Russia | Best Approach To Solving This Math Olympiad Problem | Viral Math Trick.
ฝัง
- เผยแพร่เมื่อ 18 ต.ค. 2024
- Hi my great people, here before us is another wonderful and nice video tutorial to learn some great math tricks from.
Watch the full video for all the hidden tricks in math algebra.
Subscribe for more videos of this kind from this channel.
/ @onlinemathstv
Like, comment and share with others pls 🙏🙏
#maths #viral #viralvideo
Nice video
This is one of the best video online as far math is concern on TH-cam 👏👏👏
Should not be. He got a wrong answer for n. Did you even watch the video before commenting?
I believe a smaller integer that satisfies the problem is n = 6,156. The professor actually minimized x rather than n. If we consider x(n) as a function of n, then it is easily shown that x'(n) < 0 for all positive n. Furthermore, x(0) = 20. Thus as n increases from zero, x decreases from 20. From the given expression for x^2, we see that x^2/2 must be an integer. If x = 19, then x^2 is 361, which is odd. If x = 18, x^2 is 324, an even number. It then easily follows that sqrt(10,000 - n) = 62. Solving for n gives 6,156.
Thumbs-up for this analysis sir.
You are right. The professor should please make a new video for the task.
The professor probably looked for n so that numbers sqrt(100+sqrt(n)) and sqrt(100-sqrt(n)) were both integers.
Number 6156 is not a perfect square. If you replace it in the initial expression
X=sqrt(100+sqrt(n))+sqrt(100-sqrt(n))
You get 2 irrational numbers that actually add up to 18, but you have to prove it with tedious calculations with the double radical formula.
@@sauzerfenicedinanto "...you have to prove it with tedious calculations with the double radical formula." The proof is in what we have already done. Nothing more is needed.
Check Dr PK Math. He got 6156 as n in a nice solution
This one was not from Russia. This one was from Harvard MIT Math Tournament. Dr PK posted this problem before. And you got wrong answer sir. Watch Dr PK video on this one and make a new video.