Yes remember.... you need to shift x(t) or x(n) only in input and at the output you need to shift wherever n or t is present ... hope this cleared your doubt.... SUBSCRIBE and keep supporting EC Academy 👍
At Minute 3, could you explain why you write (-n-n0) into the brackets and not (-n+n0)? I'm confused because in the first example you replaced t with (t-t0) in both steps but in the second example you only replaced n with (n-n0) in the second step.
From BD, I like your theory sir... Please keep going ❤
Sir in 3rd question input = nx(n-no)
And output=(n-no)(x(n-no))
In input we shift only x(t)
Same in 5th question
Yes remember.... you need to shift x(t) or x(n) only in input and at the output you need to shift wherever n or t is present ... hope this cleared your doubt....
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At Minute 3, could you explain why you write (-n-n0) into the brackets and not (-n+n0)?
I'm confused because in the first example you replaced t with (t-t0) in both steps but in the second example you only replaced n with (n-n0) in the second step.
No clarity while performing operation on both sides on problem no. 2 n 3
U r session are very useful for us tq soo much sir keep uploading more love ❤️
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In 3 question
You substitute n-no in n value for all 1equation
But in 2 equation you not taken n-no in starting n why sir
In 3rd one ,u r doing wrong
Hey sir thanks for your videos
What if we have a system like this y(n)=3x(n)+y(n-1)
Is this an LTI System
Knowledgeable video
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Thank you. That was helpful
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thank youuuuuu prof!
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good work
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If y(n)=x^2(n) is given then what will be the solution sir??
y(n-no) = x^2(n-no) it is time invariant
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Thanks sir
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y(n)=log(x(n)) ??
Tx,❤️
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thank you..but I think you got mistaken in the way you solved Q3..
Solution is correct…
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