It was a tricky set. In my opinion, if you can identify the main idea of the set and use simple approach to solve it, then it is never difficult to crack. Happy learning!
If you keep practicing and focus on learning simple approaches, every set will be easy to crack. Try to memoriae the approach used once you solve the sets. It will help you build the right technique. Happy Learning!
Since in 2012, there are 5 contracts, it can be from a combination of w, x, and z only, where each one of them can have maximum value of 2. So to get 5 contracts, we need to have 2, 2, 1 contracts. That we have calculated in the video later. y have contracts in 2010 and 2019 only.
Since in the statement it is given that z has at least one contract every year, we need to look at the contracts. If we add any two contracts, the sum must be equal to 10 or greater than 10. So if we involve 1-year contract, then we will not get sum 10. From the remaining contracts we have values 3, 4, 7. We cannot take 3, 4 because the sum will be 7. So we have to take (3, 7) or (4, 7). When we take (3, 7), then z will have contracts every year without any overlap and when we take (4, 7), then z will have contract every year but in one year it will be overlapping.
Late se samajh aaya par clearly samajh gaya.
Thanks sir😅
It was a good set. Happy learning!
this was really hard...one
It was a tricky set. In my opinion, if you can identify the main idea of the set and use simple approach to solve it, then it is never difficult to crack. Happy learning!
Sir Interstellar was simpler..
If you keep practicing and focus on learning simple approaches, every set will be easy to crack.
Try to memoriae the approach used once you solve the sets. It will help you build the right technique.
Happy Learning!
@@ExamNestThank you so much sir I'm totally following your playlist, really helpful ❤
Without solving set got 4 correct and 2 wrong😂
Happy Learning!!
8:28 me z,w,x =2 ???
Since in 2012, there are 5 contracts, it can be from a combination of w, x, and z only, where each one of them can have maximum value of 2. So to get 5 contracts, we need to have 2, 2, 1 contracts. That we have calculated in the video later. y have contracts in 2010 and 2019 only.
sir , z ka atleast 1 contract every year wala part is not clear ......
Since in the statement it is given that z has at least one contract every year, we need to look at the contracts. If we add any two contracts, the sum must be equal to 10 or greater than 10. So if we involve 1-year contract, then we will not get sum 10. From the remaining contracts we have values 3, 4, 7. We cannot take 3, 4 because the sum will be 7. So we have to take (3, 7) or (4, 7). When we take (3, 7), then z will have contracts every year without any overlap and when we take (4, 7), then z will have contract every year but in one year it will be overlapping.
@@ExamNest .thank you so much sir .........😀