In question 1, at 2:30 what if both the shoes (35th & 36th) are of same leg (left or right) ? To make a pair, it should be 1 left and 1 right. So, I think it should be (d)45
Sir....in 9 question...for 3 Rd Statement u took 5 and 3....they both are prime numbers...they were asked to take one composite and one prime number ...so once check it sir
Q.1. Now, if he picks any two shoes, they are certainly going to be red. However, we also need to ensure that the red shoes picked by him make a pair, i.e. there should be one red shoe for left foot and one red shoe for right foot. For this to happen we need to pick 11 red shoes. So, maximum number of attempts to get a red pair of shoes = 34 + 11 = 45
In Q.21 The smallest value of m would be 127. Let's just say we get all black, blue, green, yellow, red balls. The total will be 126, when we draw another (ball no.127) it comes out white. Hence smallest value of m is 127, not 167. Hence only statement 1 is correct.
Thank you for the explanations sir. Had a doubt regarding Q 38 at 50:22 . Using both statements we can get the answer 312 which is divisible by 6. But 132 is also divisible by 6 so how can we answer the question as there are two possibilities 312 and 132 so I think both statements are insufficient to answer the question. Shouldn't the answer be (d)?
I feel the answer for the shoes question will be 45. What if he keeps on picking up one shoe of each pair of red shoes after 34 attempts. That is if he picks left shoe of 1st pair of red shoes in his 35th attempt and then left shoe of 2nd pair in his 36th attempt and so on. This leads him to pick all the left shoes by 44th attempt. Then on the 45th attempt he will pick any right shoe of any pair which will eventually make him have a pair of red shoes.
Hlo sir thank you very much for your explanation it was very helpful sir question no.9 pc can be odd was wrong I think you have taken 5prime number for multiplication
Answer for the 1st question is option (d) 45. Shoes 35 to 44 could be red shoe of either left or right leg. So 45th pick will give him one complete pair of red shoes th-cam.com/users/shorts92sWCD99eZ4
First question: he cant use same side shoes to wear He have worst case of getting all same side shoes Thus 34 + 10 44 attempts worst cases 44 and last the other side shoe 45 attempts
Sir how 36 attemp 18+16=34 So next from 35,36 37 38 39 40 41424445 can be the only righ or only left pair shoes when he will pick up 46 then definatly it wl be one side shoes so it became complete clear pair so ans should be 46 ??????? Question said pair so both righ or left shoes how can became a pair pls clear
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In question 1, at 2:30 what if both the shoes (35th & 36th) are of same leg (left or right) ? To make a pair, it should be 1 left and 1 right. So, I think it should be (d)45
Ans 45
Sir....in 9 question...for 3 Rd Statement u took 5 and 3....they both are prime numbers...they were asked to take one composite and one prime number ...so once check it sir
Q.1.
Now, if he picks any two shoes, they are certainly going to be red. However, we also need to ensure
that the red shoes picked by him make a pair, i.e. there should be one red shoe for left foot and one red
shoe for right foot. For this to happen we need to pick 11 red shoes.
So, maximum number of attempts to get a red pair of shoes = 34 + 11 = 45
In Q.21 The smallest value of m would be 127. Let's just say we get all black, blue, green, yellow, red balls. The total will be 126, when we draw another (ball no.127) it comes out white. Hence smallest value of m is 127, not 167. Hence only statement 1 is correct.
I too thought that would be the ans
Please upload more and more videos of Related CSAT Shamanth Sir.
In question 4, what if both red are of same side (say both are left), he can't wear. In question it specifically mentions "to wear" 😢
What if I m scoring 64 in CSAT with 97+ in GS Paper 😒... Tat too in 4th Attempt.. Am i the unluckiest one 😣??
Did u clear mate
😢😢😢😢😢😢
Q37. We can deduce it. Let milk only be x.
Then,
60+15+45+x=5x.
first i want to join the the coaching for understand the questions 🤣😅😆
Thank you for the explanations sir. Had a doubt regarding Q 38 at 50:22 .
Using both statements we can get the answer 312 which is divisible by 6. But 132 is also divisible by 6 so how can we answer the question as there are two possibilities 312 and 132 so I think both statements are insufficient to answer the question. Shouldn't the answer be (d)?
No bro...Both statements are Sufficient to answer the question....
I feel the answer for the shoes question will be 45.
What if he keeps on picking up one shoe of each pair of red shoes after 34 attempts. That is if he picks left shoe of 1st pair of red shoes in his 35th attempt and then left shoe of 2nd pair in his 36th attempt and so on. This leads him to pick all the left shoes by 44th attempt. Then on the 45th attempt he will pick any right shoe of any pair which will eventually make him have a pair of red shoes.
The question is very vague. Answer can be more than one depending on the interpretation. If it was sock, it was ok but they changed to shoe😂
Sir please
Explain questions of digital sum???
Please
Thank you for this. Quantitative solutions are what I needed most!
Sir for question number 2 the correct answer is 20. 19 is wrong answer please check once 🙏
Hlo sir thank you very much for your explanation it was very helpful sir question no.9 pc can be odd was wrong I think you have taken 5prime number for multiplication
Answer for the 1st question is option (d) 45. Shoes 35 to 44 could be red shoe of either left or right leg. So 45th pick will give him one complete pair of red shoes
th-cam.com/users/shorts92sWCD99eZ4
A+B = 32
B+C = 36
C+A = 38
A+B+C = ? Plz solve this question
Question 1 :( d) 45
First question: he cant use same side shoes to wear
He have worst case of getting all same side shoes
Thus 34 + 10 44 attempts worst cases
44 and last the other side shoe
45 attempts
Q34. We have to use summation of AP
Shallow explanation with no conceptual clarity and many answers wrong too such as q27
Question nomber 1 might be wrong the answer should be 45
39th Q, shouldnt the answer be option A?
Sir in q.38, 132 is also divisible by 6 apart from 312 therefore it's not possible to find the exact number. Option D is the right answer
Sir question no.25 why we can't look for series in arithmetic progression instead of prime number
For option 2
There is also another pattern different from others as
5^2 +6,6^2+5,7^2+4,8^2+3
Can you please explain if there can be other possibility in this??
Please discuss about GS paper..
Soon 😊
Wrong ans from start....45 will be ans of que 1.....
Sir how 36 attemp
18+16=34
So next from 35,36 37 38 39 40 41424445 can be the only righ or only left pair shoes when he will pick up 46 then definatly it wl be one side shoes so it became complete clear pair so ans should be 46 ??????? Question said pair so both righ or left shoes how can became a pair pls clear
Q7-199
When will you post the answer key for Csat I don’t want to watch an hour long video just for keys
Posting in 5 minutes 😊
Thank you!
1st question answer is 45 sir ... 36 is wrong answer
ans of 28 is c
Q32 hw u got lcm 65
q48 is wrong.D cant be 5
Sir, q38. 312 and 132 both possible. So is it c or d??
Sir question no 79 in csat series c number is 132 according to me answer will b..correct me if I am wrong
Can anyone of you tell which year paper this one?
2023
2023
Q.50 both will be true sir
Thank you so much sir
q 50 1 only
45 attempts raj needs. Not 36
not helpful at all
wrong methods taught