CHEMICAL KINETICS || 2nd ORDER KINETICS || INTEGRATION BY SEPARATION || MSc | BSc

[@riteshpandey8586]

Sir mene khud se hi a>b and b>a ke liye solve kiya hai sath sath

[@laiqzada2698]

Sir i m helpless but just I can pray for you ...love from Pakistan ❤❤❤

[@rambabumeena3950]

Aap ka chemistry ka knowledge amazing hai sir

[@pritishreebhuyan1835]

Thank you sir for such a beneficial playlist on kinetics.

[@enigmatichembrom7959]

Thanks a lot sir
Sab clear ho gaya aapke wajah se

[@ayeshasiddika4709]

Just mind blowing❤❤❤..Thank you so much😊

[@sabikunnahersumi6355]

Thank you very much..it is very much helpful to unterstand

[@prakharjaiswal3890]

k= 1/(b-a) ln( (b-x/a-x)*a/b ) for b>a

[@kabeerkumar4334]

And If you take out - common from 1/(b-a) and use property of log(a^x) = x log(a), then you will see expression is same

[@shekharsuman2831]

No kabeer

[@shekharsuman2831]

He is right

[@cricket.updates124]

Best teacher ever

[@MIVSIO]

a-b me se - common leke usko log ke andar chadakar Jo anwer ayega vo hi hoga agar b>a

[@diamondhunter2708]

Thankyou so much sir

[@sultangaming5953]

Thanks sir love from.pakistan

[@shubhamrivonker642]

Thank You sir.

[@nehasolanki7460]

sir you look like south indian hero 😅

[@abidurrahman531]

Thank you, this was very helpful

[@subhendunayak]

Sir always 1st 🥇🇮🇳✅

[@VG__]

Since u explained the whole integration concept again, i am subscribing to your channel sir. Thankyou it was much needed....there's my exam in next few hours and I needed the explanation desperately.
Thankyou sir, plz keep raising the concepts from basics as always:-)

[@pushpendrapatel8567]

Thank you

[@umarqadri4108]

Sir video bhut achi thee

[@saikatbiswas808]

Thanks brother

[@snigdha247]

Thanks sir❤️

[@mysterious7639]

8:32 Sir x cannot be greater than a and b as it is the value converted into products
So why have u used -ve sign before ln(a-x) and ln(b-x)
I tried hard to get the answer but i can't get it

[@Amankhan-wt1nz]

Thanks alot bro

[@rinasharma1963]

Thanks sar

[@priyankadey8423]

Sir..kya iss case ka half life period possible h??

[@anshitayadav5250]

Sir what's the cost of taking subscription for your channel, for msc?

[@Chemistryuntold]

i dnt have any course right now will update once i launch it.

[@AyushKumar-v4q1r]

Sir iska half life period🔴 vi batao issi method se

[@ADP_NEWS]

Sir bht fast speed hai please slow slow btaya krei

[@rinasharma1963]

Vry gud

[@aditishukla5341]

Nice

[@AmanKushwahaGNeet]

Par apne uske hisab se 1/a~b to cancel hona chahiye n

[@anuragdhotare9801]

Are sir 12 ke liye bhi banao na videos

[@mysterious7639]

You must be having pcm sir by the way nice explanation

[@Chemistryuntold]

Yes, thanks

[@Cmagoyat]

Sir atomic structure kb krwaoge ????

[@syed..43895]

Seep fast bro plzz slow speed

[@harshaljadhav4338]

💯

[@sumitkr9320]

Sir collision theory start kro

[@Chemistryuntold]

Time do m out of town

[@AN-or1ed]

Sir words bada likona sir

[@sahilpuri4530]

Thanks sir 😊