 12 + 1 + 11 + 2 + 10 = 36
      Part 2: 3 + 9 + 4 + 8 = 24
      Part 3: 5 + 7 + 6 = 18
      In this distribution, we have three parts with sums of 36, 24, and 18, respectively. Although they are not exactly equal, they are as close as possible using the given set of Roman numerals on the clock face."
      LOL!

    • @philosophyversuslogic
      @philosophyversuslogic ปีที่แล้ว +2

      @@LogicPhilosophy Oh, I didn't use that chat. (I don't like robots.)
      Do thank you also for providing this example! I must say you - this is not just a riddle for me. When I was a very young kid (I don't remember how old) something happened (I also don't remember it) and this made me very sad. I thought then, what if I couldn't go anywhere, or couldn't move, what should I do? - I thought that I must find the way out if such things occurred. And a thought visited me that at least I could keep staring at the wall (if a wall was nearby) trying to find there 'a little/tiny world'. So, briefly say - to find something in the small area. That is why when I saw the riddle you presented, I couldn't even stop watching; that rusty psychological mechanism of mine (gosh, I sound like a writer :) ) came alive. It was not just a question for me; no, that was something as more, than just a challenge.
      By the way, I took a name for the channel, but I didn't know there was yours. Sorry for that. I use it for my students.
      Good luck to you! Greeting from Kharkiv, Ukraine! 💙💛