i swear to God thats the same with me, even for physics and chemistry.... and especially math now, cuz these online lectures really be crappy as hell so at one point i just ditched the lectures and started watching this guy's videos instead, and i ended up with an A+ in Calc 1. this dude's great!
Same. My math grade went up from C to B because of these videos, and I was procrastinating! Imagine if I didn’t procrastinate, I’d probably have an A. These vids are great
I literally saw your first example and explanation and understood it right away while my trash math teacher spent 3 days in class trying it explain this and no one understood I saw your video and got it literally within the first 2 minutes. Why cant teachers teach in effective ways that are easy instead of the crappy traditional methods. Thank You!
14:36 there is easier way, if SUM(n=m) then (ar^m)/1-r. So in our case our m = 1, a = 5, r = 8/25. If you follow the equation you'll get same answer as in the video 40/17 .
@@adityabhardwaj3495 It might have been grade 12, I just realized I can't remember exactly who my teachers were for those classes, or if it was the same person for both
Thank you so much.After watching the lecture video on finding the sum of infinite geometric series, i have been able to complete my assignment.You surely cannot go wrong with this lecturer.
I want to express my sincere gratitude for your exceptional videos on organic chemistry. I struggled with mathematics, but thanks to your expert guidance, I was able to achieve an A in both Calculus 1 and Calculus 2. Your teaching has made a significant difference in my academic performance. Thank you for being the best! If you need any further adjustments, feel free to let me know!
I looked at my calc notes today for a test and nothing made sense after a month. I don't ever remember my teacher explaining it like this but I finally understand something!!
00:02 Finding the sum of an infinite geometric series using a formula 02:20 Finding the sum of an infinite geometric series using common ratio 04:41 Explaining calculation of the sum of an Infinite Geometric Series 07:04 Finding the sum of an Infinite Geometric Series 09:32 Sum of series with exponential terms 12:17 Finding the first term and common ratio of an infinite geometric series 14:45 Summarizing the method to find the sum of an Infinite Geometric Series 17:23 Determining the sum of the infinite geometric series.
To all further maths students: do you know the feeling when you've already studied a subject like this and then forgetting what you've learned years after the years??? Yeah, that's how I feel rn :(
Pro tip about the (2^3n)*(5^1-2n). When you get to the point where there is sigma of "5*(8/25)^n" you actually CAN use formulas. You can tranform it into "5*(8/25)*(8/25)^(n-1)", so that it fits formula with sigma starting from 1.
We also have the same question. and if you factorised the numerator on the last question into 2^n(2^2+1)/5^n this simplified to 5(2/5)^n and we obtained a different answer which was 10/3
Thank you so much for all of the math tutorials you've made, they've helped so much. Do you think you can make your voice a little bit louder though? It gets hard to hear your explanations any time there's even a little bit of background noise.
Professor Organic Chemistry Tutor, thank you for explaining The Sum of an Infinite Geometric Series in Calculus Two. Geometric Series are very important in Advanced Mathematics/Engineering. Geometric Series is also used in Signal and Systems Theory and Digital Signal Processing. This is an error free video/lecture on TH-cam TV with the Organic Chemistry Tutor.
thank you so much. I do have a doubt though. in the last problem, why did you split the fraction as 4/5 + 2/5?? why couldn't we solve without splitting the fraction? like then , first term would then be 6/5 and common ratio would be 2/3 and the total sum then would be 18/5. can you please clarify?
We also have the same question. and if you factorised the numerator on the last question into 2^n(2^2+1)/5^n this simplified to 5(2/5)^n and we obtained a different answer which was 10/3
Sir I have a question why did you multiply by 2 in 1:40? Edit: Now I know why. Im just gonna leave this comment here to remind people that some people are slower than others and thats okay.
You are literally saving me, but can you please please do one where r is bigger than one? For example idk how to solve; sigma( 1 to infiity) of 1^n/(n^6) -_-' :(
I know you're progabaly not concerned with this answer anymore. But that's a p series not a geometric series. the P value (which is 6) is > 1 so it converges by p series test. According to the online calculator wolfram alpha it converges to 1.0173..... wolfram alpha used comparison test.
hello folks, im really confused how he get the " 2 - 1" in here 1:55 , im just really confused , i try it too and get 0.5 then times it on 2 and got -1 , and i didnt know where he get the 2 from
Btw TH-cam keep adding adds telling students that they can get better education by leaving TH-cam education channels that can destroy your work .. just saying 😐
Yeah but anyone who follows these, knows they are great. I got like almost 170 videos of his down, and im going to finish this entire calculus playlist of 226. People are here for a reason.
