Mechanics: Resolving vectors at angles (A-level Physics)
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- เผยแพร่เมื่อ 11 มิ.ย. 2016
- This video is about resolving vectors on slopes for A-level Physics - Mechanics. Sorry for the lack of uploads, (A-levels take up a lot of time).
If you have any questions about the video or the topics it covers - Leave a comment or email me at everythingalevel@gmail.com
Thanks for watching, hope the video helped!
My man this question came out for my test and I blanked out XD
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This is making so much more sense in my head now! Thank you :)
What a surprise, the best explanation on a topic in physics, on youtube, is by a fellow student, cheers
Thanks so much! I finally understand this you are a life saver
your video and explanations are awesome
please make video about cooplanar forces
Would you have to take into consideration the friction on the box from the slope, which would be acting in the negative direction if the box is pulled up the slope?
Man... I didn't understand why we had to draw w1 and w2 even after 3 teachers explained it to me. After u said "u need to RESOLVE" I immediately understood. As physics teachers I think they should at least mention the important terms. I guess it's just that they are.... badd....Very bad
not all of them!
Hey just a question, in your last example you resolved the force by multiplying it by sine but you did not do that for weight (multiplying by cos)? You resolved the force parallel to the plane so why did you not do the weight perpendicular to the plane too?
as that is balanced by the reaction force acting in the opposite direction to the cos component of weight
Oh my gosh. Thank u so much.
I've just started A levels physics and this helped me!!! Thanks a lot!!!!!!!!!!! :)
How did u do?
thanks very much.just dat when we where adding F1 and F2 why did we add as if they where scalars when they are acting at an angle to each other
thank you so much
Thank you so much you are a life saver😊
Thank you ! I UNDERSTOOD !
Thank you! Sometimes i struggle to know when i should resolve or not though.
Hey, I came here to find out how you know where in the triangle theta goes, and I still don't understand, since it wasn't explained in the vid ("because of geometry"). Anyone able to explain? Thanks
Consider the fact that the parallel component (W1) makes the angle theta with the horizontal. If we extend the horizontal beyond the weight force, then we can add up the sum of the angles on a straight line (180 deg). The weight force makes an angle of 90 deg with the horizontal, leaving the remaining angle as 90 deg subtract theta (angles on a straight line). This last angle is also the angle between the weight force and W1 in the vector triangle diagram. The sum of the angles in a triangle = 180 deg. Therefore, the remaining angle, which is the angle between W and W2, must be equal to theta.
I hope that helps. I wish I could have drawn a diagram
I also don’t understand it. Can someone please explain🙏🙏
@@nkanyisongcobo5811 thanks!!
@@nkanyisongcobo5811ur a w for dat
Finally someone can make sense to me❗
Quality video thanks for helping me out
Amazing sir superb 👏 I really get all this concept cleared now otherwise I never got this cleared thanks alot 😊. Have a great day.
How did u find the angle of the triange?u said they r same bt can u show it plz?
why arent we finding the resultant force by drawing a vector diagram ?
thank you so much
if you could please make a video for or a pdf link for more questions like this.
Thanks so much man
I don't know why you gave up making these physics videos, but just know you stopped me from giving up on physics
Thank you that was helpful
thank you bru.
consider me a new subscriber 😭😭this made so much sense, thank you so much!!!!!
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Life saver
Since the force is acting downwards at F1 wouldn't the value calculated be negative?
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Thanks a lot
you know how you said that F is equal to W1, is it negative because it is in the opposite direction or is it just the exact same number? Thanks
If the question made it clear that there was a positive and negative direction then I would make it negative, but normally I would just leave it as the exact same number. In my experience, questions are really asking for the magnitude of friction and don't care about the direction. (But don't quote me on that, I don't know what specification you're using so it could be different.)
So grateful to you but how did you calculate the value of sin 35'
You can use a calculator in most exams to calculate with trigonometric functions
Perfect.
At 9:54, how is the angle 35? Since the given angle is not part of the diagram, I am not sure how they are equal?
Can we even consider the force of 5 kg block positive?
Mahrukh IM mass is not a force weight is
Shouldn't the answer be -4.66 in 2nd question ?
Thanks
You're great
Why did you use sin in the second example
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What is your name bro?
I didn't understand on how you came up with the 49
really helpful
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Thank you SO x 10^100 much
I was looking for it everywhere
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wow this is sum else you should b a teacher my man
that was helpful but i dont get how youn know wether to do sin(-) or cos(-)
You need to know that, in a right-angled triangle, sin(x) = o/h, and cos(x) = a/h. (There's no special reason why these equations are correct - the definition of sin and cos comes from these equations, so you can't really derive them.)
i think i should just stop wasting my time at school and just learn on youtube
cause these guys teach way better than any of my teachers ...makes me angry jus thinking about it!
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Hey can you tell me any other Physics tutoring youtube channels
@@Nohandlenonamenothing there definitely isn't one... I just used to look for a topic and learn but khan academy was on my list and I cannot remember the rest... It's been almost a year lol
such great helo
kindly make some more videos, you are awesome
you are literally my dad.. ty
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umm come back please 😭😭😭
I don’t understand why you did 98.1N - 28.13N, because they are not acting in the exact opposite direction
they are
In facebook?
i love you
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bruh im doing gsce physics why are my teachers making me do this
I didn't understand anything
Yuuuuu
Thanks