👉 Enroll in Yodha Test Series Now: bit.ly/yodhatestseries 👉 Join Class 10 Telegram for updates - t.me/Class10ByRankplus 👉 Download App for FREE Test Series: Android - bit.ly/rp-android-app 👉 iOS - bit.ly/rankplus-ios-app
Good evening sir, it's omkar Home work - question 17 Given - W(power) - 60W Time - 6hr Solution - total energy consumption will be - 60W × 6hr =360Whr We know that, 1 KWhr =1000 Whr So accordingly - 360whr = 0.36 KWhr Total energy consumption in a month of 30 days will be = 0.36KWhr × 30 days = 10.8 kWhr ★ANSWER=10.8 KWhr
All Formulas of Electricity: 1) I = Q/t 2) Q = ne 3) V = W/Q 4) V = IR 5) R = Rho x L/A 6)Resistance in Series: Rs = R1 + R2 + R3 7)Resistance in Parallel: 1/Rp = 1/R1 + 1/R2 + 1/R3 (» Reciprocal of R1+R2+R3) 8)H = V × Q i) H = VIt ii) H = I²Rt iii) H = V²t/R 9) P = W/t i) P = VI ii) P = I²R iii) P = V²/R 10) E = P × t S.I. Units: Current ( I ) - Ampere Charge ( Q ) - Coulomb Time ( t ) - Second Potential Difference or Voltage ( V ) - Volt Resistance ( R ) - Ohm Ω Resistivity ( Rho ) - Ohm meter Power ( P ) - Watt Heat = Energy = Work = Joule Measuring Devices: Ammeter / Milli Ammeter - for measuring current (always connected in series) Galvanometer - for measuring small/sensitive currents (we can also get the direction of the current) Voltmeter - for measuring volts (always connected in parallel) Ohm Meter - Measures the resistivity Things to remember: electron charge = (1.6 x 10⁻¹⁹ C) 1kWh= 3.6 × 10⁶J 1Ampere = 1000mA 1 Kilowaat = 1000W
12:19 SIR (ii) QUESTION ME AAP CURRENT 1/3 LE KE SOLVE KIYE TOH VOLT AAYA 1.67 OR ME CURRENT 0.3 LEKE SOLVE KIYA TOH VOLT AA RHA HAI 1.5????!! Plz sir tell me😢
@@shristyjaiswal2442 Plug key off hai tou mtlb current flow hi nhi krega aur circuit open ho jayega circuit Tut jayega isiliye potential difference zero hoga
Hello sir, Firstly thank you to all the teachers for the effort they are doing for us...❤ I have a question...? Aap jo PYQ's karwa rahe hain they are enough yaa hame alag se bhi PYQ's lagane padege and milenge kaha se saare PYQ's sir...? Hope u will read my question and respond to it!🤗❤
I dont know how but when I randomly came across this video, it blew me. Usse bhi zyaada toh wo test series jo sirf 49 ki hai. I really hope ki sir aap jo questions karaa rahe hain, usi mein se aaye and I will purchase the test series asap. This channel is truly a hidden gem/
Q17) Given : 60 W bulb 6 hr daily 30 days To Find : Energy 1kwhr = 1000W So , 60W = 0.06Kw According to formula Consumption of energy in a day E=P×T = .06×6 =0.36 Kwhr Consumption of energy in a month of 30 days So, =0.36×30 =10.8 Kwhr
sir please don't ignore this! I need help please reply kariye I am having hell lot of anxiety! Actually maine jo signature loc pe kari thi I don't remember that exactly matlab maine "a" kaise likha tha apne name ka "w" kaise likha tha..aur omr sheet pe same signature karni padti hai! Ab mai kya karun? Aur kya jo admit card hota hai uspe wo loc wali signature print hoke aati hai? Ya phir agar meri signature different hui writing mei toh kya meri copy nahi check hogi? Please sir reply me
@Decemberfruit1 Bro don't worry your admit Card will come with your signature that you have done in loc and if your signature is not Identical to 10-15 % then your answer sheet would not be checked otherwise it will be checked and I think that you are smart enough that you can copy your done signature. I Hope it helps
@@AyushVerma-yg6wh but bro I searched on Google and there is a blank space for signature...matlab signature admit card pe baad mei karni hoti hai aur wo printed nhi hoti
Sir plz ye bta do ki agr ye video dekh lenge to pyqs cbse ke paper se nhi n krenge bcz oswaal ke sample paper bhi kar rhe h jissme pyqs to rhta hi hai.plzzzzzz bta do aap khud bole ho hum sbke liye hi aaap❤❤❤❤❤❤❤❤❤❤❤❤❤❤ aur hmne yodha series bhi liya h
Answer for last question - E= P × T. E= 60w × 6 × 30 ( energy for 1 month). E= 10,800 WATTS. Therefore, energy consumed for the entire month will be 10.8 Kwh.
given - p = 60 w in 1 day power consumed = 6 hours in 30 days = 30*6=180 hr energy consumed in 30 days= p *t 60 w * 180 hr 108000whr divide by 1000 10.8 kwh ans..
