In electronics, a comparator is an electronic circuit that compares the voltage level of two input signals and outputs a binary signal indicating which input signal is greater. It is a type of operational amplifier (op-amp) circuit that has a very high gain and is designed to operate in its linear region. The comparator has two input terminals, one positive (+) and one negative (-), and one output terminal. The input signals are connected to the positive and negative input terminals, and the output signal is a binary signal that indicates whether the positive input is greater than or less than the negative input. When the voltage level of the positive input is greater than the negative input, the output of the comparator is high (logic level 1). When the voltage level of the negative input is greater than the positive input, the output of the comparator is low (logic level 0). Comparators are used in a wide range of electronic circuits, such as voltage level detectors, oscillators, and digital-to-analog converters. They are also commonly used in analog-to-digital converters (ADCs) to convert analog signals into digital signals.
Have to point out in the window comparator, the circuit works only when the op-amp has open collector output stage. It won't work if it has push-pull output, which is what many modern IC uses nowadays.
The video is really good. Thank u for ur time and efforts. Can u pls explain : 1. the use of external pull up resistor ? 2. the reason for connecting Vcc of upper OP AMP to Vout of lower one ?
The pull-up resistor ensures the output of the comparator is indeed logic high when both comparator output is high. If comparators are directly connected then it may happen that the overall output is less than the logic high value. And there might be ambiguity about the output. Using the pull-up resistor that uncertainty can be eliminated. For the second question, Vcc of the first op-amp is not connected to the output op-amp. Vcc is used for the pull-up resistor. And the pull-up resistor is connected to the output. And similarly, the output of the second comparator is connected to the overall output. I hope it will clear your doubt.
At 6:16 , when Vin < Vref the output should be negative saturation voltage, dont you think? but you showed zero level in the output graph . Plz clarify my doubt, if i'm missing the point?
Here is a suggestion for a topic : Different ways of connection between electronics circuits like open collector , compatibility between different logic families , wired and connection etc. Thanks
Consider you have a sensor which may be taking values of photoresistor and converting them into voltage. Assume that sensor is recording the following values. Max Value (Bright Light) ≈ 12 V (10% tolerance level) Min Value (Dark) ≈ -2V (10% tolerance level) Whenever the sensor reaches the value of ≈ 5V (10% tolerance level) a BlueLED must be ON and when it drops from 5V it should be OFF. The circuit is implemented using an amplifier which vaguely follows the idea of converting analog input into digital by using it as a comparator.
For the window comparator please note that if you connect the negative rail to ground, you will not output zero volts but rather a small positive voltage when the input is outside the range of the window. Further, the load in that circuit is drawn very poorly. The outputs of the two comparators should be joined into a single node which feeds one terminal of the resistor while the other terminal should be grounded.
It depends on type of comparator. Some comparators are single supply comparators. In such comparators the output will vary between Vaat and 0. In dual supply comparators the output varies between Vaat and - Vsat. I hope it will clear your doubt.
No, V- = V+, when the opamp is used with negative feedback ( in the linear region). When the opamp is used as a comparator then it is used in the open loop configuration. Therefore, it is not applicable.
actually your graphs are wrong for inverting and non inverting comparator because in case of non inverting comparator when Vin < reference then Vout = -Vsaturation not 0 and similar for inverting comparator , by the way your explanation is awesome :)
It actually depends on the comparator supply voltages. There are some comparators, where positive supply voltage is Vcc and negative supply voltage is 0. In some comparator its -VCC. For single supply comparators, the output will be zero, for the dual supply comparators, it will be -Vsat. I hope it will clear your doubt.
Hello, In my campus I am asked to do a project, I have to do a comparator circuit which detects whether the battery is below or higher a predetermined level. We have to Op-Amp comparator circuit, and also comparator circuit should be powered using the battery under test. Can you help on this, please?
Because in the window comparator, the output of the two op-amps are connected together using the pull-up resistor. So, their outputs will act as a wired AND connection. That means if any one of the op-amp output is low, then overall output will become low and the output of the window comparator is high when both the outputs are high.
great explanation, thank you! i have one question, i've been looking for a book that talks about this subject and some other subjects but couldn't find a good one yet. can you suggest me some good books that explains microelectronics well?
For basic electronics : electronics principles by malvino and electronic devices and circuit theory by Robert boylstead are good books. You can refer these books.
