You're very welcome, Ŕicky Kurosawa. Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Best regards :)
With quadratic equations if you put in anything as A B and C you'll get a simple answer. In cubic equations only a fraction of equations are simple, most are very long
Simply put x=1 or -1 and check whether it is equal to 0 or not. That little complicated stuff you showed for checking x=1,-1 came from the same logic but the former idea doesn't need anything to be to be memorized. Thanks for a good explanation in other cases. Liked it.
Thank you so much Aisha for your continued love and support. Take care dear and stay blessed😃 Keep smiling😊 Enjoy every moment of your life 🌻 Jazakallah!
thank you so much for this 🥺 we learnt this during online school and i didn’t understand a thing 😭 i feel more prepared for my test tomorrow thank youu 🤩
You are very welcome Aaliya! I'm sure you are a brilliant and bright student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
You’re an absolute legend sir, I’m cramming one day before my exams and these tips are so useful sir thank you so much for taking the time and effort to make this video ❤️❤️
You're very welcome Malik Saab! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep supporting my channel. Kind regards :)
It was really very helpful Sir.....I was searching for the video in which for the equation whose x^3 coefficient is not '1'......here I found......Your professional students are very luck.
In case of cubic equation point of view, At first one of the root should be obtained by applying "hit & trail method "(Although it needs some simplification in some cases ), Then other roots may come out by deviding the first root (suppose the first root is 7, then you have to devide the given equation by x-7), then move on (personal opinion )
Thanks for this. I've been working on a new math module and this gave me a really solid start at solving polynomial equations, as these techniques were easy to implement.
Glad to hear that Jonathan! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing premath channel with your family and friends. Take care dear and all the best😃
2x^3+x^2-13x+6=0 On observation, x=2 satisfies this equation (x-2)=0 is a factor of 2x^3+x^2-13x+6=0 (2x^3+x^2-13x+6)/(x-2)=(2x^2+5x-3)=0 using synthetic division. In 2x^2+5x-3 b^2>4ac therefore 2x^3+x^2-13x+6 has three real roots. (x-2)(2x^2+5x-3)=0 x= -3 is a solution by observation (x+3)=0 is a factor of (2x^2+5x-3)=0 (2x^2+5x-3)/(x+3)=(2x-1)=0 using synthetic division. (2x-1)=0 is a factor of 2x^3+x^2-13x+6=0 Therefore,(2x^3+x^2-13x+6)=(x-2)(x+3)(2x-1)=0 Hence x=2,x= -3 and x=1/2 are the three real roots of 2x^3+x^2-13x+6=0 Thanks for the puzzle PreMath.
You are very welcome Vinutha! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and stay blessed and healthy😃 Keep smiling😃
You're very welcome! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep supporting my channel. Take care😃
I think the method explained is rather a trial-and-error approach and the following method will be more logical: Let us consider the LHS of the equation as y and as x approaches to plus infinity, y also approaches to plus infinity; similarly, when x approaches to negative infinity, y also approaches to negative infinity. What does this mean? This means y is a continues function sloping in the NE-SW direction. Meantime, x = 0, y = 6 and x = 1, y = -7 which means that there will be a real root between 0 and 1. As y is sloping in the NE-SW direction, we can deduce that there has to be 3 real distinct roots to y. When x = -1, y = 18; This clearly indicates that the 3 real roots to function y namely α, β and γ (say α
sire, would you consider making a video? a transcript is difficult to follow at once, hence a video such as khanacademy's or this style would be much appreciated. this method may be "easier" however i'm unable to read it/remember it in this format. thanks.
Dear sun flower, you are very welcome. Thank you so much for taking the time to leave this comment. I'm glad you liked the vid. Your feedback is always appreciated. Keep it up. Kind regards :)
In that case, remove fractions first by find the LCD (LCM). Thanks Andrew for asking. I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing premath channel with your family and friends. Take care dear and all the best😃
You are very welcome Amy! I'm sure you are a brilliant and bright student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
You are very welcome Mery from beautiful Morocco! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃 Keep smiling😊
The check by comparing the sum of the roots against -B/A is going to come in handy! Thx!! Quick Question: Does this answer check work when there are 1 real root and 2 complex roots?
