If possible let there be some m for which ,s be less or equal to m/n for all n .So s is a lower bound of the set A={m/n:n is in IN)} . But greatest lower bound of A is 0. Thus contradiction arises as 0
please explain sir ji Question => in which following cases, there is no continuous function f from the set S onto T ? (a) S = [0 1] , T = R (b) S = (0 1) ,T = R (c) S = (0 1) , T = (0 1] (d) S = R , T= (0 1)
Sir wkt directional derivative exist at a point implies partial derivatives exist at that point ( necessarily). If partial derivatives exist and continuous ( or f is differentiable) then directional derivative exist( sufficient only). Then if the given statement is " directional derivative of f exist at a point then which of the following r true?" If One option is 'f is differentiable' Then is itright option?? Because we can take an example as a differentiable function then that has directional at that point . That is one example of given statement satisfy differentiability condition.
Anusha T i think it is not true always... as u mention directional derivative exist at a pt implies partial derivative exist at that pt but we know partial derivative existence doesn't imply that the function is always differentiable..... bt i have a dbt.... so let's wait for sir's reply
Give me one example such that The option is true but not necessarily true. I want to ask that Is it like that , given option is true means, there exist an example satisfying given condition in the option but that option is not in general true (i.e. there exist a counterexample for given option) And given option is necessarily true means it has no counterexample at all.......??
Suppose we have question. Let G be a finite group of order 10 then 1. G has atleast one element of order 2 2. G has 5 elements of order 2 In above option one is necessary true. But option two is true but not necessarily.
Fantastic explaination sir.....
Thnx for the knowledge ...
Plzzz regularly videos....upload krein..🤗
Yes. I m uploading regularly videos. Thank u
Sir plzz upload Archimedian property having examples
Once again best technique for discard options...sir G
Special for C part ....
Great sir ....keep it up....
Aapke videos bhut help ful hote h sir thank you 🙏
Thnx sir for solution series of real analysis,it helps a lot for preparation ☺️☺️🙏🙏
For the 2nd option n=1 will work for each m in IN
Nice, very easyly convinced respected sir..
Superb explaination sir..
Nice question
Rahulji, for option B given any m, choose m=n so that m/n=1 and s< 1.
Very good technique for explanation...thank you sir..
Philosipical explanation. Nice
Aap bahut hi aacha explanation dete hai sir plese jam ke liye v kuch kijiye most request hai sir aapse
Aapka lecture bahut hi interesting hota hai sir hame bahut aacha lagta hai sir aap iit jam ke liye v video banaye sir plese
V. Nice explanation
First or second case ke liye irrational use kar sakti hai .......to
Very nice explanation sir
sir i solved this question yesterday but i was confused in option C, but now it is clear, so thanku sir, thank you so much... 😊😊
ok
For 3 , observe that some elements of (0,1) are irrational numbers....And for 4, there is no natural number in (0,1)
Yes true. Your all comments and logics are very good. Appreciate..
Thank you sir... Your videos are very nice...
We are selecting m and n from N and not from (0,1)
Yes . Right.
Right bro..
sir muje options discard aur select m cnfusn h thodi... frst nd 2nd option discard b toh ho skta h kisi b counter xample se
Mind blowing solving
Nice explanations bro
Sir AAP ne first and second option Mai kyu root 2 use nhi Kiya...confusion h
Tb to 2nd option bhi nhi lie karega interval (0,1) me
Very nice explanation sir....👍
Sir.. option 1,2 . There is any possibility check for irrational numbers...???
Option 2 ke liye if n=m then s
Sir how option 2 can be correct? If I take s=0.5 and m=1 is there any n s.t s is less than m/n?
Nice explanation sir
But sir in 1st and 2nd condition if i take a irrational number between 0 and 1 then whether for all m there exists a n
But not from natural numbers. So we discard this option
Wow ❤❤ very nice
Nice explanation
Sir apka real analysis complete syllabus he m.sc mathematics ke lye ?
nice and good explanation sir
Sir please real analysis chi lecture series chalu kara
Wow.good sir.
Please solve MSc maths lecturer exam important Mcq questions
Sir app ka gate questions solution nahi mil rahi he kyu ???
Ty sir
Sir choice function aur axiom of choice samajh nahin aa raha ! Kya karun !
what is difference between set of limit point and sequence of limit point
This is the difference
th-cam.com/video/02w1mPsWDCI/w-d-xo.html
If S = [0,1] then what happened
Sir pls provide videos nd notes of linear algebra.
Ur classes r really too good
Ok
If possible let there be some m for which ,s be less or equal to m/n for all n .So s is a lower bound of the set A={m/n:n is in IN)} . But greatest lower bound of A is 0. Thus contradiction arises as 0
0 doesn't belongs to the set A.
Superb. . . ✌✌
Thank u Professor..
Sir ist option ke liye rational value pe check krne pe v wo shi kaise hoga?
Aap irrational bhi le sakte hai, wo to Maine example k liye liya tha
Thank u sir very i.
We are not taking irrrational number in option 1 & 2?
So u can take.
nice sir
Sir I am a student of graduation maths ....sir regular class nahi ho sakta sir . graduation ka please
Thank you sir
3rd me confusion h sir
Sir..i m doing msc from assam...we two r interested to join a coaching institute next year....reply me sir
please explain sir ji
Question => in which following cases, there is no continuous function f from the set S onto T ?
(a) S = [0 1] , T = R
(b) S = (0 1) ,T = R
(c) S = (0 1) , T = (0 1]
(d) S = R , T= (0 1)
C
sorry sir, ye question 2013 june CSIR net ka hai aur answer key me CSIR walo ne option (a) ko right krar diya hai so please explain deeply
Thnq sir...
Sir फिर आप ने option 1,2 मे भी irrational hi choose करना था
Why your camera is regularly autofocusing..
I m not using camera, I used my mobile phone to shoot. That's why video is fluctuating I think.
Sry sir.. for my comment
. but your concept is very clear.... and excellent
no it's OK. suggestions always welcome.
good one rahul ji tum mujhe m so main aap ko n dunga.
What is the difference between
"... Then which of the following are true?"
And "...Then which of the following are NECESSARILY true?"
following are true means ,if u get counter example for this statement is true, but necessarily true means every example should satisfy the statement.
Sir wkt directional derivative exist at a point implies partial derivatives exist at that point ( necessarily). If partial derivatives exist and continuous ( or f is differentiable) then directional derivative exist( sufficient only). Then if the given statement is
" directional derivative of f exist at a point then which of the following r true?"
If One option is 'f is differentiable'
Then is itright option??
Because we can take an example as a differentiable function then that has directional at that point . That is one example of given statement satisfy differentiability condition.
Anusha T i think it is not true always... as u mention directional derivative exist at a pt implies partial derivative exist at that pt but we know partial derivative existence doesn't imply that the function is always differentiable..... bt i have a dbt.... so let's wait for sir's reply
Give me one example such that
The option is true but not necessarily true.
I want to ask that
Is it like that , given option is true means, there exist an example satisfying given condition in the option but that option is not in general true (i.e. there exist a counterexample for given option)
And given option is necessarily true means it has no counterexample at all.......??
Suppose we have question.
Let G be a finite group of order 10 then
1. G has atleast one element of order 2
2. G has 5 elements of order 2
In above option one is necessary true.
But option two is true but not necessarily.
Thank u sir
nice sir
Nice sir
Thank you sir