Volume Using Known Cross Sections (Slicing) | Calculus 2 Lesson 5 - JK Math

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  • เผยแพร่เมื่อ 18 ธ.ค. 2024

ความคิดเห็น • 12

  • @bobtivnan
    @bobtivnan 2 ปีที่แล้ว +9

    I was hoping you would cover volume by cross sections. Great job with the 3-d drawings!

    • @JKMath
      @JKMath  2 ปีที่แล้ว +1

      Thanks! They can definitely be tricky to draw sometimes.

  • @maxtaylor12
    @maxtaylor12 23 วันที่ผ่านมา

    Insanely great video

  • @hyunjinscrunchytoenails8860
    @hyunjinscrunchytoenails8860 10 วันที่ผ่านมา

    ur saving my life right now thank you so much. i have a final on thursday and im cramming right now on a saturday night tryng to stay sane

    • @JKMath
      @JKMath  9 วันที่ผ่านมา

      Glad to help! Wishing you the best on your final, you've got this 👊

  • @pastamen158
    @pastamen158 6 หลายเดือนก่อน +4

    this channel is peak im in love with you

  • @BlooMzieees
    @BlooMzieees 6 หลายเดือนก่อน

    Do you have video that talks about the instances when it is not rotated in non zero axis

    • @JKMath
      @JKMath  6 หลายเดือนก่อน

      What calc 2 topic are you referring to? This video does not deal with rotating regions around an axis (no solids of revolution), we are only looking at solids with bases defined by a function and that have cross sections of common shapes we know the area of. If you are looking for solids of revolution, check out my videos on the Disk method, washer method, and shell method. All can be found in the beginning of my calc 2 playlist. Hope this helps!

  • @saraalriyami-z5l
    @saraalriyami-z5l ปีที่แล้ว +1

    In the last example, the base is bounded by x=0 so isnt that supposed to mean that it wont include the region under the x-axis

    • @JKMath
      @JKMath  ปีที่แล้ว +2

      The line x=0 is the same as the y-axis, not the x axis. So the region below the x-axis is included. If the base was instead bounded by y=0, then you would be correct in saying that it doesn’t include the region under the x-axis. Does that make sense?

  • @Josama0214
    @Josama0214 6 หลายเดือนก่อน +1

    For Example 2, The semi circle is perpendicular to the y-axis, which implies that it is parallel to the x axis, not the line y = 1/2 x

    • @JKMath
      @JKMath  6 หลายเดือนก่อน +1

      Correct, that is exactly what I show in my 3D sketch around 14:10. The base of the semicircles are perpendicular to the y-axis, parallel to the x-axis, and are neither parallel nor perpendicular to y=(1/2)x.