You are very welcome! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear and all the best 😃
This is just the way I did it (taking hints from highest power, constant term and Vieta) before seeing the video solution ... 2x³+x²-13x+6=0 Looking at the equation. Based on the 2x³ term, 2x-1 might be a solution (plug in x=1/2 - it is). Based on the constant term x+3 might be a factor (plug in x=-3 - it is). Vietas rule/formula says sum of solutions = -b/a -1/2 = 1/2 -3 + r (r is the third root) r=2 verfiy ... (2x-1)(x+3)(x-2)=2x³+x²-13x+6 In this case the guesswork was fine - the above two were the only guesses I tried. It is not always so. For example I might have guessed a more complicated (2x+3) as a factor.
So nice of you dear! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing premath channel with your family and friends. Take care dear and all the best😃 Have a very happy and blessed New Year!
You are very welcome! I've already made few videos on trig. Please search videos in my channel. If you want me to make videos on specific questions, please send it on my email: math@mycollege.org Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear and all the best 😃
You are very welcome Devdatt! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃 1
You're very welcome Arpita! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear 😃
You are very welcome dear! You are awesome 👍 I'm glad you liked it! Please keep sharing premath channel with your family and friends. Take care dear and all the best😃
Thank you so much Kevin for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear and all the best 😃
Glad to hear that Raghupathi! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
Hey guys there is a really good explanation of the cubic and quartic formula on the channel mathloger also explains why quintic equations can’t be solved with radicals using Galo is theory
Hi! Is there an easier way to find the solutions, since it might take a lot of time during exams to solve all the options. But anyways great video! You helped me a lot
guys this guy is legit doing it the wrong way it's like a really basic thing we can simply differentiate this equation and then with the gradient solve it for x and y...
You are very welcome Kailen! I'm sure you are a brilliant and bright student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
You are very welcome Flash! I'm sure you are a brilliant and bright student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
Thank you so much Harsh ji for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear and all the best😃
You are very welcome dear! I'm sure you are a brilliant and bright student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
Thank you Sir for a Most Excellent algorithm to solve Cubic Equation. Do you have an algorithm to solve ? Quartic : (AX^4 + BX^3 + CX^2 + DX + E) Quintic : (AX^5 + BX^4 + CX^3 + DX^2 + EX + F)
Dear Parveen Kachura , you are very welcome. Thank you so much for taking the time to leave this comment. I'm glad you liked the vid. Your feedback is always appreciated. Keep it up. Kind regards :)
Dear Chris, you asked a very nice question! Please watch these videos to factor out problems like above: th-cam.com/video/WKYIoUnMAnI/w-d-xo.html th-cam.com/video/0A1vPvPt_co/w-d-xo.html th-cam.com/video/Ul6x99bTSGA/w-d-xo.html Thanks for asking. If you still have question, please let me know. Take care dear and all the best😃
Thanks, this is really very helpful..continue your good work.
Cheers! ❤
You're very welcome, Ŕicky Kurosawa. Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Best regards :)
what if our equation is not factorable?
ya😄
amazing ..th-cam.com/video/JdyMqmnWJi8/w-d-xo.html
Ysss
Any bodies here after facing problem in finding characteristics equation for eigen vector
yeah
Yes😅
Yeah!! 😅
Kaise pata bhai🤩🤩
@@krishnathombre7946 😎😎😎guess
Who is here after facing problems in eigen value roots
Me😂
😂😂
me
😅
Bruuuuuuuuh
Myself 😭
One of the clearest snd cleanesr solutions to a cubic equation.
This will make solving eigenvalues and eigenvectors easier.
