Usually M < sqrt(L1×L2)... Here I guess M < 4 is allowed. M=2 is maybe reasonable values. If L1-M negative would the current be in opposite phase? Extremely hard initial value setting case. I couldn't see it well how the voltage sources polarity was selected (that is below inductance M) - what if put above M rather than below M? Sign selected according to current I1+I2 direction. The handling of the mutual inductance seems risky or complicated.
Very helpful and thanks Mr. Haddad.
Usually M < sqrt(L1×L2)... Here I guess M < 4 is allowed. M=2 is maybe reasonable values. If L1-M negative would the current be in opposite phase? Extremely hard initial value setting case. I couldn't see it well how the voltage sources polarity was selected (that is below inductance M) - what if put above M rather than below M? Sign selected according to current I1+I2 direction. The handling of the mutual inductance seems risky or complicated.
This is from Nilsson and Riedel 11th ed, Chapter 13.
What book is it? I appreciate if you say me that..!
electric circuit - nilsson riedel
Textbook:
William Hayt, Jack Kemmerly, and Steven Durbin. Engineering Circuit Analysis. 8th ed. McGraw Hill, 2012.
@@room147 I just saw it in Nilsson and Riedel 11th ed, Chapter 13.