I'm getting lost on the derivations. Particularly differentiating the sin2PifL. Do I need to explore some Maths or did I miss something in an earlier video? Many thanks, I'm thoroughly enjoying having my brain stretched.
First thing, have you downloaded the text? I go into much greater detail there than is possible in a modest video. Second, the thing to remember about differentiating a sine is that you're coming up with the slope ("steepness"), so where ever the sine has peaked, it's momentarily flat, and thus the derivative is zero. Meanwhile, it is steepest at the zero-crossings, and thus the derivative is at maximum. Just plot those four points (positive zero-cross, positive peak, negative zero-cross, negative peak), and you'll see how the derivative is a cosine (sine shifted by 90 degrees). If the issue involves "where did that 2 pi stuff come from in the derivative", that's going to require a little math review. The key is that dy/dx can be written as dy/du * du/dx, and you need to substitute in the proper value of u (that's the "2 pi" business).
@@ElectronicswithProfessorFiore yes, I’m enjoying your texts and have downloaded them all. I’m jumping between transistor work and the bits that I’ve forgotten, or can’t quite grasp. I came across the 2Pi stuff in your diode questions in the text and have returned to your AC videos to try and backfill some gaps. Thanks for taking the time to respond, it is much appreciated.
Thank you for another great lesson.
Is there a solution manual for your books ?
The answers to the odd-numbered exercises can be found in the Appendix of each textbook.
I'm getting lost on the derivations. Particularly differentiating the sin2PifL. Do I need to explore some Maths or did I miss something in an earlier video? Many thanks, I'm thoroughly enjoying having my brain stretched.
First thing, have you downloaded the text? I go into much greater detail there than is possible in a modest video. Second, the thing to remember about differentiating a sine is that you're coming up with the slope ("steepness"), so where ever the sine has peaked, it's momentarily flat, and thus the derivative is zero. Meanwhile, it is steepest at the zero-crossings, and thus the derivative is at maximum. Just plot those four points (positive zero-cross, positive peak, negative zero-cross, negative peak), and you'll see how the derivative is a cosine (sine shifted by 90 degrees). If the issue involves "where did that 2 pi stuff come from in the derivative", that's going to require a little math review. The key is that dy/dx can be written as dy/du * du/dx, and you need to substitute in the proper value of u (that's the "2 pi" business).
@@ElectronicswithProfessorFiore yes, I’m enjoying your texts and have downloaded them all. I’m jumping between transistor work and the bits that I’ve forgotten, or can’t quite grasp. I came across the 2Pi stuff in your diode questions in the text and have returned to your AC videos to try and backfill some gaps. Thanks for taking the time to respond, it is much appreciated.
@@ElectronicswithProfessorFiore I have it now, thanks. It was the dy/du * du/dx that was missing. I've reviewed that now.