In minute 8:11 why does that configuration work as an AND? If one is at HIGH and the other at LOW why doesn't it blow up or something? Can someone explain me, please? thanks :)
I think you are talking about the window comparator. Yes, the outputs are connected to Vcc through one resistor. And because of that, the output behaves like wired AND gate.
Would you please clarify that from the circuit perspective, what would be the difference between an op-amp and a comparator? how are comparators faster than op-amps? Also, can you please explain the reason of adding the resistor?
op amp is optimized to provide accuracy and stability (both dc and dynamic) for a specified linear range of output values in precision closed-loop (feedback) circuits. It is achieved through internal compensation capacitor. But when the same op-amp is used in the open loop configuration as a comparator, then due to its internal compensation capacitor, its output cannot change very fast. On the other end, the comparators are meant to be operated in the open loop configuration. So, they do not require internal compensation capacitor. And because of that they are quite fast. I hope, it will clear your doubt.
Good explanation, but there’s something I don’t understand. How come op amps and comparators aren’t the same thing? Isn’t a comparator just an op amp without feedback?
Yes, op-amp can be used as comparators. But for that, the slew rate of the op-amp should be very fast. So, ideally all the op-amps can be used as comparator. But not all the op-amp will work perfectly as comparator. So, there are dedicated comparators ICs which will work as a comparator. So, internally they are op-amp itself, but optimized for fast transition. I hope it will clear your doubt.
Sir, can you plz explain "why in window comparator, the output is low when any of the comparator output is low..? I didn't understand it.. plz help sir
when any of the comparator output is low, the output of both comparators will be pull down to zero volt or low voltage. (Becuase it's wired and connection). That means the one terminal of the resistor (which is the output of the window comaprator ) will be at a low voltage. And the entire voltage will get dropped across the RL. I hope it will clear your doubt.
@@ALLABOUTELECTRONICS sir can you explain the significance of that pull up resistor too? What really happens when the output of both comparators are high... How we determine the overall output.. Plz help sir
The pull-up resistor ensures the logic high at the output. If you see, every circuit or every IC has limited output current capacity. That means the maximum current it can deliver. If more current is drawn then the output voltage reduces. And it might happen that the output voltage would become lower than the logic high value. This pull-up resistor maintain the logic high value when the output of the comparator is high. I hope it will clear your doubt.
I think you are talking about resistor RL in window comparator right? It serves two purposes. First, when the output of the comparator is low, it will restrict the sink current of the comparator. Second, when the output of a comparator is high, it will provide the strong logic high. I hope it will clear your doubt. And yes, at some time I will make a video on external pull up resistor.
Sir why in the waveform of non inverting comparator you made the output signal zero .....will that not be equal to -Vsat ?? In books it's given -Vsat Plzzzz help sir this is creating confusion in my concepts!
See, that depends on whether the comparator is a single supply or dual supply. In a single supply comparator, when the output of the comparator is high, then it will go towards the +Vsat, and when it is low, the output is zero. In dual supply comparator, there will be +Vsat and -Vsat. Here I am assuming its single supply comparator. In the book, it might be a dual supply comparator. (The biasing voltage to the comparator will be +Vcc and -Vcc) I hope it will clear your doubt.
At 9:04 iam confused that in window comparator why overall voltage is low if vin is less than either lower threshold voltage or upper threshold voltage
The output of the two compactors are connected. So, if any one of the output is low, then overall output will remain low. The output of the window comparator high, when both comparators outputs are high. In this case, it will happen when Vin >VL and Vin < Vh. So, basically, when the input voltage is within certain voltage band, then only the output of the comparator will become high. I hope, it will clear your doubt.
Thank you for this video, can I compare 10v and 1.5 while rail sources v-=-3.3 and v+3.3? or I can only compare values less than or equal to the rail sources ?
when Vin > VH at that time the output of the first comparator will be low and the output of the second comparator will be high. So, overall output will be low.
In ideal case, the output of the comparator will be zero. But in reality due to different bias currents at both inverting and non inverting terminal, the voltage at the two terminals will be slightly different. And because of that the output of the comparator will be either +Vsat or - Vsat.
If you use opamp in the open loop configuration ( without any feedback) then that itself will act as an amplifier. If you use opamp at the output of the opamp ( without feedback) then it will rectify the output.