With quadratic equations if you put in anything as A B and C you'll get a simple answer. In cubic equations only a fraction of equations are simple, most are very long
i cnt believe i can find a 11min vid clearing up all my doubts when an hour long lesson in my sch just leaves me ???? thanks for this :))
Simply put x=1 or -1 and check whether it is equal to 0 or not. That little complicated stuff you showed for checking x=1,-1 came from the same logic but the former idea doesn't need anything to be to be memorized. Thanks for a good explanation in other cases. Liked it.
Most of you are here for eigen vectors
True
One of the clearest and cleaner solution on whole yt .. thanks a lot sir
Everyone tells put 1,-1,0,2,-2etc but no one tells this method 😮
Well done our society needs more content like this😊
Thank you so much Aisha for your continued love and support.
Take care dear and stay blessed😃 Keep smiling😊
Enjoy every moment of your life 🌻
Jazakallah!
What just happened that was such a good explanation video idk why but I felt so much smarter. You're really good at this, keep it up :D
thank you so much for this 🥺 we learnt this during online school and i didn’t understand a thing 😭 i feel more prepared for my test tomorrow thank youu 🤩
Same
You are very welcome Aaliya! I'm sure you are a brilliant and bright student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
You’re an absolute legend sir, I’m cramming one day before my exams and these tips are so useful sir thank you so much for taking the time and effort to make this video ❤️❤️
You're very welcome Malik Saab! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep supporting my channel. Kind regards :)
amazing ...th-cam.com/video/JdyMqmnWJi8/w-d-xo.html
this is the only helpful video out there on cubic polynomials, i appreciate this so much !!
God bless you very much, you're a genius.
I finally found a lingering solutions to my eigenvalues characteristic determinant.
So nice of you, dear
Thank you! Cheers! 😀
@@PreMath I wish you show a lesson too, about vector spaces.
And also there're some of the equations I have that are not factorising.
Hello, great video. Those rules you mentioned to find if x = -1, 1 are the solutions, where can I read about it?
It was really very helpful Sir.....I was searching for the video in which for the equation whose x^3 coefficient is not '1'......here I found......Your professional students are very luck.
This thing was so helpful, it deserved my like and subscribe
Who is here after bsc 🤣
Finally i found a better way of solving step 👌🏻👌🏻👌🏻
U also study? 😂😂😂
I thought u r a big mesy
😂😂😂😂
For x= -1 can we have same sum of alternate coefficient but opposite signs?
In case of cubic equation point of view, At first one of the root should be obtained by applying "hit & trail method "(Although it needs some simplification in some cases ), Then other roots may come out by deviding the first root (suppose the first root is 7, then you have to devide the given equation by x-7), then move on (personal opinion )
Thanks for this. I've been working on a new math module and this gave me a really solid start at solving polynomial equations, as these techniques were easy to implement.
Glad to hear that Jonathan! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing premath channel with your family and friends. Take care dear and all the best😃
@@PreMath Thank you!
amazing ...th-cam.com/video/JdyMqmnWJi8/w-d-xo.html
You are a wonderful teacher and doing best to create good human resource.
For sure time is delayed in in certain intervals, but given consistent and smooth paths, time moves in polynomial steps
2x^3+x^2-13x+6=0
On observation, x=2 satisfies this equation
(x-2)=0 is a factor of 2x^3+x^2-13x+6=0
(2x^3+x^2-13x+6)/(x-2)=(2x^2+5x-3)=0 using synthetic division.
In 2x^2+5x-3 b^2>4ac therefore 2x^3+x^2-13x+6 has three real roots.
(x-2)(2x^2+5x-3)=0
x= -3 is a solution by observation
(x+3)=0 is a factor of (2x^2+5x-3)=0
(2x^2+5x-3)/(x+3)=(2x-1)=0 using synthetic division.
(2x-1)=0 is a factor of 2x^3+x^2-13x+6=0
Therefore,(2x^3+x^2-13x+6)=(x-2)(x+3)(2x-1)=0
Hence x=2,x= -3 and x=1/2 are the three real roots of 2x^3+x^2-13x+6=0
Thanks for the puzzle PreMath.
