Hi Lina. No worries. Did you get 1/3 for part A? In the words "Anywhere Math" there are 2 A's and 2 E's out of 12 total letters. So the probability of choosing an "a" or "e" is 4/12, which simplifies to 1/3. In other words, 1 out of every 3 times we choose a letter, we would expect to choose an "a" or "e". So for Part B, if we choose a letter 45 different times, we would expect 1/3 of the times to choose an "a" or "e". And 1/3 of 45 is 15. You do 1/3 times 45 to get 15 or you can set up a proportion like example 2 where 1/3 = x/45. Either way, you should get the same answer. I hope that helps. Let me know.👍
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For "on your own" question 1b, how did you get 15? Can you explain please? 😁
Hi Lina. No worries. Did you get 1/3 for part A? In the words "Anywhere Math" there are 2 A's and 2 E's out of 12 total letters. So the probability of choosing an "a" or "e" is 4/12, which simplifies to 1/3. In other words, 1 out of every 3 times we choose a letter, we would expect to choose an "a" or "e". So for Part B, if we choose a letter 45 different times, we would expect 1/3 of the times to choose an "a" or "e". And 1/3 of 45 is 15. You do 1/3 times 45 to get 15 or you can set up a proportion like example 2 where 1/3 = x/45. Either way, you should get the same answer. I hope that helps. Let me know.👍
@@AnywhereMath thank you so much, I did end up solving this on my own but thank you anyways 😊🙏
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What did y'all get for 2 example after 1b. I got 18😊
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