Antennas Part I: Exploring the Fundamentals of Antennas - DC To Daylight

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  • เผยแพร่เมื่อ 14 พ.ค. 2024
  • Derek has always been interested in antennas and radio wave propagation; however, he's never spent the time to understand how the wiggling of electrons in a wire can actually produce RF radiation.
    So, in this theory-based episode of DC to Daylight, Derek discusses antenna physics, shows how a dipole antenna radiates RF, and demonstrates how that RF behaves with a receiver antenna. And, where Derek needs some help with the details, he calls in an expert, Sterling Mann, who works in the field of RF. In the next application-based episode, we'll build our own antenna and use it to communicate around the globe!
    Watch the full interview with Sterling Mann and ask Derek questions on the element14 Community! bit.ly/3IIVEKl
    Engage with the element14 presents team on the element14 Community - suggest builds, find project files and behind the scenes video: bit.ly/3tmdewv
    Visit the element14 Community for more great activities and free hardware: bit.ly/3q6YMpu
    Tech Spotlights: bit.ly/3qPrDhM
    RoadTest and Reviews: bit.ly/3pV5Bux
    Project14: bit.ly/31wbnJY
    #0:00 Welcome to DC To Daylight
    #1:20 Antennas
    #3:05 Sterling Mann
    #4:05 What Is an Antenna?
    #6:18 Maxwell's Equations
    #9:25 Sterling Explains
    #12:55 Give Your Feedback
    #antenna #antennas #radiofrequency #maxwellequations #dipole
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ความคิดเห็น • 81

  • @element14presents
    @element14presents  ปีที่แล้ว +3

    Watch the full interview with Sterling Mann and ask Derek questions on the element14 Community! bit.ly/3IIVEKl

  • @Rouverius
    @Rouverius ปีที่แล้ว +17

    So much to learn here. Looking forward to part 2!

    • @AmRadPodcast
      @AmRadPodcast ปีที่แล้ว +2

      Thanks! It's quite a lot of information to cram into one video, so we needed to split it up. Yes, part 2 is coming soon - and as usual, there will be an application video to follow. Happy to have you! -Derek

  • @7alfatech860
    @7alfatech860 ปีที่แล้ว +4

    We really appreciate you, future Derek

    • @AmRadPodcast
      @AmRadPodcast ปีที่แล้ว +1

      Thanks 7Alfa - I always appreciate your supportive comments.

  • @pratikbhatt9638
    @pratikbhatt9638 ปีที่แล้ว +3

    Really appreciate your efforts. Keep it up and waiting for Part-2 🤟

  • @WECB640
    @WECB640 ปีที่แล้ว

    Thanks Derek for sharing. Antennas have always been captivating and fascinating. As hams, they are perhaps one of the best parts of the hobby to experiment and laarn from, and I encourage ALL to build their own when they can. 73

  • @vaseemmehrancp9372
    @vaseemmehrancp9372 12 วันที่ผ่านมา

    Very nice presentation

  • @richardphillips2405
    @richardphillips2405 ปีที่แล้ว +1

    Thank you for this video. I did have trouble in understanding the section on Maxwell's equations. I will have to spend some time on that.

  • @Hiram8866
    @Hiram8866 ปีที่แล้ว +1

    The best explanation of antennas.

  • @pesekmar
    @pesekmar ปีที่แล้ว +6

    That was great... much more of that please! :)

    • @AmRadPodcast
      @AmRadPodcast ปีที่แล้ว

      Excellent... You got it! -Derek

  • @FredHendrix
    @FredHendrix ปีที่แล้ว +1

    Thank you for the informative presentation.
    Derek is sporting a sweet looking hat. 🤘

  • @arnotek
    @arnotek ปีที่แล้ว +2

    Yeah, antennas have always been "black magic" to me, now they are "magic". Looking forward to part 2. I am learning a lot from your channel - thanks!

    • @AmRadPodcast
      @AmRadPodcast ปีที่แล้ว

      That's awesome to hear that it's more understandable now - so glad you are here. Believe me, this is one of those topics that I still have difficulty wrapping my head around, because I can't see the thing! More cool stuff in the pipeline so make sure to come back. -Derek

  • @deltoid77-nick
    @deltoid77-nick ปีที่แล้ว +2

    I had a hunch about this information but now it's all so crystal clear.