Thank u so much . It was very helpful and I was searching for this kind of teaching . l'm happy that I finally found it 😇
You are very welcome Vinutha! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and stay blessed and healthy😃 Keep smiling😃
Thank you,in Hong Kong,they did not teach us those interesting properties,and just teach us to aim higher marks
This what I want ....Lots of thanks & respect
You're very welcome! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep supporting my channel. Take care😃
U are from which country sir ?
U speak english clearly.
I think the method explained is rather a trial-and-error approach and the following method will be more logical:
Let us consider the LHS of the equation as y and as x approaches to plus infinity, y also approaches to plus infinity; similarly, when x approaches to negative infinity, y also approaches to negative infinity.
What does this mean? This means y is a continues function sloping in the NE-SW direction.
Meantime, x = 0, y = 6 and x = 1, y = -7 which means that there will be a real root between 0 and 1. As y is sloping in the NE-SW direction, we can deduce that there has to be 3 real distinct roots to y. When x = -1, y = 18;
This clearly indicates that the 3 real roots to function y namely α, β and γ (say α
sire, would you consider making a video? a transcript is difficult to follow at once, hence a video such as khanacademy's or this style would be much appreciated. this method may be "easier" however i'm unable to read it/remember it in this format.
thanks.
this is incredible, im speechless
2 divided by 6 is 3! Brilliant!!!!!!
thankyou so much, you are better than my teacher.
Dear sun flower, you are very welcome. Thank you so much for taking the time to leave this comment. I'm glad you liked the vid. Your feedback is always appreciated. Keep it up. Kind regards :)
thanks
thank you so much sir!! Jesus bless you and your family always!
Worked so far! But what do I do if my coefficients are fractions?
In that case, remove fractions first by find the LCD (LCM).
Thanks Andrew for asking.
I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing premath channel with your family and friends. Take care dear and all the best😃
i think this the best video ever made on cubic . thank u sir
Thank you so much your such a great teacher this really helped me keep on going!
You are very welcome Amy! I'm sure you are a brilliant and bright student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
thank u tecaher from morocoo (north of africa) i find this video really interesting and it really helped me a lot ♥
You are very welcome Mery from beautiful Morocco! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃 Keep smiling😊
Rabat
The check by comparing the sum of the roots against -B/A is going to come in handy! Thx!!
Quick Question: Does this answer check work when there are 1 real root and 2 complex roots?
When you were listing the divisors of P and Q, were those the factors of P and Q? Thank you.
Thanks for giving such easy and simple way to solve this! The way that taught from book which is LONG DIVISION are too complicated tho
You are very welcome! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear and all the best 😃
This is just the way I did it (taking hints from highest power, constant term and Vieta) before seeing the video solution ...
2x³+x²-13x+6=0
Looking at the equation.
Based on the 2x³ term, 2x-1 might be a solution (plug in x=1/2 - it is).
Based on the constant term x+3 might be a factor (plug in x=-3 - it is).
Vietas rule/formula says sum of solutions = -b/a
-1/2 = 1/2 -3 + r (r is the third root)
r=2
verfiy ... (2x-1)(x+3)(x-2)=2x³+x²-13x+6
In this case the guesswork was fine - the above two were the only guesses I tried.
It is not always so. For example I might have guessed a more complicated (2x+3) as a factor.
You are Awesome Sir !!
So nice of you dear! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing premath channel with your family and friends. Take care dear and all the best😃 Have a very happy and blessed New Year!
Its always the indians making good food and good tutorials
Thanks! And please make a video on trigonometric identities.
You are very welcome! I've already made few videos on trig. Please search videos in my channel. If you want me to make videos on specific questions, please send it on my email: math@mycollege.org
Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear and all the best 😃
Ur Explaination is just awesome
Very useful video and succinct tutorial. Thank you for this, cheers!
wtf gabs gamers dont do math
Can I ask about the graphic tablet and the application which you use
Thanks for the video, it is really very helpful.