Ideally, if both inputs are same then output should be zero. But practically that isn't the case. And even if you apply the same input to both input terminals, still you will see either +Vcc or -Vcc/ or 0V at the output (due to noise, offset voltage etc.)
If it does not go into the saturation then op-amp is operating in the linear region and it will work as linear amplifier. That is means vout = open loop gain* ( vin1 - Vin2) But for that input should be very small. Typically in uV.
sir, in 6:12 , the output waveform should give a negative saturation for all input less than reference voltage , i am confused by the way u have given only one side positive saturations. should the low outputs ought to be below axis ??.can u help me out
Many comparators are single supply, where the negative supply pin is grounded. In that case, the output will vary between Vsat and 0. When the comparator is biased with dual supply, (Positive and negative) then, in that case, the output will vary between +Vsat and - Vsat. Here the comparator is biased with the single supply. That's why the output is zero instead of negative Vsat. I hope it will clear your doubt.
Sir,in window comparator ,if input is less than low threshold value ,then comp1(upper comparator) should give high according to ur circuit design ?..u should keep the input on non inverting terminal of upper comparator (comp1) and modify the circuit ,if I m not wrong 🤔
When Vin is less than VL, then the output of the first comparator is high, but the second comparator is low. (ideally, the output of the second comparator is zero). So, it will pull down the overall output voltage to zero. (even though the output of 1st comparator is high) It acts like a wired-AND gate. That means the output will be high when both comparator output is high. I hope it will clear your doubt.
Is it possible for a quad op-amp to generate 3 window comparators. Specifically, if an RGB LED is used, how can I have ... Input (In) Comp-A (R) Comp-B (G) Comp-C (B) Colour In < 2.4V Low Low Low - 2.4V < In < 2.6V Hi Low Low R 2.6V < In < 2.8V Low Hi Low G 2.8V < In < 3.0C Low Low Hi B In > 3.0 Low Low Low -
Let's take the case when Vin is less than VL. In this case, the first comparator output will be high and the second comparator output will be low. And if you observe the output of both comparators are tied to gather. (Wired AND connection). So, even if first comparator output is high, it will be pulled down to a low voltage by the second comparator. And in this way, overall output will be low. I hope, it will clear your doubt.
Stability of the op-amp can be checked using the gain margin and phase margin. In simple terms, if I say, for the stability of the op-amp, when the gain of the op-amp reaches 1 (0 dB) at that frequency, phase should be less than -180 degree. And when phase angle reaches the -180 degree, at that frequency, the product of open loop gain and feedback factor should be less than 1.
try to follow the above mentioned two criteria. If you find that at your operating frequency the product of gain and feedback factor is greater than 1 and phase angle is less than 180 then change the feedback factor by adjusting the component values. Or if you use that circuit below the frequency where circuit becomes unstable, then you can avoid the instability.
You are talking about the digital 1 bit comparator right? The one which is discussed here is the analog comparator. In 1 bit comparator there are three conditions. Let's say A and B are the inputs. 1) A=B (It can be determined using XOR operation) 2) A>B (AB') 3) A
In the open-collector configuration, the output is taken through the collector of the internal transistor.To get the proper logic high and low, it is required to connect the external pull-up resistor at the collector. (resistor needs to be connected to Vcc at the collector).
In electronics, a comparator is an electronic circuit that compares the voltage level of two input signals and outputs a binary signal indicating which input signal is greater. It is a type of operational amplifier (op-amp) circuit that has a very high gain and is designed to operate in its linear region.
The comparator has two input terminals, one positive (+) and one negative (-), and one output terminal. The input signals are connected to the positive and negative input terminals, and the output signal is a binary signal that indicates whether the positive input is greater than or less than the negative input.
When the voltage level of the positive input is greater than the negative input, the output of the comparator is high (logic level 1). When the voltage level of the negative input is greater than the positive input, the output of the comparator is low (logic level 0).
Comparators are used in a wide range of electronic circuits, such as voltage level detectors, oscillators, and digital-to-analog converters. They are also commonly used in analog-to-digital converters (ADCs) to convert analog signals into digital signals.
