How to print Hollow Diamond Shaped star "*" pattern using Python | python tutorial for beginners

[@TycomacCodes]

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[@TycomacCodes]

If you like this to type of content then consider subscribing, it really helps out the channel
Find more pattern programs here:
th-cam.com/play/PLhBd9eXZZqGIhrPl97yOfOAI7TqJQOHRm.html

[@williamjayaraj2244]

Thank you for this lesson on creating diamond pattern in an easily understandable method.

[@yashilrajbeesetty6628]

Ur video helped me, can't say how much😌

[@THE_KODER]

Awesome bro

[@gurvirsandhu8644]

What if you want the rows and columns to be n, not 7?
Please answer

[@frd334]

Take if condition as below,but it will work for only odd numbers such 3,5,7,9,11 ...:
n = int(input())
for row in range(1,n+1):
for col in range(1,n+1):
if (row+col==(n+1)/2+1) or (col-row==(n+1)/2-1) or (row-col==(n+1)/2-1) or (col+row==n+(n+1)/2):
print('*',end='')
else:
print(' ',end='')
print()

[@DemonExplainer01]

n=int(input("enter row"))
for i in range(1,n+1):
print(' '*(n-i)+'*',end="")
if i>=2:
print(' '*(2*i-3)+'*',end="")
print()
for i in range(1,n):
print(' '*(i)+'*',end="")
if i

[@07_crew_officials]

Its not exactly giving the correct pattern their is a issue in output can u plz check nd provide the correct one...

[@keremoztopuz875]

hello sir, i did exactly what u did but my output is this:
b
b
b
b
b
b
b
b
b
b
b
b

[@Remo123]

😘

[@anshulkumar8195]

not true for all cases

[@mohankadagala59]

Its a customized code and is not valid for other inputs if you provide

[@ganeshjadhav566]

# hollow diamond
n = int(input("Enter number of rows :: "))
def hollow_diamond(n):
for i in range((n*2)-1):
for j in range((n*2)-1):
if (i+j == n-1) or (i-j == n-1) or(j-i == n-1) or (i+j == 3*(n-1)):
print(" *",end="")
else:
print(" ",end="")
print("")
hollow_diamond(n)
this code generate accurate output for any inputs (in numbers)