Lecture -- Electrostatic Boundary Conditions

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  • เผยแพร่เมื่อ 17 ธ.ค. 2024

ความคิดเห็น • 13

  • @yosefpatinio3669
    @yosefpatinio3669 4 หลายเดือนก่อน +1

    good video !
    in the min 5:20 , why the faraday law equals to zero? what about the magnetic field? it's a EM wave...
    and why in the integral take E as a constant?

    • @empossible1577
      @empossible1577  4 หลายเดือนก่อน

      Thank you!!
      This video is in a sequence for electrostatics. The magnetic field term appears in a derivative with respect to time. This goes to zero for electrostatics.
      BTW...here is a a link to the official course website. It has links to the latest versions of the notes, videos, summary sheets, and other learning resources.
      empossible.net/academics/emp3302/

  • @MohamedNassar-dr1dw
    @MohamedNassar-dr1dw 6 หลายเดือนก่อน +1

    Thank you , really great Video , the only resource which I was able to understand clearly and follow.

    • @empossible1577
      @empossible1577  6 หลายเดือนก่อน

      Thank you! Happy to help!

  • @PresCalvinCoolidge
    @PresCalvinCoolidge 5 หลายเดือนก่อน +1

    Great explanation. Would you please make a video on the electromagnetic Boundary Conditions?

    • @empossible1577
      @empossible1577  5 หลายเดือนก่อน +1

      They are exactly the same, just that the terms are phasors instead of scalars. The magnetostatic boundary conditions are Lecture 5j here:
      empossible.net/academics/emp3302/

  • @PerJohannessen
    @PerJohannessen ปีที่แล้ว +1

    wow your lectures are really good. I wish you covered the entire griffiths book

  • @hongpan0507
    @hongpan0507 2 ปีที่แล้ว +1

    Very clear explanation for dielectric to dielectric boundary condition. @15:08, If electric field cannot exist in the metal, why can we not say the normal component of the electric field in the metal is zero?

    • @empossible1577
      @empossible1577  2 ปีที่แล้ว

      The normal component of E must be zero inside of the perfect metal. However, the normal component of E is not continuous across the interface so the normal component of E in the dielectric does not have to be zero.

    • @hongpan0507
      @hongpan0507 2 ปีที่แล้ว +1

      @@empossible1577 Thank you. Professor. That's very helpful.

  • @localfuture1484
    @localfuture1484 6 หลายเดือนก่อน +1

    Hi, I think " These are derived from Ampere's Circuit Law and Gauss' Law. " should be changed to " These are derived from Faraday's law of induction and Gauss' Law."

    • @empossible1577
      @empossible1577  6 หลายเดือนก่อน +1

      Are you referring to slide 6 around 2:30? That first equation is Ampere's circuit law in integral form for electrostatics. Did I misspeak somewhere else?

    • @localfuture1484
      @localfuture1484 6 หลายเดือนก่อน +2

      @@empossible1577 I think That first equation is " Maxwell-Faraday equation " instead of "Ampere's circuit law"