Thankyou
Thank you very much ❤
I love you
the concept was easy but you make it big ....................5 min video will be enough for this video.............but it is good explanation
Aewsome stuff!!!! Keep up with the excellent work! It helped me a lot. Thanks, man :D
Have to point out in the window comparator, the circuit works only when the op-amp has open collector output stage. It won't work if it has push-pull output, which is what many modern IC uses nowadays.
You are best teacher... ❤️❤️
The video is really good. Thank u for ur time and efforts.
Can u pls explain : 1. the use of external pull up resistor ? 2. the reason for connecting Vcc of upper OP AMP to Vout of lower one ?
The pull-up resistor ensures the output of the comparator is indeed logic high when both comparator output is high.
If comparators are directly connected then it may happen that the overall output is less than the logic high value. And there might be ambiguity about the output.
Using the pull-up resistor that uncertainty can be eliminated.
For the second question, Vcc of the first op-amp is not connected to the output op-amp. Vcc is used for the pull-up resistor. And the pull-up resistor is connected to the output.
And similarly, the output of the second comparator is connected to the overall output.
I hope it will clear your doubt.
I have gathered lots of knowledge and learn so many things about comparator from this video, thanks 👍✌️❣️❣️🙏
Make more and more videos,,
At 6:16 , when Vin < Vref the output should be negative saturation voltage, dont you think? but you showed zero level in the output graph . Plz clarify my doubt, if i'm missing the point?
Here is a suggestion for a topic : Different ways of connection between electronics circuits like open collector , compatibility between different logic families , wired and connection etc.
Thanks
Awesome video! I have an analog signal which I need to convert to a digital high/low voltage. I now know I need to use a window comparator!
your explaination is so awesome.
Excellent explaination sir 👏
Can you explain what is latched comparator?
Great video. I enjoyed watching this video!👍
Woooooow sir that's a really nice session😊👍
Op amp act as an amplifier comes under non linear application
Great explanation. You made it too easy to understand. Thanks...
Consider you have a sensor which may be taking values of photoresistor and converting
them into voltage. Assume that sensor is recording the following values.
Max Value (Bright Light) ≈ 12 V (10% tolerance level)
Min Value (Dark) ≈ -2V (10% tolerance level)
Whenever the sensor reaches the value of ≈ 5V (10% tolerance level) a BlueLED must
be ON and when it drops from 5V it should be OFF.
The circuit is implemented using an amplifier which vaguely follows the idea of converting
analog input into digital by using it as a comparator.
Great video! Thanks for explaining the op amp comparator circuit .
Your videos are great, upload the videos for the whole portion covering comparator and waveform generators,,please
Yes, I am going to cover it.
For the window comparator please note that if you connect the negative rail to ground, you will not output zero volts but rather a small positive voltage when the input is outside the range of the window. Further, the load in that circuit is drawn very poorly. The outputs of the two comparators should be joined into a single node which feeds one terminal of the resistor while the other terminal should be grounded.
Thanks Vivek, i was wondering how to interprete the RL. U made a good video into a better one.
Thank you bro, this was very useful. Now I understand how to bulid an inverting comparator circuit.
why in output voltage , vo= 0 V when vin < vref , it should have been -vsat
It depends on type of comparator. Some comparators are single supply comparators. In such comparators the output will vary between Vaat and 0. In dual supply comparators the output varies between Vaat and - Vsat.
I hope it will clear your doubt.
@@ALLABOUTELECTRONICS Thank you very much
Kya explanation hai sir , tagraaaaa..,...
I thought op amp always try to make V- = V+. When ap-amp is used as comparator, it seems the rule is obeyed?
No, V- = V+, when the opamp is used with negative feedback ( in the linear region). When the opamp is used as a comparator then it is used in the open loop configuration. Therefore, it is not applicable.
@@ALLABOUTELECTRONICS Thank you so much for confirming this information.
Sorry, violated.
actually your graphs are wrong for inverting and non inverting comparator because in case of non inverting comparator when Vin < reference then Vout = -Vsaturation not 0 and similar for inverting comparator , by the way your explanation is awesome :)
It actually depends on the comparator supply voltages. There are some comparators, where positive supply voltage is Vcc and negative supply voltage is 0. In some comparator its -VCC.
For single supply comparators, the output will be zero, for the dual supply comparators, it will be -Vsat.
I hope it will clear your doubt.
