I am officially done with all chemistry topics!!! *-* wow. Thank uu MSJCHEM! Now let's solve some past papers) ! Have an exam on 14th May, fingers crossed
It is due to a phenomenon called deshielding. Knowledge of this is not required in IB chemistry but it is useful to know. "Deshielding: The electrons around the proton create a magnetic field that opposes the applied field. This reduces the field experienced at the nucleus and therefore decreases the frequency required for the absorption. Therefore the chemical shift (delta /ppm) will change depending on the electron density around the proton. Since electronegative groups decrease the electron density, there will be less shielding (ie. deshielding) and the chemical shift will increase." www.mhhe.com/physsci/chemistry/carey5e/Useful/nmr.html#Deshielding
The chemical shift of CH3 as mentioned in the data booklet is 0.9-1.0. So, how does the peak at 2 indicate CH3? I'm really confused. Can you please help?
“Deshielding: The electrons around the proton create a magnetic field that opposes the applied field. This reduces the field experienced at the nucleus and therefore decreases the freqency required for the absorption. Therefore the chemical shift (delta /ppm) will change depending on the electron density around the proton. Since electronegative groups decrease the electron density, there will be less shielding (ie. deshielding) and the chemical shift will increase. “ www.chem.ucalgary.ca/courses/353/Carey5th/useful/nmr.html
I am officially done with all chemistry topics!!! *-* wow. Thank uu MSJCHEM!
Now let's solve some past papers) !
Have an exam on 14th May, fingers crossed
Best of luck in your exam
how was it
?
Thank you for the videos, you make IB chemistry so simple.
thank you for updated video and the explanation of "chemical environment"
god bless you. I've been struggling with this so much! thank you!!
Glad I could help.
this man is a god
Thank you so much. These videos are helpful but at 3:17, why is there no peak at 0.9-1.0 range for -CH3?
It is due to a phenomenon called deshielding. Knowledge of this is not required in IB chemistry but it is useful to know.
"Deshielding: The electrons around the proton create a magnetic field that opposes the applied field. This reduces the field experienced at the nucleus and therefore decreases the frequency required for the absorption. Therefore the chemical shift (delta /ppm) will change depending on the electron density around the proton. Since electronegative groups decrease the electron density, there will be less shielding (ie. deshielding) and the chemical shift will increase."
www.mhhe.com/physsci/chemistry/carey5e/Useful/nmr.html#Deshielding
@@MSJChem you just couldnt explain this in the video
The chemical shift of CH3 as mentioned in the data booklet is 0.9-1.0. So, how does the peak at 2 indicate CH3?
I'm really confused. Can you please help?
“Deshielding: The electrons around the proton create a magnetic field that opposes the applied field. This reduces the field experienced at the nucleus and therefore decreases the freqency required for the absorption. Therefore the chemical shift (delta /ppm) will change depending on the electron density around the proton. Since electronegative groups decrease the electron density, there will be less shielding (ie. deshielding) and the chemical shift will increase. “
www.chem.ucalgary.ca/courses/353/Carey5th/useful/nmr.html
Give fortis an A
?
Thanks! It is really helpful
+이준식준식 You're welcome.