Pythagorean Trig Identity sin^4x cos^4x = 1 2 cos^2x

Quadratic Trigonometric Identities: • 16sin^5x + 2sinx = 12s...
Trigonometric Identities Playlist: • Trig Identity tan x si...
#trigonometric_identities_Test #trigonometric_identities #trigonometric_equations #anilkumarmath #globalmathinstitute
/ @mathematicstutor Learn From Anil Kumar:

[@TheMissAlira]

Omg I was thinking for an hour, similar problem, I factored right just could not understand that I should sub it like that. I don’t know how to thank you! 🤗

[@MathematicsTutor]

Thanks. More with Factoring: th-cam.com/video/fTQaJ0Tw2_8/w-d-xo.html

[@TheMissAlira]

Anil Kumar thank you

[@vangnguyenvan4333]

Thank you ❤️

[@marcosalcantaraoficial]

help me, i have one question here that say : the number of solutions of the equation sen^4=cos^4=1, satisying the condition 0

[@imforever5942]

Thanks mister!

[@Nikita-jr6de]

Thank-you sir

[@asmartfact7184]

Ggggggggggggggggggggggg😅

[@FUNNEXTLEVEL]

Nise solution

[@dragonice8387]

Hay quá ạ😀😀

[@desibrothers2801]

Sir I have a problem please solve it sin^3A-cos^3A=(sin^2A-cos^2A)(1-2sin^2A.cos^2A) sir please please solve it

[@rosthaexinor5051]

S'il-te-plaît calculer pour moi cosx exposant 4-sinx exposant4+sinx carré pour égale à 1

[@sh_sharma1336]

2sin^2-1

[@ardrajithendran9303]

Thank you

[@39.phamthithuthao27]

Thanks you

[@nikitaganevich7620]

thanks

[@NhuPhan-dp4rj]

tẹt vời

[@qhgaming8418]

sin^4x + cos^4x = -1/2cos^2(2x)

[@MathematicsTutor]

Thanks. Will take it up

[@sumitnamdev1218]

Thanks sir

[@salmasayed6334]

Thank u really much Mr Anil
ur way explaining it is perfect

[@sh_sharma1336]

This answer is wrong

[@tomgretzky]

[@veroxida]

Thank you sir