👉 Enroll in Yodha Test Series Now: bit.ly/yodhatestseries
👉 Join Class 10 Telegram for updates - t.me/Class10ByRankplus
👉 Download App for FREE Test Series: Android - bit.ly/rp-android-app
👉 iOS - bit.ly/rankplus-ios-app
Sir 49 rupees mein sab sabject ka ka question hoga
Jaise biology ka bhi math ka bhi aur sabhi ka ki kewal 1 sabject ka aayega sir kewal 49 rupees mein sir pls tell me
Thank you sir literally sir jo app questions karvata ho vohi exam ma ata ha thank you ❤
Good evening sir, it's omkar
Home work - question 17
Given - W(power) - 60W
Time - 6hr
Solution -
total energy consumption will be - 60W × 6hr =360Whr
We know that, 1 KWhr =1000 Whr
So accordingly - 360whr = 0.36 KWhr
Total energy consumption in a month of 30 days will be
= 0.36KWhr × 30 days
= 10.8 kWhr
★ANSWER=10.8 KWhr
Same answer bro
Or
3.89X10^7 joules
All Formulas of Electricity:
1) I = Q/t
2) Q = ne
3) V = W/Q
4) V = IR
5) R = Rho x L/A
6)Resistance in Series: Rs = R1 + R2 + R3
7)Resistance in Parallel: 1/Rp = 1/R1 + 1/R2 + 1/R3 (» Reciprocal of R1+R2+R3)
8)H = V × Q
i) H = VIt
ii) H = I²Rt
iii) H = V²t/R
9) P = W/t
i) P = VI
ii) P = I²R
iii) P = V²/R
10) E = P × t
S.I. Units:
Current ( I ) - Ampere
Charge ( Q ) - Coulomb
Time ( t ) - Second
Potential Difference or Voltage ( V ) - Volt
Resistance ( R ) - Ohm Ω
Resistivity ( Rho ) - Ohm meter
Power ( P ) - Watt
Heat = Energy = Work = Joule
Measuring Devices:
Ammeter / Milli Ammeter - for measuring current (always connected in series)
Galvanometer - for measuring small/sensitive currents (we can also get the direction of the current)
Voltmeter - for measuring volts (always connected in parallel)
Ohm Meter - Measures the resistivity
Things to remember:
electron charge = (1.6 x 10⁻¹⁹ C)
1kWh= 3.6 × 10⁶J
1Ampere = 1000mA
1 Kilowaat = 1000W
Thank you soo muchhh🤍💌🎀🌺
Power= 60 w = 0.06kw
time=6hrs
Energy= power× time taken
= 0.06× 6
= 0.36 kwh
Daily = 0.36 kwh
30 days = 0.36 × 30
= 10.80 kwh
1 kwh = 1 units
10.80 kwh = 10.80 units
= 11 units ( approx )
THANK YOU SO MUCH SIR...🤝🏻
WE WANT MAGNETIC EFFECTS OF ELECTRIC CURRENT CHAPTER MOST REAPEATED QUESTIONS...!!🙏🏻💯
Q.17 ANS = 10.8KWH ❤ 37:28
37:31 solution 10.8kwh
Paid the required sum for yodha test series, still im unable to get access to the questions... Was not expecting this dreadful experience.
Have you received it atleast by now??
Q 17
Ans - e= p.t
E = 60 . 180
=10800 wh
=10.8 kwh
14:40 sir ye kya hai phir 😅
Answer of H.W =10.8KWH
14:35 sir agar individually nikala tho galat hoga.? Pls clear my doubt
Sahi hoga. But use me time thoda jada lagega or last me dono ko add karna padega to answer same hi ayega 🤝
@ankitclecker4328 thanks
dekho bhai pw ke andar ncert solution me sir ne individually kiya hai toh vo bhi sahi ha ok
37:05 10.8 kwh
Excellent vedio💯💯
Abhishek sir is One of the best teacher 🥰🥰😘😘
Goat
I study physics only from him❤
12:19 SIR (ii) QUESTION ME AAP CURRENT 1/3 LE KE SOLVE KIYE TOH VOLT AAYA 1.67 OR ME CURRENT 0.3 LEKE SOLVE KIYA TOH VOLT AA RHA HAI 1.5????!! Plz sir tell me😢
37:05 the answer is 10.8
Answer is 10.8 kwh 37:24
10.8kwhr is anwer 37:22 ❤
12:26 sir part (ii) plug key is off and that's why current is not flow in circuit then how we can find voltage?