Thank you so much but d part not yet clear for me is when we multiple both side with the denominator does that automatically rule out the denominator itself??
question : how do you know that the series has the same patter all the way to infinity by only testing a couple of those numbers Im referring to r , thanks you for sharing
15:30 - Didn't you say earlier in this video that the summand's power should be (n-1) if n starts from 1, and should be n if n starts from 0? Why the power = n here while n starts from 1? That is, the a₀ term is missing.
I need your help with this problem : The second term of a sequence is 17 and the sum of the first six terms is 147 : Determine the first three terms and the nth term. .. Please help me. ...if you have a video referring to this problem may you please give me the link.
Hopefully you're doing OK but just in case, I believe he multiplied by 2 to make the 1-1/2 easier to visually work with by making all the numbers whole (i.e 1-1/2 -> 2-1). So instead of having a fraction in the denominator, he has all whole numbers. Technically it was easy to solve without doing so, but I think it looks cleaner that way when explaining
Sequences - Free Formula Sheet: bit.ly/4eau2KQ
Sequences and Series: www.video-tutor.net/sequences.html
God bless
n
seriously i just come to this guy for everything i’m learning
i swear to God thats the same with me, even for physics and chemistry.... and especially math now, cuz these online lectures really be crappy as hell so at one point i just ditched the lectures and started watching this guy's videos instead, and i ended up with an A+ in Calc 1. this dude's great!
Ikr
Same. This is my go to for anything science/math related.
Same. My math grade went up from C to B because of these videos, and I was procrastinating! Imagine if I didn’t procrastinate, I’d probably have an A. These vids are great
Same here, best math teacher ever.
I'm an engineering student and this guy has officially carried me through my first year.
you guys take this at university? im in 11th grade lmao
@@dazllc Most uni's re-teach to make sure students are on the same level. I wish I didnt have to fork out 500CAD to learn this stuff xD. You're lucky
@@00_002 I’m in my final highschool year. This guy is gold
@@dazllc you're gonna do it again
@@dazllc same bruh
I literally saw your first example and explanation and understood it right away while my trash math teacher spent 3 days in class trying it explain this and no one understood I saw your video and got it literally within the first 2 minutes. Why cant teachers teach in effective ways that are easy instead of the crappy traditional methods. Thank You!
15:39 how did he get e value
@@mullins69 Thats the universal value of *e* .Like pi has the value 3.1415 , e has the value 2.718
Atleast your teacher described it but in my case only homework.
same bruv.
I know right, my dumbass teacher made it a million times more complicated than it had to be
2 minutes in and you've taught me more than my calc prof and the textbook. I've read this chapter like 5 times and could not understand it. Thank you.
I watched 2 minutes of this video and IMMEDIATELY understood something I've been trying to get for 2 weeks! Thank you so much!!!!
You can't go wrong with this lecture. My request is to see your face sir. Because of you I'm a fully baked mathematician.
for real! I always watch his videos after my school and tuitions just to properly grasp the topic
You're baked?
Omfg you're baked?
@@surelock3221 i am
God bless
I would never graduate if it wasn't OCT's help! This man is single handed forming the future of the world! Thank you Sir!
14:36 there is easier way, if SUM(n=m) then (ar^m)/1-r. So in our case our m = 1, a = 5, r = 8/25. If you follow the equation you'll get same answer as in the video 40/17 .
How did people understand this before Mar 28, 2018
I wonder
My grade 11 teacher did a pretty good job teaching this unit actually
@@surelock3221 bro, they taught you this topic in the 11th grade? here we just learn continuity in the 11th grade.
@@adityabhardwaj3495 It might have been grade 12, I just realized I can't remember exactly who my teachers were for those classes, or if it was the same person for both
@@adityabhardwaj3495 bruh Im learning this for my 9th-grade pre calc final rn smh.
Looking forward to graduating IT with the help of this guy ,such an inspiration !
Thank you so much.After watching the lecture video on finding the sum of infinite geometric series, i have been able to complete my assignment.You surely cannot go wrong with this lecturer.
I'm a high school math teacher, and this guy is ' my go to'. Thank you
1. In the a/(1-r) formula, a is just a sub 1.
2. The abs(r) < 1 is just a check to see if you can use the a/(1-r) formula.
A whole day of not understanding my Calculus professor and textbook, and this video taught me all of it within 15 mins! Many thanks!
Thank you for helping so many college students throughout the years. I am so grateful for this channel's existence and I owe my college degree to you.
Sir u help me in my need! God bless you!
