For an equivalent reason that the arrow has its tip at (4,3)... the line has to start from (1,1) and finish at (4,3) so any arrows, circles, etc. drawn as endpoints of the line have to be contained within these points.
When you rotated the a 180 degrees, you increased the distance from the line from 10pt to 15pt, yet the letter actually moved closer to the line instead of further. Why?
It is because the centre of the rotation is the midpoint of the line. Therefore, the order of transformations is: 1) move the node above left of the line; 2) rotate node around the midpoint of the line; 3) move the node 15pt above left from its current position. So the reason that it appears closer is only because it has further to travel. You can see this if you keep the distance to be the default (0pt): \draw (1,1)--(4,3) node[midway, above left] {$a$}; \draw (1,1)--(4,3) node[midway, above left, rotate=180] {$a$};
Thank you very much, the best video I've ever seen about this. Following since now. Huges from Brazil. ;)
Thank you .. greeting from morocco 🇲🇦🇲🇦
This is terrific. I just finished learning HTML but this LaTex is much better. Thanks.
This is much more than I expected. Thank you so much!
How to display a text on a circular area using polar coordinates?
Thank you for this very important (to me) tutorial!!!
why does the circle's center, at the end of the line, not located at (1,1)?
For an equivalent reason that the arrow has its tip at (4,3)... the line has to start from (1,1) and finish at (4,3) so any arrows, circles, etc. drawn as endpoints of the line have to be contained within these points.
Great video! Thanks!
Great stuff, thanks.
When you rotated the a 180 degrees, you increased the distance from the line from 10pt to 15pt, yet the letter actually moved closer to the line instead of further. Why?
It is because the centre of the rotation is the midpoint of the line. Therefore, the order of transformations is:
1) move the node above left of the line;
2) rotate node around the midpoint of the line;
3) move the node 15pt above left from its current position.
So the reason that it appears closer is only because it has further to travel.
You can see this if you keep the distance to be the default (0pt):
\draw (1,1)--(4,3) node[midway, above left] {$a$};
\draw (1,1)--(4,3) node[midway, above left, rotate=180] {$a$};
This is great, thank you
This video was super helpful!
Your program , in the notes does not compile .
Amazing! Thanks 🙂
Thanks. 👍
Just wanted to point out, the abbreviation "pt" stands for "point", not "pint". See en.wikipedia.org/wiki/Point_(typography)
Thanks!
thank you for this tutorial
Awesome
doesnt even compile on my machine...
this is really clear thank you!
This is horrific. I just started learning PeRL and this math debug project is much worse. Welcome.
Thanks