    • @AmRadPodcast
      @AmRadPodcast ปีที่แล้ว

      Thanks. I hope it was helpful. More practical antenna content is coming in part II. -Derek

  • @liljonwask
    @liljonwask ปีที่แล้ว +1

    Wow so well explained 👏

  • @hagopboghossian6841
    @hagopboghossian6841 ปีที่แล้ว +2

    Great tutorial 👌

    • @AmRadPodcast
      @AmRadPodcast ปีที่แล้ว +1

      Thanks Hagop. It was fun.. Keep coming back, because we're going to talk more about antenna engineering and after part II there'll be the application video which is going to be a blast. -Derek

  • @TheSmokinApe
    @TheSmokinApe ปีที่แล้ว +1

    Great job Derek 👍

    • @AmRadPodcast
      @AmRadPodcast ปีที่แล้ว

      Thanks for checking in!

  • @Hacker-at-Large
    @Hacker-at-Large ปีที่แล้ว +2

    Yay! Calculus and linear algebra!

    • @AmRadPodcast
      @AmRadPodcast ปีที่แล้ว

      Not tooooo much though. -Derek

  • @MOHAMAD_ABDO_ALHOWARY
    @MOHAMAD_ABDO_ALHOWARY ปีที่แล้ว +2

    great explanation ! ♥️🇲🇦

  • @wodowiesel
    @wodowiesel ปีที่แล้ว +1

    very kewl :) like such topics

  • @bramfran4326
    @bramfran4326 ปีที่แล้ว

    WHERE IS PART 2!? Not out yet? Nooooo, can't wait!
    Thank you, my favourite part was at 11:00.

    • @AmRadPodcast
      @AmRadPodcast ปีที่แล้ว +2

      It's in the pipeline.. The animation *is* mesmerizing. Thanks for the feedback. -Derek

  • @vaseemmehrancp9372
    @vaseemmehrancp9372 12 วันที่ผ่านมา

    Second part pls

  • @mewintle
    @mewintle 3 หลายเดือนก่อน

    “Assuming *your* earth is spherical”
    Hahahaha! Nice burn.

  • @naturalmilkhoneyandzenretr9508
    @naturalmilkhoneyandzenretr9508 3 หลายเดือนก่อน

    How do you power the antenna? How do you recieve the power in the receiver?

  • @nareshkumar4207
    @nareshkumar4207 6 หลายเดือนก่อน

    Any possibility to explain its mathematical derivations

  • @forbaldo1
    @forbaldo1 4 หลายเดือนก่อน

    at 8 min it almost started then back to chatting with friend about arithmetic and a bit of math

  • @richardphillips2405
    @richardphillips2405 ปีที่แล้ว

    I would like to ask you for help on measuring rf field strength. Is there an accurate way to measure the rf field where the location is inside of one wavelength? I would like to measure frequencies that are in the hf amateur radio bands starting at 1.7 mHz and going up to 30 mHz. Do I want to measure the e-field or the h-field? I think that the e-field would be easier to measure. The equipment I have is a Siglent spectrum analyzer which I believe to be accurate and I have an older field strength meter, EFS-1, which works but I am not sure about the calibration. I read a paper from Keysight Technologies which describes how to use a spectrum analyzer to measure the e-field. (859xE: How Do You Measure
    Electric Field Strength with an
    Antenna and Spectrum
    Analyzer?) I'm not sure about what they call the antenna factor which gives volts/meter in terms of dB's. I checked into buying an accurate rf field strength meter that can measure lower hf frequencies. I found them to be very expensive. What is driving this project, is the FCC requirement to measure rf exposure around the amateur radio station. The ARRL has an online rf exposure calculator. I have several unknown factors at my station and I would like to be more accurate. I also want to learn more about rf fields. Thank you.

  • @ats89117
    @ats89117 ปีที่แล้ว +1

    The discussion of the transition from separate E and M fields in the nearfield to an EM field in the farfield was a little muddled. The discussion in wiki is pretty good. One picture that is missing is the transition from either a high characteristic impedance at the antenna-free space interface from a dipole, or the low characteristic impedance from a loop antenna to 120 x pi (377 Ohm) free space impedance. This is shown in Henry Ott's book on EMI...

    • @AmRadPodcast
      @AmRadPodcast ปีที่แล้ว

      Ott's book is a fantastic read. Highly recommend to all interested in EMI or radiated/conducted emissions and good info on layer stackup. Yes what you mentioned is missing. However, it's always difficult to determine how deep to go on a subject. Maybe in the future we can dig even deeper. -Derek

  • @guilhermeschweitzer8459
    @guilhermeschweitzer8459 ปีที่แล้ว

    What intrigues me is how do electric field flows in an open circuit. It shoudn't a close circuit to electric field to flow?

  • @Morten_Jaeger
    @Morten_Jaeger 10 วันที่ผ่านมา

    8:20 No, an electric field can indeed exist without an magnetic field, and vice versa. The time term in Maxwells 3. and 4. equations just tells you than when one field is changed over time, the other is induced.