Good explanation sir... Happy teacher day ❤
Thank you!!! I have a way better understanding now. 👍
Your great bro satellite communications gurinchi tutorial s cheyandi
IT IS VARY GOOD VIDEO,COULD YOU SEND TO ME HOW IT OPERA TO CONTROL THE THREE PHASE LOAD BALANCING
Why can't we use one AND gate at end having inputs as two comparator outputs
Please provide notes PDF along with lecture 🙏🙏🙏
Awesome explanation
Please make video's in hindi as they will be easy to understand and clear's concept.....
Hello, In my campus I am asked to do a project, I have to do a comparator circuit which detects whether the battery is below or higher a predetermined level. We have to Op-Amp comparator circuit, and also comparator circuit should be powered using the battery under test. Can you help on this, please?
Great video sir..
good information but i find it difficult to focus on whats being said because of the constant pauses as if hes asking questions
Amazing video sir 👍👍👌👌
For the window comparator, why is it that if one op-amp goes low then Vo goes low automatically, but needs both op-amps to be high for Vo to go high?
Because in the window comparator, the output of the two op-amps are connected together using the pull-up resistor. So, their outputs will act as a wired AND connection. That means if any one of the op-amp output is low, then overall output will become low and the output of the window comparator is high when both the outputs are high.
great explanation, thank you!
i have one question, i've been looking for a book that talks about this subject and some other subjects but couldn't find a good one yet.
can you suggest me some good books that explains microelectronics well?
For basic electronics : electronics principles by malvino and electronic devices and circuit theory by Robert boylstead are good books. You can refer these books.
It's a very helpful video thank u sir
Great video. Thanks for explain.
Really learn a lot from your channel. But you spoke about "open-loop configuration", could you please explain this concept/ circuit? Thanks
In minute 8:11 why does that configuration work as an AND? If one is at HIGH and the other at LOW why doesn't it blow up or something? Can someone explain me, please? thanks :)
Whether both the comparator outputs are been connected with Vcc, because your diagram seems to be like that only ?
I think you are talking about the window comparator. Yes, the outputs are connected to Vcc through one resistor. And because of that, the output behaves like wired AND gate.
Very well explained,thank you
Would you please clarify that from the circuit perspective, what would be the difference between an op-amp and a comparator? how are comparators faster than op-amps? Also, can you please explain the reason of adding the resistor?
op amp is optimized to provide accuracy and stability (both dc and dynamic) for a specified linear range of output values in precision closed-loop (feedback) circuits. It is achieved through internal compensation capacitor. But when the same op-amp is used in the open loop configuration as a comparator, then due to its internal compensation capacitor, its output cannot change very fast. On the other end, the comparators are meant to be operated in the open loop configuration. So, they do not require internal compensation capacitor. And because of that they are quite fast. I hope, it will clear your doubt.
Very nice explanation. 👍👍
Plz cover all 1st year topics..
Good explanation, but there’s something I don’t understand. How come op amps and comparators aren’t the same thing? Isn’t a comparator just an op amp without feedback?
Yes, op-amp can be used as comparators. But for that, the slew rate of the op-amp should be very fast.
So, ideally all the op-amps can be used as comparator. But not all the op-amp will work perfectly as comparator.
So, there are dedicated comparators ICs which will work as a comparator.
So, internally they are op-amp itself, but optimized for fast transition.
I hope it will clear your doubt.
ALL ABOUT ELECTRONICS thank you so much for the fast reply 👍🏻
thanks bhai hope u do more videos in the near future
At 4.00 what is open collecter configuration
You didn't explain about the clamp diodes we use to protect the op amp against damage to excessive input voltage?!
you made it so easy to understand
Sir, can you plz explain "why in window comparator, the output is low when any of the comparator output is low..?
I didn't understand it.. plz help sir
when any of the comparator output is low, the output of both comparators will be pull down to zero volt or low voltage. (Becuase it's wired and connection). That means the one terminal of the resistor (which is the output of the window comaprator ) will be at a low voltage. And the entire voltage will get dropped across the RL.
I hope it will clear your doubt.
@@ALLABOUTELECTRONICS sir can you explain the significance of that pull up resistor too? What really happens when the output of both comparators are high... How we determine the overall output..
Plz help sir
The pull-up resistor ensures the logic high at the output. If you see, every circuit or every IC has limited output current capacity. That means the maximum current it can deliver. If more current is drawn then the output voltage reduces.