Plug key off ka mtlb closed h to current flow karega
@@shristyjaiswal2442 Plug key off hai tou mtlb current flow hi nhi krega aur circuit open ho jayega circuit Tut jayega isiliye potential difference zero hoga
Oh thanks
37:45 ans is 10.800❤
37:14
10,800 Wh ❤️🙌🏻
Q.17
P = 60W ; t = 6 h
∴ E= P.t = 60 X 6 = 360 Wh
In KWh : 360/1000 = 0.36 KWh
∴ energy consumed in 30 days = 0.36 X 30 = 10.8 KWh
Sir notes kahan available hoga please reply sir
37:27 motivation de diya sirrrr
Thank you so much sir for giving most expected question of electricity sir we want magnetic effect 17 most expected question .
Hello sir,
Firstly thank you to all the teachers for the effort they are doing for us...❤
I have a question...?
Aap jo PYQ's karwa rahe hain they are enough yaa hame alag se bhi PYQ's lagane padege and milenge kaha se saare PYQ's sir...?
Hope u will read my question and respond to it!🤗❤
Zarurat nahi hai beta, agar apko krna hi hai toh Yodha Test Series kr skte ho kafi hoga
@@Class10byRankplus Ohk sir thank you so much!🤗
12:30( ii) answer 1.6
37:05 answer - 10.8 Kwh
Sir i have lot of issue in power related numericals plz make a video dedicated to power related numericals plz sir its an humble request
Sar Mere Pre board mein aapke isme se do teen question repeat hue 🙏❤️❤️❤️
Sir apka content sabse zyada useful hota hai❤❤
14:20 me to V2/R FORMULA LAGNA CHAHIYE !!??
H.W
TIME - 37.06
ANS - 10.08KWH
10.8 units
Answer for q17
Sir batch enroll ho hi nhi rha
Thank s alot sir ❤for providing such informative video
I dont know how but when I randomly came across this video, it blew me. Usse bhi zyaada toh wo test series jo sirf 49 ki hai. I really hope ki sir aap jo questions karaa rahe hain, usi mein se aaye and I will purchase the test series asap. This channel is truly a hidden gem/
Thanks sir keep going on sir......... ❤
Sir ye bahut badhiya thaa kyuki Live mein time bahut waste hota hai. ❤🎉
Answer of question number 17 is 108 kWh
Wrong hee😅
P= 60W, T= 6h ×30= 180
W= pt
W= 60×180
W= 10800 wh
W= 10.8 kwh Ans
10800 joule or 10.8 Kwh because Energy=power into time.
37:48 ans 10.8kwh
Thank you sir ap bas last ch electric effect and mangent wala dal do 17 most repeated physic se maja ane laga hai ap mere co ❤❤❤love you sir
Next topper 😂
@IluKhan-hx7gr Hasane ka kya bad hai ham practice ke liye deka Hai
37:18 10.8kwh
37:32 10.8 Kwh
P =60w
T=6hr
E= Whr
60×6 = 360 Whr
In 30 days
360 × 30=10800
But in kwh ,
10.8 kwhr Ans
@Salonimehta3 heyy sister are you from orrisa
Thank u sir feeling a bit confident
Q17)
Given : 60 W bulb
6 hr daily
30 days
To Find : Energy
1kwhr = 1000W
So , 60W = 0.06Kw
According to formula
Consumption of energy in a day
E=P×T
= .06×6
=0.36 Kwhr
Consumption of energy in a month of 30 days
So,
=0.36×30
=10.8 Kwhr
Thank youuu so much sir for this Hardwork and dedication for us ❤.
Answer of Last question:- 10.8 kwh. 😊
Good evening sir it's Hemadriii HOMEWROKQUESTION Q17) =10.8 KWH .. Thank you sir veryy much I wish you to bless me and all the other students
Answer for 17 questions
Energy consumption= watt×hours×days÷1000
So,W=60
T=6hrs
Days=30
Solution
W×T×d÷1000
60×6×30÷1000=10.8J
10.8 kwh 37:40
Most underrated teacher❤❤❤❤🎉😢😢😢
Sir mere sare questions shi ja rhe h but fir v mujhe bahut dar lag rha h
ANS OF LAST Q = 10.8 KWH
3:51
3:54
3:56 3:57 3:57 3:57 3:57 3:58 3:58 3:58
Q17: 3.6 Kw Hour
sir please don't ignore this! I need help please reply kariye I am having hell lot of anxiety!