  • @FEPLabsRadio
    @FEPLabsRadio ปีที่แล้ว +1

    Outstanding info. When future Derek had the Sabbath shirt on, he was awesome! Just sayin...

    • @AmRadPodcast
      @AmRadPodcast ปีที่แล้ว

      Thanks Jim! That future guy is a troublemaker. (And we only talk about future Derek in future tense) 😁

  • @NowInAus
    @NowInAus ปีที่แล้ว +1

    The simple reason why antennae produce rf is that the driving signal is accelerating electrons in the aerial conducting material. accelerating electrons radiate electromagnetic radiation.

    • @AmRadPodcast
      @AmRadPodcast ปีที่แล้ว

      Hi Andy. Thanks for your comment. Unfortunately, I have trouble with simple reasons! 🙃
      True, accelerating charged particles radiate RF, (intended and un-intended radiators) but I thought it would be fun to look under the hood of Maxwell (or maybe it was just an excuse to talk to Sterling). 😀 -Derek

  • @chriswesley594
    @chriswesley594 2 หลายเดือนก่อน

    9:25 "Sterling Explains". Hahahaha. yeah. Sterling doesn't know, but it took him a long time to fail to say it.

  • @Allan_aka_RocKITEman
    @Allan_aka_RocKITEman 11 หลายเดือนก่อน

    At about 02:02 in this video:
    *_"Ah, nuts...."_*
    🤭🤭🤭

  • @h7opolo
    @h7opolo 4 หลายเดือนก่อน

    Halfway decent

  • @easyerthanyouthink
    @easyerthanyouthink ปีที่แล้ว +1

    Thank for your video, but vital info seems to be missing.
    As in most rf videos.
    Still a good video though

    • @AmRadPodcast
      @AmRadPodcast ปีที่แล้ว

      That is great to hear! I didn't want this to be the same format as most other antenna videos.. and I've watched quite a few. Make sure to come back for part II and maybe some of the missing vital information will be there. -Derek

  • @petersage5157
    @petersage5157 ปีที่แล้ว +1

    Integral? I do enjoy a good calculus pun.
    e to the x was at a party for math functions and tried to integrate. It didn't make any difference.

    • @AmRadPodcast
      @AmRadPodcast ปีที่แล้ว

      Ha! My wife says pi r squared. I say they're round. -Derek

    • @petersage5157
      @petersage5157 ปีที่แล้ว +1

      @@AmRadPodcast Pi and 22/7 were roommates, and they constantly got on each others' nerves, as roommates are wont to do. At one point, 22/7 asked Pi "Why do you have to be so irrational?!" Pi retorted "Stop repeating yourself!"

    • @AmRadPodcast
      @AmRadPodcast ปีที่แล้ว

      @@petersage5157 😆

  • @JensenPlaysMC
    @JensenPlaysMC ปีที่แล้ว +1

    J is not displacement current, mu0 de/dt is. Also an E field can exist without a B field, just not a solenoidal one.

    • @AmRadPodcast
      @AmRadPodcast ปีที่แล้ว

      Thanks for your comment. I think the viewer understands that when we're speaking about E and B fields coexisting, we're referring to an electromagnetic wave.

    • @erykbaradziej3639
      @erykbaradziej3639 ปีที่แล้ว

      @@AmRadPodcast There is also an error in the equation 8:28 - there should be no factor 1/c^2. This factor, or epsilon0*mu0, is to be found in the wave equations derived from Maxwell's equations: (1) Nabla^2*E-epsilon0*mu0*(de^2_E/de_t^2)=0 for electric field and (2) Nabla^2*H-epsilon0*mu0*(de^2_H/de_t^2)=0 for magnetic field. Because there is formula epsilon0*mu0=1/c^2 for the speed of light in vacuum we can also write Nabla^2*E-(1/c^2)*(de^2_E/de_t^2)=0 and Nabla^2*H-(1/c^2)*(de^2_H/de_t^2)=0.
      Greetings from Poland!

    • @JensenPlaysMC
      @JensenPlaysMC ปีที่แล้ว

      @@erykbaradziej3639 This is wrong, The video is using SI units, The factor is correct.

    • @erykbaradziej3639
      @erykbaradziej3639 ปีที่แล้ว

      @@JensenPlaysMC Oh yes, you're right, excuse me. But I know different form of the equation (that is in a Polish book for students of electronics) which I mixed up with that of 8:28. The version is: Nabla x H = J + de D / de t where there are different vectors: H which is B / mu or B / mu0 in vacuum and D which is epsilon * E or epsilon0 * E in vacuum. This form is more clear in my view and it corresponds well with the previous Maxwell's equation: Nabla x E = - de B / de t . I also found a form: Nabla x B = mu * (J + epsilon * (de E / de t)). If we factorize this we achieve mu * epsilon or mu0 * epsilon0 which is mu0 * J and (1 / c^2) * (de E / de t) as in 8:28 because mu0 * epsilon0 = 1 / c^2.

