Dear sir, I have a conceptual query. In a conservative force field, the change in potential energy is defined by the negative of the work done. In our fundamental physics, we have seen that both gravitational and electrostatic fields are conservative. Then, why do we incorporate the gravitational work done as gravitational potential energy in the internal energy term, while electrical work done remains in the work done by the system?
ty very much sir
Very good video.enjoying thermodynamics
if R=0.287 and T2 = 293.15k and T1= 673.15
k
then work done is equal to - 109.06 kj/kg but is - 96.6 given
Next lectures upload karain plz
i didn't get the work done in the problem sum
Brother it depends on the value of 'R' you have taken.
@@saivenkateshmalakala7236 if R=0.287 and T2 = 293.15k and T1= 673.15
k
then work done is equal to - 109.06 kj/kg but is - 96.6 given
worth
Dear sir, I have a conceptual query.
In a conservative force field, the change in potential energy is defined by the negative of the work done.
In our fundamental physics, we have seen that both gravitational and electrostatic fields are conservative.
Then, why do we incorporate the gravitational work done as gravitational potential energy in the internal energy term, while electrical work done remains in the work done by the system?