Circuits I: Example with RLC Circuit (Parallel, Natural Response)
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- เผยแพร่เมื่อ 2 ต.ค. 2024
- This video works through a problem involving a circuit with resistor, capacitor, and inductor in a parallel configuration. We examine the natural response of the voltage following a switching event.
University of California, Davis
ENG17: Circuits I, Spring Quarter 2015
Instructor: Dr. Kyle Montgomery
Course Website: www.kmontgomery...
Thanks a lot for this explanation. You explain things so clearly.
Why torture folks, just explain ac circuit analysis theory because capacitors and inductors have little use in most dc circuits. Use 2 pie F L and 1 over two pie F C as a reactance to a SET frequency which is how most all circuits are designed to be used. I’ve a degree in the field and twenty five years of experience so be real. I work with products of the market. Not university physics time exposure modals. I also have a computer science degree so get real GEZ. It’s nice calculus implementation but not necessary, I know.
Thanks for the comments - Yes, you may understand this...but unfortunately students in the majority of engineering programs around the world will have to do this, regardless of its real-world usage. These videos are over 7 years old now...and I'm no longer in academia, so, I get it. Regardless, I still get views and comments nearly everyday from students suffering through these problems from people even less qualified than I was at the time I recorded this!
For anyone wanted to see the derivative:
you should get dv(0+)/dt = e^-t * [A1(-WdsinWdt + cosWdt*(0) + A2[WdcosWdt + sinWdt * (0) ] + (A1cosWdt + A2sinWdt) * -e^-t
Plug in zero for t you get:
dv(0+)/dt = A2*Wd + A1(-1)
Or simply
dv(0+)/dt = -A1 + Wd(A2)
If you took the derivative of v(t) and multiple by c would that be the current thru the capacitor?
I just discovered your video series --GREAT PLEASE ADD MORE!-
It is helping me more than you can imagine.
Do you have any video(s) on worked series RLC examples? Did you know that this is the perfect mathematical theory for such things as MagLevs, and those hobby coilguns all over youtube?
AGAIN, I WOULD LOVE TO SEE MORE RIGHT NOW!
very difficult to understand with all the skipped steps...
do you write backwards?
Yes...a skill I developed as a baby...
Aren't all number really the same at the end of the day?
What do u think the average impedance of a man's scrotum would be? I'm going to try to make a RLS(resistor, inductor, scrote) circuit v soon. Stay tooned
B....J -- we are all but a series of ones and zeros....
@@ThePhDEngineer legend... You will go down in the history books
Thank you so much. My professor has a foreign accent and a silent tone. You have helped clear things up for me in one of my classes.
Your arrow is tilted upwards, but the switch moves sideways, that is really confusing...
I really had a bad time trying to understand what my professor did on the whiteboard and what the book was expecting on me, and you come up with and make everything so simple and understandable without a simple KCL. Thank you so much for this video!
this video was immensely helpful and I am sad you are not posting videos anymore, regardless I hope you are doing well in your life.
Took me a minute to figure out that he wasn't actually writing backwards, but just mirrored the video.
are you writing everything backwards on the board so itll show up normal on our side? O.o
it's a visual effect that is done in editing
Look at the logo on his shirt
1. Shoot the video with glass in front of you.
2. Invert the video horizontally.
Dr. Montgomery.... you'r a good man.... thank you
Thanks!
was quite excited at the beginning, then stop when all steps are skipped........
How to analyse if a step voltage applied to parallel RLC circuit at t=0...?
how u get -8?
four years later but I can answer that. So once u expand the KCL knowns --> 0A + 8A + C (dv/dt) = 0 (Step 2 move the 8 to the other side. aka subtract. ) - 8 = C (dv/dt). ----> (Step 3, divide out C) 8/C = (dv/dt)
Yaramean! lol
thank you, I have an addiction now
Feed the beast!
what the hell is Wd and how did he get that equation to find Wd
Thank you sir for a good explanation, have enjoyed new steps you've shown.
you skipped the important steps.
God bless you.
And you as well
thank you sir
You're welcome!
Why is it in parallel if the 8ohm resistor is in series with the voltage source?
jrmusante1 once the switch is flipped. That side of the circuit is no longer active.
Can you please do more videos on forming the characteristic equations for RLC circuits, 2nd order, forced response, Laplace? Thank you. Your videos are very helpful.
+Shaun K. Johnson Hi there and thanks for the comment! Unfortunately, I am not teaching circuits at the current time...and do not have access to the nifty recording setup I used for these videos. Hopefully you can find others on TH-cam that address those items!
@@ThePhDEngineer "I'm not teaching circuits at the 'CURRENT' time." I like that!
Legend!
Hell yeah!
Great instructional video
You're Awesome! Thank you!!!
you left out the a for the e? should be e^-at
a was found to equal 1 in the previous steps, so e^-at = e^-t
@@mrOmar432 ahhh ty
Thank you!!
awesome
love you bro
Love you too!
how u get -8?
+zacharyzackify The currents drawn are guesses of the direction, and i of c actually goes the other way and will be negative 1 in the equation... current is going to want to flow from the pos side of the cap to the neg side thru the resistor to get there. therefore since it opposes or goes into the node it should be negative
+jon iodi That is exactly right! Thanks for the comment...
thanks!
I understood why it negative but I don't understand why 8 ☹️👌
why is the omega d in front of the constant A2 after taking the derivative?
kindly upload more videos at basic tricks in circuit about solving nd applying
Ohm my gosh you should try this application! Stumble Upon: 'Circuit Solver' by Phasor Systems on Google Play.
You look this like too easy and simple! Great work! :)
Can anyone test this out and give feedback? Stumble Upon: 'Circuit Solver' by Phasor Systems on Google Play.