Edexcel A level Maths: 1.1 Proof By Contradiction

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Pearson A level Maths, Pure Year 2 textbook (1.1)
In this video I cover:
1. Negation Statement
2. Ration and Irrational Numbers
3. Proof By Contradiction

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How is he this good at explaining hard concepts it honestly baffles me,my teachers explanations were so bad and hard to understand but Zeeshan explained it absolutely brilliantly.God bless you!

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Zeeshan has explained this in 13 minutes better than my maths teachers had throughout the year, thank you!

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this is a very good and detailed explanation thank you so much for the lesson

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[@baburlu]

selam, but if n is not a multiple of 3, cant it be 3k - 1 or 3k + 2?
dont we need to do them all?

[@ali_a1805]

salam, no because when you are doing proof by contradiction you only need to find one case where the original statement doesnt work so doing 3k+1 only is fine

[@GoatedGamer-v7n]

My teacher said u gotta do both cases cuz it comes under it not being a multiple of 3 and the textbook says that aswell​@ali_a1805

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[@HonyaHikmatQadr]

Ifn is an odd number then n^4 is also an odd number. Please answer that

[@nadineabusaleh9401]

i did not understand example 3) we said that n must not be multiple of 3 however we wrote it as n=3k+1 , as we can factorise it to n=3(k)+1 and it is a multiple of 3 ?

[@ali_a1805]

3k+1 cant be a multiple of 3 as if you take a number (k) then x3 then add 1 it will never be a multiple of 3 as it is always 1 more than a multiple of 3

[@nadineabusaleh9401]

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[@jeffs_r_us7166]

Uve proved that EVERY non multiple of three number squared will also not be a multiple of three, so theres no case where u can have a non multiple of three square to a multiple of three, so ur contradiction is wrong

[@angeldioxide]

@@jeffs_r_us7166 that's the point of the contradiction. It's supposed to highlight the fact that there's no case where you can have a non multiple of three square to a multiple of three, by stating that every non multiple of 3 will always ever square to a non multple of three

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[@benwebber4523]

What if n squared was 3? Then n would be root 3 and therefore not a multiple of three?

[@Wow-hr1gl]

root 3 is irrational in these questions they are integers

[@frostedbg142]

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