Lec-54: Fragmentation of IPv4 Datagram | Identification, Flags and Fragment Offset | Networks

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This video explains the concept of Fragmentation of IPv4 Datagram.
When a packet is received at the router, destination address is examined and MTU is determined. If size of the packet is bigger than the MTU, and the 'Do not Fragment (DF)' bit is set to 0 in header, then the packet is fragmented into parts and sent one by one.
0:00 - Introduction
0:27 - Fragmentation
0:59 - Identification bits
1:33 - Flag
3:21 - Fragment Offset
3:47 - Numerical
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#Fragmentation#IPV4#CN

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[@niteshkushwaha9493]

Following piece of information is missing in this lecture:
Router uses the following rule to choose the amount of data that will be transmitted in one fragment-
RULE::->
The amount of data sent in one fragment is chosen such that-
It is as large as possible but less than or equal to MTU.
It is a multiple of 8 so that pure decimal value can be obtained for the fragment offset field.

NOTE::->
It is not compulsory for the last fragment to contain the amount of data that is a multiple of 8.
This is because it does not have to decide the fragment offset value for any other fragment.

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[@mustaqahmed4066]

Here the pure data of each datagram should be divisible by 8. You didn't mention that and directly took the number 480 which is divisible. On my question total data was 600 and mtu was 250.Header data was 20. I wrote 230+20. But 230 is not divisible by 8. Hence my answer was wrong. This question carried 15 marks. 🥲

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It's your negligence humans can make mistakes you should not just watch videos but also read the theory once.

[@mustaqahmed4066]

@@harshapathak3103 But it's not like a small mistake which can be neglected and still the answer will be correct. It's a core part of the concept. It should be made clear while teaching. Moreover he is a teacher and a small mistake from the teacher, that too on a platform like TH-cam is a big deal. Most of the engineering students watch his videos as the primary knowledge source hence a small mistake can make the concept go wrong. Aur agar book mei se theory samajh aata toh videos kyu dekhte.😄These videos are far more optimised than a book. Again....no hard feelings for this man(varun singhla)..just stating my perspective.

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I don't understand why it should be divisible by 8?

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[@navdeepp5]

If link is with MTU 576Bytes instead of 500Bytes, then we should make each fragment packets of 572 bytes (not 576 bytes), because 572-20 = 552 bytes divides by 8 gives integer number. (576-20 = 556 bytes divides by 8 doesn't give integer number)

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