Timestamps for the different topics covered in the video: 0:00 Introduction 2:58 Input Impedance of Source Follower 4:05 Voltage Gain of Source Follower 7:07 Output Impedance of Source Follower 11:15 Application of Source Follower (As a Buffer) The link for the notes: www.allaboutelectronics.org/mosfet-source-follower-common-drain-amplifier/
Very fundamental. It’s perfect! An interesting move forward would be to discuss designs in the context of lectures you have already converted, so maybe you could go through a low frequency op amp design with these fundamentals + the differential amplifier videos. It’s kinda difficult to cover dynamics in this setting, but you could approach it in the context of avoiding Barkhausen criteria.
@@viditsharma3929 In Karnataka boards we have a combination of PCME(Physics Chemistry Maths and Electronics) for class 11 and 12th students and we learn about mosfets and a hell lot of derivations in class 11
Is there any chance that you would be able to explain to me the KVL at4:05? Why do you choose to introduce a variable for both Vi and Vgs, when Vi=Vgs? Also with that in mind, why are we not able to derive the gain equation from a single KCL at the node Vs (Vo)? I notice that my method yields the incorrect solution, but your method of the KCL with the KVL yields the correct solution. I was hoping you could explain why that is? Thanks so much!
Vin and Vgs are not same. Vin is between drain and ground, while Vgs is between drain and source. And source terminal is not at the ground potential. I hope, it will clear your doubt.
I guess you are refereeing to Vgs, while finding the output impedance. Because here, the source terminal is not at the ground potential. There is a source resistor (Rs) between source and ground. If you still have any doubt then let me know here.
The output impedance is the Thevenin's equivalent impedance looking from the output side of the small signal circuit. So, here the procedure is very similar to the procedure which is followed for finding the Thevenin's equivalent impedance of any circuit. Since the circuit contains dependent source, the test voltage is applied at the output side. I hope, it will clear your doubt.
For explaining the application of source follower, the value of 1/gm was assumed as 50 ohm. (Coincidently, in this case, it is the same as RL). I hope, it will clear your doubt.
Timestamps for the different topics covered in the video:
0:00 Introduction
2:58 Input Impedance of Source Follower
4:05 Voltage Gain of Source Follower
7:07 Output Impedance of Source Follower
11:15 Application of Source Follower (As a Buffer)
The link for the notes: www.allaboutelectronics.org/mosfet-source-follower-common-drain-amplifier/
Very fundamental. It’s perfect! An interesting move forward would be to discuss designs in the context of lectures you have already converted, so maybe you could go through a low frequency op amp design with these fundamentals + the differential amplifier videos. It’s kinda difficult to cover dynamics in this setting, but you could approach it in the context of avoiding Barkhausen criteria.
Thank you bro these videos help me a lot in my board exam preparations
what?
@@viditsharma3929 Yeah, what ?
@@wanderingscience8670 boards? which boards examination is asking you to prepare for mosfets ???
@@viditsharma3929 In Karnataka boards we have a combination of PCME(Physics Chemistry Maths and Electronics) for class 11 and 12th students and we learn about mosfets and a hell lot of derivations in class 11
@@wanderingscience8670 great
Very nicely explained 👌🏻👌🏻👍🏻
Just Brilliant.
How to know if the output voltage for common drain amplifier distorted?
Thank you very much for your videos!!
Is there any chance that you would be able to explain to me the KVL at4:05? Why do you choose to introduce a variable for both Vi and Vgs, when Vi=Vgs? Also with that in mind, why are we not able to derive the gain equation from a single KCL at the node Vs (Vo)? I notice that my method yields the incorrect solution, but your method of the KCL with the KVL yields the correct solution. I was hoping you could explain why that is? Thanks so much!
Vin and Vgs are not same. Vin is between drain and ground, while Vgs is between drain and source. And source terminal is not at the ground potential. I hope, it will clear your doubt.
need -20VDC output from multistage source follower. Input are +20 and -40V correct?
why vgs not equal to zero in this case like in common source amplifier
I guess you are refereeing to Vgs, while finding the output impedance. Because here, the source terminal is not at the ground potential. There is a source resistor (Rs) between source and ground. If you still have any doubt then let me know here.
Very nice Sir
Mashallah..keep up the good work.. Electronics is love..
Why Vx introduce in output impedance will you explain
The output impedance is the Thevenin's equivalent impedance looking from the output side of the small signal circuit. So, here the procedure is very similar to the procedure which is followed for finding the Thevenin's equivalent impedance of any circuit. Since the circuit contains dependent source, the test voltage is applied at the output side. I hope, it will clear your doubt.
Absolutely superb 👍
How is gm=1/Rl...??
at 11:40
Thanks in advance sir
For explaining the application of source follower, the value of 1/gm was assumed as 50 ohm. (Coincidently, in this case, it is the same as RL). I hope, it will clear your doubt.
THANX THANX THANX .......
Bro...Which pen&board tool u r using for the lecture???
How is gm=1/Rl...??
Would you please mention the timestamp where you are referring to in the video ?
@@ALLABOUTELECTRONICS 11:45
❤❤❤❤
Why do you end sentences like a robot?
My electronic Marathi channel
Pattewar vithal
Gate current should be zero . So ur calculation of voltage gain in common drain amplifier is wrong