Maclaurins Series Expansion for ln(1+x) : ExamSolutions Maths Revision

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  • เผยแพร่เมื่อ 14 ม.ค. 2025

ความคิดเห็น • 10

  • @EmilyDeibert
    @EmilyDeibert 11 ปีที่แล้ว +3

    Great video, thank you!

  • @SorryCrane16
    @SorryCrane16 10 ปีที่แล้ว +9

    I don't understand how to generate the general solution term with r in it

    • @tuneese2561
      @tuneese2561 4 ปีที่แล้ว +2

      the (-1)^(r-1) determines the sign before the term.its to determine the sign (if it is positive or negative). Look at the last term for the blue graph (-x^4/4). In this case r=4 and the sign is negative. If we do (-1)^4 we get +1 making the sign positive which would be incorrect. If we put the power as r-1 then when we put in r=4 the power becomes 3. (-1)^3 is -1 which means the sign will be negative which is correct. generating the general solution is very hard as you have to look and identify small details then figure how to express them in the general solution term.

    • @KatyVLOGS12
      @KatyVLOGS12 3 ปีที่แล้ว

      @@tuneese2561 you're a saviour

  • @shabistantaqvi2404
    @shabistantaqvi2404 5 ปีที่แล้ว

    What do you use for writing (software and hardware)?

  • @heinrichwoogue8887
    @heinrichwoogue8887 9 ปีที่แล้ว +1

    excuse me guys could you help me out, i am trying to make a code for the ln function using taylor polynomials without calling predefined functions. I seem to have trouble in calculating for ln(0.1) because it needs a lot of terms (or iterations in coding) to be accurate to 10^-6 or 6 decimal places. I would like to ask if there can be some special ln rule that can help me lessen the number of terms in the taylor series to calculate for ln (0.1)?

  • @loftystandards9991
    @loftystandards9991 4 ปีที่แล้ว

    If I were to sum the first n terms of log(1+x), what would it be? Help?

  • @kiyodante
    @kiyodante 6 ปีที่แล้ว +2

    Why does the last term of the series ln (1+ x) is (-1)^r-1 x x^r all over r. Why is it r-1?

    • @tuneese2561
      @tuneese2561 4 ปีที่แล้ว

      its to determine the sign (if it is positive or negative). Look at the last term for the blue graph (-x^4/4). In this case r=4 and the sign is negative. If we do (-1)^4 we get +1 making the sign positive which would be incorrect. If we put the power as r-1 then when we put in r=4 the power becomes 3. (-1)^3 is -1 which means the sign will be negative which is correct.

  • @079palashpatel9
    @079palashpatel9 3 ปีที่แล้ว

    nai hua tho deakh lena wtf