You are very welcome Devdatt! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
1
Thank you sir❤❤❤❤
It is so helpfull in my jee preparation❤❤
Thanxxx a lot 😊😊😊
It really helped me a lot
I shared the concept amongst my frnds & they were quite surprised that I am studying these days 😂😂😂😂
You're very welcome Arpita! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear 😃
when the maths tutorials so good you start crying tears of joy
Thank you so much for this!! It was so helpful ^^
Thank you very much sir.
This is really helpful. Just keep up making this kinds of helpful videos.
Really easy to understand sir!
this is so helpful, thank you sir! gonna pass my test now
thank you so much sir you have tought me this solution....
You are very welcome dear! You are awesome 👍 I'm glad you liked it! Please keep sharing premath channel with your family and friends. Take care dear and all the best😃
Is step 2 still applicable when sums the same number "48" but has different signs? For example, 48 and -48.
Maybe you can substitute for x and see if x = -1
I love the Rational Roots Theorem
Thank you so much Kevin for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear and all the best 😃
Thanks, I've been trying to solve the cubic for so long, and this video helped me a lot. Thanks again.
0:46 ambulance!!!!
Lmao, you listening that sound 😁😁😁,instead of this
😂😂😂😂 I just couldn't ignore it either 😑
Are bhai bhai bhai 😂😂🥴
Wow! you are cool! Thanks for watching. Kind regards 😊
th-cam.com/video/CgcEEQIlpMk/w-d-xo.html
It's a very good explanation, I understood very much
Glad to hear that Raghupathi! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
@@PreMath thank you
Thank you 😊 sir, it helped me a lot .Now I know the best way to solve these type of questions
Hey guys there is a really good explanation of the cubic and quartic formula on the channel mathloger also explains why quintic equations can’t be solved with radicals using Galo is theory
Hi! Is there an easier way to find the solutions, since it might take a lot of time during exams to solve all the options. But anyways great video! You helped me a lot
Explain that easier way
@@butterfly99899 that's what I am asking
@@sainandhana8828 JUST USE ANY SCIENTIFIC CALCULATOR
What if it has a negative remainder using the synthetic division?
What to do sir?
Hi can we be friends please ☺
guys this guy is legit doing it the wrong way
it's like a really basic thing
we can simply differentiate this equation and then with the gradient solve it for x and y...
Normally putting x=2 in the equation will be quite easier than synthetic division.
Thanks for making it even more confusing
THANKS FOR YOUR HELP! ❤
LOVE FROM BANGALORE! 🗣
Thanks so much this was incredibly helpful, so clear and straightforward!
You are very welcome Kailen! I'm sure you are a brilliant and bright student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
What to do if last no. is not substracted completely
ex. x^3 - 9x^2+ 26x -24=0 ( x=2 )
Thank you so much
You are very welcome Flash! I'm sure you are a brilliant and bright student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
@@PreMath aww... Your complement made my day
☺☺
We solve as math teachers cubics as well
You might look at some examples
th-cam.com/video/ircZ_M1m3I8/w-d-xo.html
Yes absolutely
Solve equation 2x^3+x^2-13x+6=0
Solve:
2x^3+x^2-13x+6
=2x^3-12x^2+24x-16+13x^2-37x+22
=2(x-2)^3+(13x-11)(x-2)
=(x-2)[2(x-2)^2+(13x-11)]
=(x-2)[2x^2-8x+8+13x-11]
=(x-2)[2x^2+5x-3]
=(x-2)[(x+3)(2x-1)]
=(x-2)(x+3)(2x-1)=0
So
x-2=0
x+3=0
2x-1=0
So
x1=2
x2=-3
x3=1/2
Verify:x1=2 or x2=-3 or x3=1/2 are all the root of the original equation
解方程2x ^ 3 + x ^ 2-13x + 6 = 0
解答：
2x ^ 3 + x ^ 2-13x + 6
= 2x ^ 3-12x ^ 2 + 24x-16 + 13x ^ 2-37x + 22
= 2（x-2）^ 3 +（13x-11）（x-2）
=（x-2）[2（x-2）^ 2 +（13x-11）]
=（x-2）[2x ^ 2-8x + 8 + 13x-11]
=（x-2）[2x ^ 2 + 5x-3]
=（x-2）[（x + 3）（2x-1）]
=（x-2）（x + 3）（2x-1）= 0
所以
x-2 = 0
x + 3 = 0
2x-1 = 0
所以
x1 = 2
x2 = -3
x3 = 1/2
验证：x1 = 2或x2 = -3或x3 = 1/2都是原始方程式的根
AN - 09PF - Harold M Brathwaite SS (2482): Because the complex solution shows the students, they would like to learn the easy synthetic division.