And it might happen that the output voltage would become lower than the logic high value.
This pull-up resistor maintain the logic high value when the output of the comparator is high.
I hope it will clear your doubt.
Thank you for the detailed video
please explain the function of RL resistor in this circuit,and please make a video explaining pull up resistors.
I think you are talking about resistor RL in window comparator right?
It serves two purposes. First, when the output of the comparator is low, it will restrict the sink current of the comparator. Second, when the output of a comparator is high, it will provide the strong logic high.
I hope it will clear your doubt.
And yes, at some time I will make a video on external pull up resistor.
Sir why in the waveform of non inverting comparator you made the output signal zero .....will that not be equal to -Vsat ??
In books it's given -Vsat
Plzzzz help sir this is creating confusion in my concepts!
See, that depends on whether the comparator is a single supply or dual supply. In a single supply comparator, when the output of the comparator is high, then it will go towards the +Vsat, and when it is low, the output is zero.
In dual supply comparator, there will be +Vsat and -Vsat.
Here I am assuming its single supply comparator. In the book, it might be a dual supply comparator. (The biasing voltage to the comparator will be +Vcc and -Vcc)
I hope it will clear your doubt.
@@ALLABOUTELECTRONICS ohh okay .....thank you so VERY much sir ....now m fine with the concept 😄
Sir but how can I get 0& 5 volts only neither -ve nor any positive if I just want 0 or 5
Excellent sir!
At 9:04 iam confused that in window comparator why overall voltage is low if vin is less than either lower threshold voltage or upper threshold voltage
The output of the two compactors are connected. So, if any one of the output is low, then overall output will remain low.
The output of the window comparator high, when both comparators outputs are high. In this case, it will happen when Vin >VL and Vin < Vh.
So, basically, when the input voltage is within certain voltage band, then only the output of the comparator will become high.
I hope, it will clear your doubt.
So I request that can u show videos electronic topics of diploma (ECE) many of our frnds subscribers of ur channel
Please let me know here the topics which you want me to cover on the channel.
That's a lovely accent you have....New Jersey?
Be grateful that he’s not talking in Hindi you ingrate
I think you mixed up Beyond with Above..
What type of comparators are used in 555ic.
THANKS SIR FOR THIS VIDEO!!!!!!!!!!!!!!!!!!!!! IT IS A GREAT HELP TO ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! THANKS SIR!!!!!!!!!!!!!!!!!!!!!!!!
SIR PLEASE KEEP MAKING MORE VIDEOS... YOU ARE THE ONLY ONE I LOOK UP TO WHEN I NEED HELP!
Pls continue the remaining topics of comparator and wave form
I have already made videos on them. If you go through the op-amp playlist, you will get it.
Thank you for this video, can I compare 10v and 1.5 while rail sources v-=-3.3 and v+3.3? or I can only compare values less than or equal to the rail sources ?
when first one is low and second is high ,how output is low? when Vin >VH
when Vin > VH at that time the output of the first comparator will be low and the output of the second comparator will be high. So, overall output will be low.
When the inverting terminal voltage and non-inverting terminal voltage are same, how will it work then?
In ideal case, the output of the comparator will be zero. But in reality due to different bias currents at both inverting and non inverting terminal, the voltage at the two terminals will be slightly different. And because of that the output of the comparator will be either +Vsat or - Vsat.
Excellent it helped me a lot...
If you run the output of an op-amp through a diode, would that give you a comparator?
If you use opamp in the open loop configuration ( without any feedback) then that itself will act as an amplifier. If you use opamp at the output of the opamp ( without feedback) then it will rectify the output.
What happens when you have the same input?
Ideally, if both inputs are same then output should be zero. But practically that isn't the case. And even if you apply the same input to both input terminals, still you will see either +Vcc or -Vcc/ or 0V at the output (due to noise, offset voltage etc.)
Good video but the explanation is waaayyy too fast. Much better if he slowed down a bit after each sentences.
Sir, what about the case when output is in between Vsat and -Vsat (means if open loop gain*(Vin-Vref) donot reach Vsat)
If it does not go into the saturation then op-amp is operating in the linear region and it will work as linear amplifier. That is means vout = open loop gain* ( vin1 - Vin2)
But for that input should be very small. Typically in uV.
