DM-11-Derangements

Here you learn how to calculate derangements

[@dusko173]

Thank you sir, you are very good teacher and everything is clear without doubts.

[@bhavuks6554]

Sir I have a confusion, how non relative prime numbers = pq + p^2 - p ?

[@YOUR12341]

|s(p)Us(q)|=(n/p)+(n/q)+(n/pq)
put n=(p^2)q in above you will get
pq+p^2-p.

[@vrundavarvedia530]

*|s(p)Us(q)|=(n/p)+(n/q)-(n/pq)

[@ShaliniSingh-fq6on]

why n/p?

[@subham5060]

total number divide by p

[@muhammadiqbalbazmi9275]

@@YOUR12341, how, just prove it.

[@prajaktakharwandikar9546]

You are a very good teacher

[@arundhakad1575]

Why you have not covered Recurrence Relations and Generating functions

[@SalimAnsari-xh2hs]

You are a legend sir, Thank you 🙏🙏🙏🙏

[@adityasaini8437]

bro is this playlist covers all topics sufficient for gate

[@SalimAnsari-xh2hs]

@@adityasaini8437 Yes, if you already have some basic ideas about Discrete Mathematics then this playlist will help you.

[@adityasaini8437]

@@SalimAnsari-xh2hs thanks for your feedback

[@ayushgoel4660]

Sir , How to solve recurrence relation videos are missing !!!

[@saddamahmad2310]

Thankyou sir your video is very helpful to us
again very very thanks a lot for helping us

[@anchitjindal07]

Number of non derrangements when 4 persona are in their original position should be zero because when 4 persons have occupied their original position their will be only one position left which is correct position of 5th person. So there will be zero non derrangements. Please correct if I am wrong

[@uddeshya98]

A non-derangement is nothing but an Arrangement. When all the people are at their 'correct' positions, it is not a derangement, but it is still an arrangement. That's why, number of non-derangements i.e. arrangements is 1.

[@Epicshorts54]

Good initiative Sir

[@akashdinkar2541]

very well explanation sir.....very thank u!!!!

[@jayeshjuneja2219]

Sir nice session with nice teacher

[@tulasiram6371]

@10.35 when 1,2,3,4 are in exact positions , then the last element has to be in the correct position only, which is the given sequence , in one way only

[@muhammadiqbalbazmi9275]

that is the reason there is 1!. and you know that 1!=1.

[@SachinKumar-lk6uc]

Thanks a lot sir. :)

[@ranjeet9868]

the main question is why the signs are alternating ?

[@Sneha_Negi]

He just proved in the whole video.. It is because the principle of mutual exclusion and inclusion

[@muhammadiqbalbazmi9275]

sir voice is not clear in this video.
anyway thanks.

[@akumlonglongkumer3824]

someone pls prove me non relative prime numbers=pq+p^2-p i think the prove vedio got cut here

[@gourishanker7419]

Non relative prime number = n/p +n/q+n/pq
Now substitute n =(p^2)q

[@bense_tony]

Important Rule :
If the clockwise and counter clockwise orders CAN be distinguished then total number of circular permutation of n elements taken all together = (n-1)!
If the clockwise and counter clockwise orders CANNOT be distinguished then total number of circular permutation of n elements taken all together = (n-1)! / 2

[@amanjain3339]

thanks sir

[@mathsandeducationcoach2840]

thank you sir...