I want to express my sincere gratitude for your exceptional videos on organic chemistry. I struggled with mathematics, but thanks to your expert guidance, I was able to achieve an A in both Calculus 1 and Calculus 2. Your teaching has made a significant difference in my academic performance. Thank you for being the best!
If you need any further adjustments, feel free to let me know!
I looked at my calc notes today for a test and nothing made sense after a month. I don't ever remember my teacher explaining it like this but I finally understand something!!
I don't think you'll ever be able to comprehend just how many lives you're constantly positively impacting
u need a noble price for this u are like a life saver and also a hero
00:02 Finding the sum of an infinite geometric series using a formula
02:20 Finding the sum of an infinite geometric series using common ratio
04:41 Explaining calculation of the sum of an Infinite Geometric Series
07:04 Finding the sum of an Infinite Geometric Series
09:32 Sum of series with exponential terms
12:17 Finding the first term and common ratio of an infinite geometric series
14:45 Summarizing the method to find the sum of an Infinite Geometric Series
17:23 Determining the sum of the infinite geometric series.
To all further maths students: do you know the feeling when you've already studied a subject like this and then forgetting what you've learned years after the years???
Yeah, that's how I feel rn :(
But it's like riding a bike. We can get back on easier second time.
@@justsam0511 maybe not quite like a bike but it's definitely easier to pick back up the next time around
@@justsam0511 Except the bike breaks apart if you switch a sign accidentally.
nope just nope its suffering and suffering only@@justsam0511
dude is literally my life saver. I have a math final on Tuesday on this lesson, this will rly help me
I watched this and now I'm a mathematician by genetics !
i am first year civil E student and this guy really make me HAPPY love you big man
Thank you sir for teaching my lesson.
Pro tip about the (2^3n)*(5^1-2n).
When you get to the point where there is sigma of "5*(8/25)^n" you actually CAN use formulas. You can tranform it into "5*(8/25)*(8/25)^(n-1)", so that it fits formula with sigma starting from 1.
How do you do that, please send me via e-mail.My e-mail is smposula300@gmail.com.Please m writing this Monday.
This will NOT give you the same answer which is 40/17. This instead gives you 200/17. WRONG ANSWER
Thanks a lot i really appreciate those lectures and also the lectures of thermodynamics
i always go to this guy whenever there's a lesson I can't understand from my teacher..
Thank you! Very straightforward video.
akutami sensei makes me learn this lesson
This helped me since i got confused at my teachers explanation
This guy is way more useful then my teacher
my worst fear is that one day I will have to learn something that you havent covered on the channel :(
Exactly what I was looking for. I can make the assumption that if r>1 the series must be diverging.
your students must be so lucky to have you
Best guy ever
I understood everything in the first 3 minutes, this is a very helpful video
This makes so much sense now! Thank you!
can we cancel out mixed numbers?
Better than my instructor and sloppy notes, Thanks!
We also have the same question. and if you factorised the numerator on the last question into 2^n(2^2+1)/5^n this simplified to 5(2/5)^n and we obtained a different answer which was 10/3
Why did you multiply by 2 at 1:48
Your content are amaizing
your a legend bro, love you very much
Thank you so much, I finally understand what I'm suppose to do.
Thank you so much for all of the math tutorials you've made, they've helped so much.
Do you think you can make your voice a little bit louder though? It gets hard to hear your explanations any time there's even a little bit of background noise.
Thank you sir, you are a life saver.
THANK YOU SO MUCH! ❤️
This guy is the best.
Professor Organic Chemistry Tutor, thank you for explaining The Sum of an Infinite Geometric Series in Calculus Two. Geometric Series are very important in Advanced Mathematics/Engineering. Geometric Series is also used in Signal and Systems Theory and Digital Signal Processing. This is an error free video/lecture on TH-cam TV with the Organic Chemistry Tutor.
May God bless you i have no word for you
thank you so much. I do have a doubt though. in the last problem, why did you split the fraction as 4/5 + 2/5?? why couldn't we solve without splitting the fraction? like then , first term would then be 6/5 and common ratio would be 2/3 and the total sum then would be 18/5. can you please clarify?
We also have the same question. and if you factorised the numerator on the last question into 2^n(2^2+1)/5^n this simplified to 5(2/5)^n and we obtained a different answer which was 10/3
I tried without splitting and it wasn't forming a geometric series as the r differed in value when I tried a2/a1 and a3/a2
@@jimhalpert9803 YES. This was my question. Thank you, Jim, for explaining!
Thank you very much for this great video🤩
3 m subscribers!!!!! I'm excited!!!