Slow down to about quarter of the speed and annunciate properly and this would have been perfect.
sir, in 6:12 , the output waveform should give a negative saturation for all input less than reference voltage , i am confused by the way u have given only one side positive saturations. should the low outputs ought to be below axis ??.can u help me out
Many comparators are single supply, where the negative supply pin is grounded. In that case, the output will vary between Vsat and 0.
When the comparator is biased with dual supply, (Positive and negative) then, in that case, the output will vary between +Vsat and - Vsat.
Here the comparator is biased with the single supply.
That's why the output is zero instead of negative Vsat.
I hope it will clear your doubt.
@@ALLABOUTELECTRONICS thank u sir
Excellent sir....
if the input to a comparator is a sine wave the output is a?
Sir,in window comparator ,if input is less than low threshold value ,then comp1(upper comparator) should give high according to ur circuit design ?..u should keep the input on non inverting terminal of upper comparator (comp1) and modify the circuit ,if I m not wrong 🤔
When Vin is less than VL, then the output of the first comparator is high, but the second comparator is low. (ideally, the output of the second comparator is zero).
So, it will pull down the overall output voltage to zero. (even though the output of 1st comparator is high)
It acts like a wired-AND gate. That means the output will be high when both comparator output is high.
I hope it will clear your doubt.
Thanku sir😊
nicely explained Sir
Is it possible for a quad op-amp to generate 3 window comparators. Specifically, if an RGB LED is used, how can I have ...
Input (In) Comp-A (R) Comp-B (G) Comp-C (B) Colour
In < 2.4V Low Low Low -
2.4V < In < 2.6V Hi Low Low R
2.6V < In < 2.8V Low Hi Low G
2.8V < In < 3.0C Low Low Hi B
In > 3.0 Low Low Low -
But how is it acting as an AND gate connection?
Well done
can you explain why one is high and other is low,overall output is zero in window comparator?
Let's take the case when Vin is less than VL. In this case, the first comparator output will be high and the second comparator output will be low. And if you observe the output of both comparators are tied to gather. (Wired AND connection). So, even if first comparator output is high, it will be pulled down to a low voltage by the second comparator. And in this way, overall output will be low.
I hope, it will clear your doubt.
how we can check stability of op-amp during frequency response
Stability of the op-amp can be checked using the gain margin and phase margin.
In simple terms, if I say, for the stability of the op-amp, when the gain of the op-amp reaches 1 (0 dB) at that frequency, phase should be less than -180 degree.
And when phase angle reaches the -180 degree, at that frequency, the product of open loop gain and feedback factor should be less than 1.
and how we can remove unstability
try to follow the above mentioned two criteria.
If you find that at your operating frequency the product of gain and feedback factor is greater than 1 and phase angle is less than 180 then change the feedback factor by adjusting the component values. Or if you use that circuit below the frequency where circuit becomes unstable, then you can avoid the instability.
Just Superb!!
Wht if both inputs are equal?
Can PLD and NLD be used as Comparator??
thank you very much. Namastê
Bro can u please explain about. What is the use of not gate in 1bit comparator please answer me bro
You are talking about the digital 1 bit comparator right?
The one which is discussed here is the analog comparator.
In 1 bit comparator there are three conditions.
Let's say A and B are the inputs.
1) A=B (It can be determined using XOR operation)
2) A>B (AB')
3) A
Bro write truth table for all three conditions obtain expression by k map technique..K map technique can be used to analyze any ic
Huge Thanks to U Dude
What is the meaning of open collector configuration at 3:56 ?
In the open-collector configuration, the output is taken through the collector of the internal transistor.To get the proper logic high and low, it is required to connect the external pull-up resistor at the collector. (resistor needs to be connected to Vcc at the collector).
@@ALLABOUTELECTRONICS okay thanks
Nice video
Joss video sir... Carry on
very well explained
Is this same as the digital comparator????
No, this is analog comparator.
can 741 be used for searching comparing
Yes, It can be used as a comparator. But the response time of the 741 will not be that fast. Still for lab testing and prototyping, it can be used.
fantastic video. but I am having a bit of trouble understanding through the accent...
Please use closed captions, incase you face any difficulty.
Reduce your teaching speed, you go like a superfast,
Fantastic