It was awesome. It helped me a lot.
✌✌
Thank you so much Harsh ji for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear and all the best😃
thank you for saving my life
That was awsome thank you
You are very welcome dear! I'm sure you are a brilliant and bright student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
@@PreMath Your command is my wish i would share your videos as much as possible ❤
@@nr6728 Thanks dear. You are awesome. Stay blessed 😃
Does this work for all cubic equations
can I have a solution of this equation from the same solution-:
z^3-5z^2+7z+21=0
thank u!
Popular Power thnx bro
but I need full solution from that method
Its your school homework ?😂😂
@@leaveitblank2625 bro this thing is not present at school level.
@@jayjain4341 oh?well it's not too hard to solve anyway or you can use online solving website if you want some complex solution 😁 .
@@leaveitblank2625 I did it....that's why I came to this video but can't find its answer by this method that's why I asked!
Please acknowledge me which software used to make video.
omg thank you for this example only one i could find with everything i needed to studuy
08:05 can somebody please explain this part? I totaly don't understand where did he get these numbers
0.011x³+2.355x²-729.167=0
Plz solve this
In the synthetic division, what if 0 comes before the end?
Thanks it was helpful
Thanks Bir Amrit Singh for the feedback. Please share my channel with friends as well. Kind regards :)
Very very very helpful..greal work..👍👍👊👊👊
I miss 5th grade when I thought a+b=c
Lmao
Take care dear and all the best😃
Thank you Sir for a Most Excellent algorithm to solve Cubic Equation.
Do you have an algorithm to solve ?
Quartic : (AX^4 + BX^3 + CX^2 + DX + E)
Quintic : (AX^5 + BX^4 + CX^3 + DX^2 + EX + F)
Nice....but it's a time taking procedure
At 1:30, to solve a cubic equation, why is it that if the sum of all coefficients sum to 0, 1 is always a solution?
if u plug in x for 1 into the equation, it equals 0
@@Duckeiigot it! Thank you so much!
Glad I wasn't stuck with someone like him,....
Thank you for this video on solving Cubic Equations.
He was even slower then sloth 🤣🤣😂😂🤣🤣
Can you please explain me how does -1/2 came in LHS ?
10:05
Thanks sir
Dear Parveen Kachura , you are very welcome. Thank you so much for taking the time to leave this comment. I'm glad you liked the vid. Your feedback is always appreciated. Keep it up. Kind regards :)
@premath how did you factorize 2x^2+5x-3=0
Dear Chris, you asked a very nice question! Please watch these videos to factor out problems like above:
th-cam.com/video/WKYIoUnMAnI/w-d-xo.html
th-cam.com/video/0A1vPvPt_co/w-d-xo.html
th-cam.com/video/Ul6x99bTSGA/w-d-xo.html
Thanks for asking. If you still have question, please let me know.
Take care dear and all the best😃
Newton-Raphson method is a powerful mathematical weapon for this! 💪💪
This video really helpful Sir! Thanks a lot
Glad to hear that!
Thanks for your feedback! Cheers!
You are awesome, Keziah. Keep it up 👍
Love and prayers from the USA! 😀
Stay blessed 😀
THANK YOU SO MUCHHH!!! I FINALLY UNDERSTAND!!♥♥♥♥♥♥
bro you are a god amongst men. you should be recognized amongst the math world #fsal
You are so generous with your comments my friend. Take care dear and all the best 😃