Sir this facility provided by u all are very informative as well as very conceptual instead of just memorizing the formulas , we are very kind that IIT professors are teaching us.
transfer function is the ratio of laplace transform of the output to the laplace transform of the input. But the problem is that some functions like sin(wt) has no laplace transform (OR does it have a laplace transform? i am not sure, as sin(wt) can be written as sin(wt).u(t) + sin(wt).u(-t), and then for eash of these the laplace transform will exist maybe ) . Sin(wt).u(t) has a laplace transform. so shouldn't there be an extra condition for writing the transfer function? like the input should be applied at time t=0 and the output before t=0 should be zero? please can anyone explain?
@@AnkitYadav-zg5zd I am sorry if I offended you. I gave you the answer, that is to refresh your concepts of Laplace transformation. In this series itself, we were shown how to get the Laplace transform of sin(ax). By reading you original comment about, "whether it is possible to calculate Laplace transform of sin ... etc ... etc " I got carried away as how can one miss such an important example. I again sincerely apologise. I should have not said what I said. I thought that you must have figured out the correct explanation of your own problem since you posted the original comment months ago. I thought that by reading your own comment you would have realised "what the hell I was thinking" and would take my comment lightly and sarcastically. I am sorry. Hope you have a great day.
@@ayush7805 it's alright brother! i also went a little too far. sorry for that! Coming back to the question now.... see the laplace transform we deal with in the control systems in unilateral laplace transform (having the limit Zero to infinity in the laplace transform formula integration) . Actually Sin(at) has a unilateral laplace transform and the bilateral laplace transform (having the limit -ve infinity to infinity in the laplace transform formula integration) of sin(at) does not exist! if we write the transfer function of a system then we are actually writing the ratio of unilateral laplace transform of output to the unilateral laplace transform of the input. Right? But now once we got the transfer function of the system and we are asked to find the output of the system for a signal like sin(at) which exists for all time (-infinity
Sir this facility provided by u all are very informative as well as very conceptual instead of just memorizing the formulas , we are very kind that IIT professors are teaching us.
34:00 that is the doubt I also had. That is the advantage of studying control system in electrical engineering way.
Thank you sir for giving us lecturers
Sir Thank you for providing lectures
To be taught by a professor of iit great moment .no problem even it in the phone
Saurabh ku
ty very much sir
Thanks sir
Hw did do the last transfer function question...
35.48 how that -ve sign came for 3rd equation?
nice
transfer function is the ratio of laplace transform of the output to the laplace transform of the input. But the problem is that some functions like sin(wt) has no laplace transform (OR does it have a laplace transform? i am not sure, as sin(wt) can be written as sin(wt).u(t) + sin(wt).u(-t), and then for eash of these the laplace transform will exist maybe ) . Sin(wt).u(t) has a laplace transform. so shouldn't there be an extra condition for writing the transfer function? like the input should be applied at time t=0 and the output before t=0 should be zero? please can anyone explain?
pagal hai kya?
lol .. mzaak krr rha hu .. please go and refresh your laplace transform concepts
@@ayush7805 tera baap pagal! Mazak kar raha hu bhai! If you don't have the ans just keep your funny thoughts in your head!
@@AnkitYadav-zg5zd I am sorry if I offended you. I gave you the answer, that is to refresh your concepts of Laplace transformation. In this series itself, we were shown how to get the Laplace transform of sin(ax).
By reading you original comment about, "whether it is possible to calculate Laplace transform of sin ... etc ... etc " I got carried away as how can one miss such an important example.
I again sincerely apologise. I should have not said what I said.
I thought that you must have figured out the correct explanation of your own problem since you posted the original comment months ago. I thought that by reading your own comment you would have realised "what the hell I was thinking" and would take my comment lightly and sarcastically.
I am sorry.
Hope you have a great day.
@@ayush7805 it's alright brother! i also went a little too far. sorry for that! Coming back to the question now.... see the laplace transform we deal with in the control systems in unilateral laplace transform (having the limit Zero to infinity in the laplace transform formula integration) . Actually Sin(at) has a unilateral laplace transform and the bilateral laplace transform (having the limit -ve infinity to infinity in the laplace transform formula integration) of sin(at) does not exist! if we write the transfer function of a system then we are actually writing the ratio of unilateral laplace transform of output to the unilateral laplace transform of the input. Right? But now once we got the transfer function of the system and we are asked to find the output of the system for a signal like sin(at) which exists for all time (-infinity
Aaplog board pe kyu nhi pthate hai?
Subtitles are hiding the information please remove or make it small
Y did u skip La
Sir skipped rit?
Anyone from MIT?