Actually maine jo signature loc pe kari thi I don't remember that exactly matlab maine "a" kaise likha tha apne name ka "w" kaise likha tha..aur omr sheet pe same signature karni padti hai! Ab mai kya karun? Aur kya jo admit card hota hai uspe wo loc wali signature print hoke aati hai? Ya phir agar meri signature different hui writing mei toh kya meri copy nahi check hogi? Please sir reply me
Reply me sir please I am too disturbed because of this
@Decemberfruit1 Bro don't worry your admit Card will come with your signature that you have done in loc and if your signature is not Identical to 10-15 % then your answer sheet would not be checked otherwise it will be checked and I think that you are smart enough that you can copy your done signature. I Hope it helps
@@AyushVerma-yg6wh Is that signature already printed on the admit card?
@Decemberfruit1 yes bro
@@AyushVerma-yg6wh but bro I searched on Google and there is a blank space for signature...matlab signature admit card pe baad mei karni hoti hai aur wo printed nhi hoti
Sir carbon and it's compounds bahut kamjor h kuch bhi nhi ho pa rha h.
Kyu bhai tu to next toppers ka student hai karwaya nhi sir ne😂😢
Thanks sir for this video 🙏🥰💫💫🌹🌹🌹💥💥🎇🎇🥰
day by day heart beat 📈☠☠
Same for all bro
HELLO SIR JI. SESSION WENT AMAZING AS ALWAYS......HOMEWORK QUESTION ANSWER IS 10.8Kwhr ....
ITHNA HELPFUL VIDEO !!!! SUBSCRIBE KAR LIYAAA
last ans is 10.8 KWh
37:12 10.8KWH or 38880000JOULE
thakyou so much sir.
37:02 10800 joule
36:55 10.8 kwhr
Sir plz ye bta do ki agr ye video dekh lenge to pyqs cbse ke paper se nhi n krenge bcz oswaal ke sample paper bhi kar rhe h jissme pyqs to rhta hi hai.plzzzzzz bta do aap khud bole ho hum sbke liye hi aaap❤❤❤❤❤❤❤❤❤❤❤❤❤❤ aur hmne yodha series bhi liya h
Sir energy is comming 0.36 kw/hr
Edit :- my mistake I didn't multiplied it with 30 days
Now final answer is 10.8kw/hr
Thankyou for this sir. Was really helpful 🔥
37:33 thanks
Answer for last question -
E= P × T.
E= 60w × 6 × 30 ( energy for 1 month).
E= 10,800 WATTS.
Therefore, energy consumed for the entire month will be 10.8 Kwh.
10.8 kWh is the answer of hw question.
Really amazing I really appreciate and helpful
Last qs answer - 38880 Kj
Q.17
P = 60W
T = 6 x 30 = 180 hours
P = 60/1000 KW
P = E/T
P x T = E
60/1000 x 180 = E
*Energy = 10.8KWh*
12:30 ke divide galat kiya ap na
37:30 complete 👍
Sir you are great ❤
ANS 10.8 KWH
Sir electricity search karu 7-8 aapke hi video aa jate hai ❤
Thank you sirr ❤..... Quest.17 = 10.8kwh
Sir payment nahi ho raha hai😢
Sir you are great
Sir apne jo question karwaya hai unme se bhut question 2023 me aaye hai par apne mention nhi kara hai 😊😢
Thank you sir
given - p = 60 w
in 1 day power consumed = 6 hours
in 30 days = 30*6=180 hr
energy consumed in 30 days=
p *t
60 w * 180 hr
108000whr
divide by 1000
10.8 kwh ans..
Thank you for this video sirrr
Sir q3 mein 5 ohm wale resistor ke across bhi to voltmeter banana chahiye tha na ?
Sir matals and non metals sir . Please sir 17 questions sir
H.W ans:- 10.8kwh or 10800wh
10.8
q17 : 10.8
H.w questions E = P×T ans is 10.8Kwh
Sir app to Hacker ho jiii❤✌️🤩
Bhaiya exam bohot paas aa rhi hai
Dar lag raha hai
Kya kare
10.8kwh. ❤❤❤🎉🎉 awesome 👍😎 sir please reply l find my favourite one sir please 🥺 🥺 🥺 🥺 🥺 🕐
10.8 answer is right 👍👍
P = w.t
P = 60 × 10 × 30
P = 18000 W
P = 18 kw