sir we can just directly add the resistances and divide it by voltage R=V/I [10+20+30]/11=10/I 60/11=10/I I=[10x11]/60 I=110/60 I=11/6 It is really simple sir! thank you for posting this video😍🤩
Sir last question alone doubtful sir. If we take the equivalent resistance for the series, then why don't we take it for parallel as well? If we take equivalent resistance in parallel connection: Rp=R/3 I=V/R/3= 3V/R P=I^2R= (3V/R)^2 × R/3 = 9V^2/R^2 × R/3 = 3V^2/R^2 × R Can I take equivalent resistance for parallel as well? Can you say if it's a correct way or not?
Sir in 3rd question they have netion3d same length and diameter but you have done for only Same length. The answer must be Sam current only know sir ????
Sir really thanks a lot sir✨ sir neenga ennoda periya motivation sir🔥 ungaloda way of teaching is bettee tha school sir🎉Ad²🎉 Proud to be a assault batch🔥
Dont worry ..... Practice again and again and understand the question and concept Write the given value for the sum And do the sums with the suitable formula
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sir we can just directly add the resistances and divide it by voltage
R=V/I
[10+20+30]/11=10/I
60/11=10/I
I=[10x11]/60
I=110/60
I=11/6
It is really simple sir! thank you for posting this video😍🤩
reply sir
I too thought of this😅 finding individual current and adding them once again instead of this some time drain our time
47:20 Super ! Trick
hi sir i got full in my phy school exam tq somuch sir
energy = pt period
E= P.T[FORMULA- ENERGY= POWER. TIME]
SIR PLEASE TAKE CIRCLES AND TRIANGLES MARATHON AND NCERT SESSION
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48:35 This pen spin........Your the GOAT for 10th graders , Thankyou sir, your motivation keeps me going🥰🥰🥰😇😇😀😀
Dai super comment da
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Me bro
Bro me too 😢
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i used to feel physics is difficult because of word problems but now its easy thank you sir
Sir last question alone doubtful sir.
If we take the equivalent resistance for the series, then why don't we take it for parallel as well?
If we take equivalent resistance in parallel connection:
Rp=R/3
I=V/R/3= 3V/R
P=I^2R= (3V/R)^2 × R/3
= 9V^2/R^2 × R/3
= 3V^2/R^2 × R
Can I take equivalent resistance for parallel as well? Can you say if it's a correct way or not?
Same doubt for me too
Moreover while calculating power for series also
We should take resistance as 3R
So P for series=
(V/3R)²×3R
= V²/3R
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sir a small request could you please give questions from all the subject and extend this to next month also ? adad
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Sir in 3rd question they have netion3d same length and diameter but you have done for only Same length. The answer must be Sam current only know sir ????
Thank u so much sir ❤
Sir really thanks a lot sir✨ sir neenga ennoda periya motivation sir🔥 ungaloda way of teaching is bettee tha school sir🎉Ad²🎉 Proud to be a assault batch🔥
I didn't get everything correct.... But I will try to make it correct... Btw Tq so much sir...
Dont worry .....
Practice again and again and understand the question and concept
Write the given value for the sum
And do the sums with the suitable formula
@@anithan8370 ok and Thank you so much
This session is very useful sir..... This video helped me a lot to improve my numerical skills.... Thank you sir....
My aim is to solve minimum 500 questions in each physics chapter sir
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