Python Program to Remove Duplicate Elements from a List

In this tutorial you will learn to write a Python Program to Remove Duplicate Elements from a List.
The function that we create here will take a list which as duplicate elements as a parameter and it will return a list without any duplicates.
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[@sanjaychanghate8898]

Thanks sire u helped me a lot😘😘😘

[@ExampleProgram]

Most welcome 😊

[@mR_r0b07]

Thanks sire u helped me solve my assignment 🇳🇬💗💗

[@ExampleProgram]

Most welcome 😊

[@fredsoda3034]

Thank you. I appreciate your Support for the Community.

[@ExampleProgram]

❤️

[@Adrian.LovesFitness]

YOU SAVED MY LIFE!!!!!!!

[@ExampleProgram]

Pleasure

[@mayank9447]

You made your code so complex you could just convert the list to sets and all duplicates would be gone

[@vickyrocks6560]

excellent bro

[@moodmaker2796]

To be fair: I am a beginner and I new about the x2 = list(set(x)) method but I thought I needed to figure out problem solving shit... not thinking once about the possibility of a "not in" statement... so I came here and was enlightened... only to forget it in two days haha.
Doing shit the hard way can be very helpful to learn the basics I guess.

[@sktdebnath]

This is exactly what I did. But you will mess up the order. So you have to sort according to the list index.

[@deepaksankhua7791]

Yeah

[@PadaiWallah-tz8ls]

@@moodmaker2796 this 🙌

[@lindsay9120]

thank you, dawg. appreciate ya

[@ExampleProgram]

No problem

[@sinengazzah5528]

i swear i love u bro

[@ExampleProgram]

thank you :)

[@riadalhasanabir6716]

thank you so much it solved my assignment

[@ExampleProgram]

You are most welcome

[@siddigamer4426]

Thank you very much>>>...

[@ExampleProgram]

You are welcome!

[@Abhishekkumar-fi1dy]

This is really helpful

[@ExampleProgram]

Glad this helps you :)

[@VibexxD]

List1=[1,5,6,4,2,3,3,3]
Set1= set(List1)
List1=list(Set1)
print(List1)
Better than your code sir.

[@Gunashekaryadav-oq1um]

Bro it's user defined function 😂

[@pennywise6058]

Bro u put that duplicate list into set datatype and you again convert the set to the list data type and print the list like this
List1=[ 1,5,6,4,2,3,3,3]
Set1=set(list1)
List1= list(set1)
Print(list1)

[@prasanna4280]

Yes..
Friend i have another doubt in .py
If we want to find index of second occurrence of a number in list what we do.. ans need urgent

[@HarshaMaddur]

Please correct me if I am wrong. Why complicating things by defining function. Why not this following simple code:
data=[10, 20, 30, 30, 40, 50, 50, 60, 70]
noduplist=[]
for element in data:
if element not in noduplist:
noduplist.append(element)

print(noduplist)
#output: [10, 20, 30, 40, 50, 60, 70]

[@abrarulhasann]

totally agree

[@HarshaMaddur]

@Prashant Rai Ok. Thank you.

[@KILLER-kt9no]

good one bro!

[@ShubhamRai06]

by defining function we can , use it any no of time with any no of duplicate list , that's what functions are use for...

[@rohitsinghrawat6317]

print(list(set(data))) try this

[@AttachmentStudios]

Use this rather maybe if you wanna reduce lines of code:
# Function
remove_duplicates = lambda input_list:list(dict({key:0 for key in input_list}))
# Example/Usage
my_list = [...]
my_list = remove_duplicates(my_list)

[@susantaVlogs180]

for loop would be performance killer if we have a big list...

[@Davidkunde]

list comprehension will come in handy in this case

[@rajeswaranr9082]

Awsm❤️

[@ExampleProgram]

thank you

[@flipaclip-animators6455]

Nice work

[@ExampleProgram]

Thanks

[@majjigurunadh6108]

Tq Sir

[@ExampleProgram]

Welcome

[@GladwinNewton]

Thank you

[@ExampleProgram]

You're welcome

[@ammadammad4709]

Can we count the duplicate numbers In a list without using count built-in function?
I want an output like...
(Number, repeated x times)

[@nishalmalhotra3116]

#Remove Duplicate Elements from a List and count the number of duplicate elemnets
lst=[5,2,4,-5,12,2,7,4,4]
new=[]
count=0
for i in lst:
if i not in new:
new.append(i)
#print(i)
x=len(lst)-len(new)
print("The orignal list is : ",lst)
print("The new list without duplicates is : ",new)
print("The number of repeated elements in the orignal list are : ",x)

[@cedar693]

when I heard an Indian accent I knew, I'd learn something today.

[@ExampleProgram]

👍

[@mymantra4]

We can convert the list into set to remove duplicates

[@kshitishkumarbehera8974]

thanks you are amazing 💖💖💖💖💖💖💖💖

[@hotroadcol4166]

Thanks

[@ExampleProgram]

Welcome

[@escapefelicity2913]

It might be a REAL GOOD IDEA to post the code

[@ExampleProgram]

thanks for the suggestion.
i will try to implement that :)

[@vashistathakuri8026]

You can just convert it to a set and convert it back to a list.

[@shubham_birhade_vlogs]

This program question is asked in every interview

[@ExampleProgram]

oh :)

[@gianlucacaredda5202]

I am trying to print also the noduplist by the console tells me that it is not defined. What should I do ??

[@sumitbhoi4070]

For elements in duplist likhna jaruri hai kya ?

[@mohammadaslam5815]

Sir pls.. say sir
Noduplist is a empty list
But how we check if the element present in noduplist or not...

[@sahilhanda6761]

See what happens is we iterate over the new list and if for example '0' is there in list , program will not execute. Therefore 'not in' is used

[@orangeullr]

nice

[@ExampleProgram]

Thanks

[@telugughostloverskaadda2163]

Please tell me how to remove alternative eliminats in a list

[@hotroadcol4166]

👍👍👍

[@ExampleProgram]

Thank you :)

[@areebtahir2692]

Sir ye har value ke liye kam nhi krega.
While loop se krye ek baar

[@kvelez]

data = [10,20,20,30,40,50,50]
def remove_duplicate(data, i):
if i >= len(data):
return data
if isinstance(data[i], int):
if data[i] == data[i+1]:
data.pop(i)
return remove_duplicate(data, i+1)
print(remove_duplicate(data, 0))

[@alfonsoramirezelorriaga1153]

It would be great if you could show how to do it withouth the "not in" method. That is what I am trying to do. I am trying to loop through "unique" and if "i" is not equal to "j" then I append i to unique. However, I am doing something wrong sintaxis wise.

[@carlfernandez9897]

Can't you sort it, loop through the array comparing it to the last element and if so delete that that element/append it if not, to a noduplist. Then it sorts in nlog(n) time and runs in n time. This will run in worst case (n/2)^2. which is worse after 8 elements.

[@janardhanm3060]

❤

[@ExampleProgram]

thanks

[@RohitRaj-nt9ot]

It's not working in my system. Error says function object not iterable

[@timechannel5850]

but how to remove duplicate with that number for example numbers=[2,2,4,4,6,8,8,9] it will be unique =[6,9] . how to solve that problem?

[@karisamichael2417]

Nice video but...?
How do you delete the '+' in the list below?
My_list=[+1222..., +1838..., 1737...]

[@lostfrequency89]

Is this even efficient?

[@AnilKumar-wf7lb]

Sir what is the output for 1-2,2-3,3-4,4-5

[@shubhamkumar-h5h9w]

This program is wrong

[@VeebaSauce]

Your explanation is not to the point.
Can't understand what are saying.