its a great video...its surprising that you were able to explain things without any animations... wonder why so less views and likes.... anyway.. thanks a lot
Hamzeh Feddah Being adjacent to a pi bond is important to the hybridization of that nitrogen. Since the lone pair prefers to be part of the pi system, and to do so it must occupy a p orbital, the nitrogen is sp^2 hybridized. If you draw a resonance form in which that lone pair is "pushed" into the pi system, I think you'll see what I mean. :-)
its a great video...its surprising that you were able to explain things without any animations... wonder why so less views and likes.... anyway.. thanks a lot
The Nitrogen @ 3:20 is not sp2 hybridized. It has a lone pair with 3 bonds, that makes it SP3 hybridized doesn't it?
Hamzeh Feddah Being adjacent to a pi bond is important to the hybridization of that nitrogen. Since the lone pair prefers to be part of the pi system, and to do so it must occupy a p orbital, the nitrogen is sp^2 hybridized. If you draw a resonance form in which that lone pair is "pushed" into the pi system, I think you'll see what I mean. :-)
At 3.20 you told N is sp^2 hybrid but that lone pait is not a part of resonance..
in benzanmine the line of symmetry cuts the nitrogen in two parts how can this be line of symmetry
Very useful. Please keep it up
How come the carbon at 5:57 do not have hydrogen at the back?
It does-I didn't draw it because it is "eclipsed" by the forward-pointing -NH2 group.
What is the name of the rule which tells that the top left corner structure (the complex one) is achiral?
2 of the same substitutes so is superimposable. All achiral molecules are superimposable to mirror images
nice video
You are too fast
I didn't able to get it...