why we cant transmit the B frame in [t - Tfr, t] time slot and A frame in [t, t+ Tfr] ?? why the entire [t - Tfr to t] time slot shoul be free in order to avoid collision??
I never have understood a single lecture by Tutorials Point. He should either speak in Hindi or if he chooses to speak in English then that should be clear. *पता नहीं क्या हि बोलता है* |
at 10:49 you told that to avoid a collision the previous frame should also be free but the forward time should also be free for it to avoid the collision in future then the Vulnerable time should be V=3*Tfr right???
The next Tfr will be taken into account by the next station who has to transmit data next. Next Tfr will be counted in vulnerable time for next station.
why we cant transmit the B frame in [t - Tfr, t] time slot and A frame in [t, t+ Tfr] ?? why the entire [t - Tfr to t] time slot shoul be free in order to avoid collision??
00:01 Pure Aloha is a random access protocol for wireless LAN and shared medium. 01:34 Collision occurs when multiple stations transmit data at the same time. 03:05 Pure Aloha allows stations to transmit frames on a shared medium. 04:39 Pure Aloha enables any station to transmit data at any point of time, leading to collision possibilities. 06:05 Pure Aloha uses a strategy called waiting for a random amount of time to prevent collision. 07:31 The throughput of Pure Aloha is maximized when frames are of uniform size. 09:04 In Pure Aloha, collisions occur when multiple frames are transmitted simultaneously. 10:37 Pure Aloha is a multiple access protocol
why we cant transmit the B frame in [t - Tfr, t] time slot and A frame in [t, t+ Tfr] ?? why the entire [t - Tfr to t] time slot shoul be free in order to avoid collision??
I hope you know how adored you are by us CS and ECE students. I've talked to random other students who definitely use your channel as a huge resource.
Definitely
why we cant transmit the B frame in [t - Tfr, t] time slot and A frame in [t, t+ Tfr] ?? why the entire [t - Tfr to t] time slot shoul be free in order to avoid collision??
The most underrated channel. Thank u for each and every tutorial ❤️
Still With 2.11m subscribers?
I am new to this channel and this channel satisfies me with high quality teaching experience.
You explained this so much better than my professor.
Neso academy is doing their best grateful job keep it up 👍
Excellent teaching sir.. We want more videos from u
Who need paid courses when you have a Neso Academy courses for free 🔥🔥
Thanks, that really helped to visualize it.
super explanation, clear voice. Thank you very much. better than tutorials point lecturs..
I never have understood a single lecture by Tutorials Point. He should either speak in Hindi or if he chooses to speak in English then that should be clear. *पता नहीं क्या हि बोलता है* |
you are ultimate man!!!lots of love to you
Great video, keep up the amazing work
Thank you Sr 😃
really excellent sir
MR. Neso THANK YOU for giving such information for us.... keep going..😇😇
clear explanation thank you very much
This explanation is so clear .thanks♥️🔥👍
at 10:49 you told that to avoid a collision the previous frame should also be free but the forward time should also be free for it to avoid the collision in future then the Vulnerable time should be V=3*Tfr right???
The next Tfr will be taken into account by the next station who has to transmit data next. Next Tfr will be counted in vulnerable time for next station.
No, if the current frame is free and we know that all frames are uniform. It is obvious that the next frame will not be collided with the current one.
@@mahamamir9176 elaborate
2:30 😂😂😂😂😂👌👌👌👌
Hiii
How are you❤
@@sumadhursah6019 ha bhai mil gaya reply
Excellent Teaching
Please upload full playlist of computer networks
Please install our app for the complete course.
@@nesoacademy it is still asking for fuel
11:40 how the number of stations can be in a non-integer value G=0.5?
Same question
it means when one station transmit in 2Tframe then u will get maximum efficiency
can we simulate ALOHA using Packet Tracer? If yes then please upload its video? If no then please let us know , in which platform we can do this?
thank you sir
Thank you so much
You're really good!! Thank you
Thankuu sirrr it means a lot💗
Thank you!
thank u so much sir
Thank you very much👍
For throughput formula, if G = number of stations...how can we take G = 0.5 ?
same what a nonsense line, and trying to explain it as if it makes some sense.
Simple and best
Very helpful!
Explanation 👍🔥
Awesome sir👌👌👌👌
Doubt :How the throughput of pure ALOHA is maximized when frames are in uniform length?🤔🤔🤔🤔🤔
Compare the last slide with the first slide
Non uniform has more collision
@@whois2517 Thank you
You understand well so you are able to explain in simple manner❤️❤️whereas our lecturers never understand 😏so thy can't teach properly🤦
why we cant transmit the B frame in [t - Tfr, t] time slot and A frame in [t, t+ Tfr] ?? why the entire [t - Tfr to t] time slot shoul be free in order to avoid collision??
thank you
7:30? Someone please elaborate why it happens
Nice Video!👍
Thanks sir
00:01 Pure Aloha is a random access protocol for wireless LAN and shared medium.
01:34 Collision occurs when multiple stations transmit data at the same time.
03:05 Pure Aloha allows stations to transmit frames on a shared medium.
04:39 Pure Aloha enables any station to transmit data at any point of time, leading to collision possibilities.
06:05 Pure Aloha uses a strategy called waiting for a random amount of time to prevent collision.
07:31 The throughput of Pure Aloha is maximized when frames are of uniform size.
09:04 In Pure Aloha, collisions occur when multiple frames are transmitted simultaneously.
10:37 Pure Aloha is a multiple access protocol
why we cant transmit the B frame in [t - Tfr, t] time slot and A frame in [t, t+ Tfr] ?? why the entire [t - Tfr to t] time slot shoul be free in order to avoid collision??
@Neso Academy what is frame transmission time??
thanku
How can we have 1/2 station????
So pure aloha does not actually solves the problem of collision?
It solves,by retransmitting if ack is not received by the sender
Why throughput is maximum at G = 0.5 ?????
@@_s_h_l_o_k_ differentiate it, and equate to 0, you'll know.
How 1/2 system as transition state
BOOM!
Tq sir nice
13/7/21
11:51 am
impossible that i saw this comment at the same time three years down the line. Gosh!!
Boom!
sir total kitne video hai iss series mei
205
@@kaushalagrawal1620 Yaha to bas 97 hi dikh rhe h
Nice video🤟
Now i remember ALHOHA with the boom
does this videos has notes?
Please what is half station
9:46
What is the limit of G in pure-aloha? :(
I know a website where you can check it. its name is google.
@@catast9075 gotem
Great , Brilliant bro but please use Hindi language
Half Station ?
Does it mean half of the total number of stations (G) involved in transmitting the frames ??
7:30? Someone please elaborate why it happens
A❌ Yeaa✅
You dance around collisions without actually explaining the ALOHA protocol properly.
How Can I get your ppt?
You can't.
🤩
boom
,it leads to collision.
i am dead after listening to your pure accent :-
A :- ye
shared :- shard
damn god protect us
saviour
This technique is very tedium
Cant get it 😅
yay and b
Ycce gang wya
it seems that the world suffer from bad teachers, this is very obvious from the comments.
2:24 BooM!!
p
Wv
3rd class
just chnge the backgrond green background………………………..
Very poor pronunciation... 😢
Hindi nhi aati kya Bhai use Hindi also
The Indian accent in this video is hard to understand. Perhaps a AI generated voice is more welcomed
Please change your voice tone
Boom!
Thank You