Problem 2 on Conjugate Beam Method [ HINDI ] | Structural analysis-1

Problem 2 on Conjugate Beam Method Structural analysis-1
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[@sidd_0101]

left side downward negative is taken in shear force so 20 and 13.33 will not come negative they are upward already

[@DevilGaming-up9rp]

Hmmm sbhi positive ayenege S.F. At C me bhi jb aap L to R jyenge OR jo B.M. h usme bhi kunki clockwise is also positive OR kunki B.M. at C positive h to deflection at C point is also downward hogi

[@DevilGaming-up9rp]

Vese calculations ke results same hi rhenege bs signs change honge

[@suhelpatvekar964]

Sir slope and deflection ke liye sign humme SF aur BMD mmt criteria se Lena hai na..(jaisa ki problem 1 me bataya tha..)

[@stockstepper]

We can divide the trapezoidal shape into traingle and rectangle

[@Bhavnamahor1234]

Thanks you sir

[@afzalahmad3827]

Sir yaha or jab aap *slope* find kiye hai to saari value negative liye hai aur iske part onle wali video mai aap jab *slope* find kiye hai to waha pe value positive liye hai *How sir*

[@swikriti368]

bm uper jani wala + ve but at last aap ni -ve q kiya?

[@milindpote6970]

Is problem me trapezoidal ko rectangle and traingle me convert karke 2 load lenge to chalega kya ?

[@adilshah7450]

But ha possible hai but exam mein time kam hota hai these way is much time efficient btw Best of luck exams 11 ko hai

[@milindpote6970]

@@adilshah7450 please reply me this msg : ye trapezoidal ka formula hai vo left side max.hai right ke comparison me isiliye use kiya hai....agar right side badi huyi to bhi yahi formula use kare kya ? Aur C.G hai vo kaha se kaha pe act ho jayega ? Yaani badi vali side se ya choti vali side se
Please reply me 11Tarikh ko mera SA-1 hai isiliye

[@Gauravmahendravlogs]

Currently Studying(dying) in IIT 6 7 hours me exam hai mera, pure sem kuch ni phada ab yt ki videos hi last umid hai

[@oniyatania529]

In cantilever beam B. M at free end is zero which means B. M at c will be zero

[@GaneshShegar]

sumPi umpi but in question ... Clockworks 10 KN moment is given naa
If there was nothing then we should take 0

[@Shubham-ps9bf]

@@GaneshShegarthat moment is clock wise so can we take it as positive at C which will be +10KN

[@subhodipcivil6774]

thnx sir.

[@SunilKumar-gd6kf]

How u got height 2

[@hassankhattak3112]

is area of parabola not 2/3(b*h)???

[@rushabhparikh4797]

(1/3)*b*h bro
It's kinda late ik 😂

[@niteshjoshi35]

Trapezoidal ke C.G. me h=2 kyse aaya

[@cricketorigin4793]

Bhai aap over hanging pr bhi problems banau

[@rajashekhar.garampallimath2989]

Area of parabola is 1/3(h×b)

[@hassankhattak3112]

it,s 2/3(b*h)

[@gulabchandmahawar2694]

Bhai yr thoda sahi btao phle Jaise vdo me btaya vese batao na isme kuch smj ni aya

[@cricketorigin4793]

H=2 kase put hua

[@rajshekar-nm3fh]

Wrong solution, area=1/3 base*height and cg at 1/4 or 3/4 is outrightly wrong

[@surajmourya7161]

Why don't you reply in comment?
I want ask about your method , because some time you taking shear force positive and something negative why ? In last video you take positive and here you taking negative

[@GaneshShegar]

Dear I'm not able to understand your Doubt
Sign Convention of Shear Force is ( R Up | L Down = - ) and( L Up | R Down = + ) .. sometime it become hard to explain on Comments

[@sidd_0101]

ya left side downward negative so 130 will come positive because it was already negative when we find it

[@rajukumarsharma8800]

Thanks sir