  • @alfredkasereka2083
    @alfredkasereka2083 ปีที่แล้ว +1

    School never end? We thought we've left school, but no!

    • @AmRadPodcast
      @AmRadPodcast ปีที่แล้ว

      Never stop learning! Pull up a chair. 😁

  • @Mr.Beauregarde
    @Mr.Beauregarde ปีที่แล้ว +1

    U cut it there?!

    • @AmRadPodcast
      @AmRadPodcast ปีที่แล้ว

      Yeah, sorry had to cut it somewhere - unfortunately, that was the most natural place. However, if you hit the link in description, the full talk with Sterling is there. -Derek

  • @ayadeisabeloiii3665
    @ayadeisabeloiii3665 5 หลายเดือนก่อน

    Hi sir good day to you where ever you are i just want to ask a question about my ssb 710 icom why does the power supply flactuate whenever it transmit? Even other devices turn off suddenly whenever i talk.

  • @ashishkumarrana1
    @ashishkumarrana1 4 หลายเดือนก่อน +3

    why do you look like Tony stark ??

  • @thesteadyturtle4447
    @thesteadyturtle4447 25 วันที่ผ่านมา

    In vacuum 😂

  • @mibrahim4245
    @mibrahim4245 ปีที่แล้ว

    Thank you for the video .. but well, sorry Sterling but the black magic is still black magic :( ...
    the key thing to start with for the journey of understanding this magic is: "Kinks" ..
    but guess what, although I've went through the journey of "digesting" what really happens for the em wave to propagate, I'm unluckily still not satisfied :( ...

  • @ToolsAandLogic
    @ToolsAandLogic ปีที่แล้ว +1

    please speak slowly. because your videos are watch by people around world, not only english speaking people. please reduce your speech speed by 30 percent. Please

    • @philiplamoureux8951
      @philiplamoureux8951 4 หลายเดือนก่อน +2

      Good thing you tube offers the option to change playback speed.

    • @LogicAndTools
      @LogicAndTools 4 หลายเดือนก่อน

      With the playback speed control, still not good speech. Better, the speech in you tube video be reduced by a content creator.

  • @citizensteve6713
    @citizensteve6713 ปีที่แล้ว

    Typical, bait you in then here’s the subscription fee.

  • @tylerufen
    @tylerufen ปีที่แล้ว

    where do you guys make your money? you barely get any TH-cam views, you don't sell anything, there's not that much activity on your forum, ... is this just for you people to add to your resumes? i mean, great production values, but i'm just wondering what's in it for you, and why, despite seemingly working hard on this, why you're not working on getting more reach?
    ... Element 14 just seems kinda weird to me...

    • @7alfatech860
      @7alfatech860 ปีที่แล้ว +1

      Element14 is part of the big electronics components retailer Newark, which is I believe owned by Avnet. Avent also own Farnell in the UK

    • @element14presents
      @element14presents  ปีที่แล้ว +4

      Thanks, we're glad to hear that you believe element14 presents content, and the content by the video creators is worth sharing and we'd be glad to see it shared further!
      element14 presents is a part of the element14 Community as we're sure you've seen the links to the Community site, and it's easy to think that not a lot happens there, perhaps because there are so many different groups and categories, but there's more than simply one forum, there're many forums, comments, blog posts and documents to get involved with, and you're welcome to take part.
      As another mentioned, the element14 Community is a part of Farnell, a multi-national electronics distribution company, and Farnell is a part of Avnet. Frankly we don't typically post our products directly as links on our videos because we've responded to feedback that people don't want to see that. We can start doing that again if it's what people want, but really we want people to be a part of the Community and help Engineers and Makers to produce great projects, to inspire them, and learn and share their knowledge with others.
      Thanks for the comment and taking part.

    • @petersheldon3558
      @petersheldon3558 ปีที่แล้ว +2

      ​​@@7alfatech860 They also own CPC in the UK too, together the organisation is probably the biggest around!

    • @7alfatech860
      @7alfatech860 ปีที่แล้ว +2

      @@petersheldon3558 Didn't know that.
      Just want to clarify, I really enjoy the videos they put out on this channel, esp Derek and I have not noticed any commercial bias

    • @petersheldon3558
      @petersheldon3558 ปีที่แล้ว +2

      @@7alfatech860 I really enjoy them too, it makes a change from the video's which just want to sell you something, hopefully they keep up the good work as I'm looking forward to the next installment.

  • @waynesallee-com
    @waynesallee-com 5 วันที่ผ่านมา

    Don't split videos up into parts.