Sir I have a question why did you multiply by 2 in 1:40?
Edit: Now I know why. Im just gonna leave this comment here to remind people that some people are slower than others and thats okay.
Wait what's the reason tho?
@@aki8683
because of the 1/2 the denominator is 2
@@spicy_tomato641 Ohh okay thanksss
@@spicy_tomato641 does that automatically rule out the denominator??
Lets be realistic here. Its been 3 years. I already forgot. AHAHAHAHAHAHA@@queenosas7774
The Lord has provided us once again
You might’ve just saved me from failing my exam tomorrow. Fingers crossed.
thank you very much ,this helped out a lot
this video has taught me more in 3 minutes then my entire summer school math lesson
your methods are good
for one of the problems how do you know the value of e??
I’ve been trying to get this for days now and only now understood it.
I’m going to keep this one stored away for future reference.
The gift that keeps on giving
I'm 13 years old (almost 14 though), I'm portuguese and his explanation is so good, that I understood it, even though it's in english.
happy 14th birthday, i'm assuming you've turned by now
@@niccoloripamonti6501 Yes I have haha, cheers man!
Please can you do a video
About expansion of e^x
To find sum of geometric series using e^x
@ 3:55 (second # problem). 3*3*3 is 27. YOU put 9. Please check for the right ans. Let me know
SO the answer should be 27.
My bad I see you are multiplying not squaring. OMG sorry
I will give you a shout out📢📢 when I graduate for sure 👨🏽🎓
You are literally saving me, but can you please please do one where r is bigger than one? For example idk how to solve; sigma( 1 to infiity) of 1^n/(n^6) -_-' :(
I know you're progabaly not concerned with this answer anymore. But that's a p series not a geometric series. the P value (which is 6) is > 1 so it converges by p series test. According to the online calculator wolfram alpha it converges to 1.0173..... wolfram alpha used comparison test.
@@WittyComm3nter Ok.
I like these series because you can see what it will converge to if it does
love you mate
Speechless sir....
so in the first example why did you multiply both 8 and 1-1/2 by 2
hello folks, im really confused how he get the " 2 - 1" in here 1:55 , im just really confused , i try it too and get 0.5 then times it on 2 and got -1 , and i didnt know where he get the 2 from
Can you please explain how you come to the exponential number at the end?
Btw TH-cam keep adding adds telling students that they can get better education by leaving TH-cam education channels that can destroy your work .. just saying 😐
Yeah but anyone who follows these, knows they are great. I got like almost 170 videos of his down, and im going to finish this entire calculus playlist of 226.
People are here for a reason.
7:51 please is it not supposed to be 24/5
Please someone should explain
sir your lectures are awesome
but can you make it a bit louder [it is less audible]
This is a really good video!!!!!!!!!!!!!!!!
You are a legend
god bless this man
Thank you so much but d part not yet clear for me is when we multiple both side with the denominator does that automatically rule out the denominator itself??
Love this guy.
Your a genius 🤧
Thank you sooooooooo much ❤
question : how do you know that the series has the same patter all the way to infinity by only testing a couple of those numbers Im referring to r , thanks you for sharing
I just watched this and my exam is within an hour.
Hey can you make a playlist on linear algebra.. Space and base staff
15:27 why is 9 outside? Why isn't in the numerator??
And how'd ya get the value of e
15:30 - Didn't you say earlier in this video that the summand's power should be (n-1) if n starts from 1, and should be n if n starts from 0? Why the power = n here while n starts from 1? That is, the a₀ term is missing.
In the first example, why do you square the 8/(1-1/2)?
I need your help with this problem : The second term of a sequence is 17 and the sum of the first six terms is 147
: Determine the first three terms and the nth term. ..
Please help me. ...if you have a video referring to this problem may you please give me the link.
at 15:45 seconds. how was the value of e calculated
help please
Its a constant duh
Absolute legend
What if a1 would be a fraction along with r being a fraction? How would that work?
Well sir I might just actually pass this test
Please pray for me for my calculus exams tomorrow 😭
How’d you do
Thankyou! Very understandable! 💖
I'm having mental breakdown while watching, why did you multiply it by two😭😭😭 on the first ex.
Hopefully you're doing OK but just in case, I believe he multiplied by 2 to make the 1-1/2 easier to visually work with by making all the numbers whole (i.e 1-1/2 -> 2-1). So instead of having a fraction in the denominator, he has all whole numbers. Technically it was easy to solve without doing so, but I think it looks cleaner that way when explaining
in the first one, how come the sum is less than the initial value if there is no negative numbers in the series?