TIFR 2025 Mathematics Solution | TIFR 2025 Math Real Analysis Solution | TIFR 2025 Q.No 07 Solution

[@piyushjoshi5462]

I think S:={x=p/2^n |p is odd} is a dense set in R
that is a key fact here that leads to existence of any sequence in xn in S st xn --->c ( c being irrational or 0)

[@AlokRatnaMauryama24c006]

❤❤❤❤❤❤

[@jkmathematics..jitendrakoh8557]

Sir I have a doubt jab 2025 suru he nhi huwa tho ye question 2025 kese puchha gya sir

[@suranjanroy7528]

If we take a=p/2^m then any y belongs to R\Q(intersection)(a-delta,a+delta) we have /f(y) -f(x)/=1/2^m=epsilon..so f is not continuous at x=a

[@swarnavakundu4753]

H.W. Ans Yes

[@MATHEMATICSWANDERER]

Hw ans
Yes hoga x=1 pr

[@jagdishkumbhakar6452]

HW Ans-No ,since f is not continuous at x which is not equal to p/2^n €Q

[@akanksha5550]

H W ana - no

[@tadkamoviesmasaala]

Good morning sir,
Sir out of 25 attempts questions, only 22 are correct, any chance of selection in the written exam?😐 (Applying in integrated PhD)

[@AlokRatnaMauryama24c006]

Hw answer, Yes

[@everythingnice4609]

H.W. ans No

[@Checkmate-h7u]

Isko mne attemp hi nhi kiya muje c me doubt tha kyuki

[@smitasengar5821]

Hw ans Yes

[@dhenasaranya1614]

H.w.Ans NO

[@MercuryWorld-km3jc]

H.W Ans : No

[@saritasaini149]

H.W ans, yes

[@yograj_22]

HW ans NO

[@yograj_22]

Since it depends whether the rational is of the form p/2^n or p/q form

[@pavana2001]

HW ans No