Find the Arc Length of a Function with Calculus

[@disagaharasgama7994]

please make more Cal 2 videos. We need you

[@rere-x6g]

remember this for calc 3 and during your last unit of calc 2 there should be parametrization (most important thing for calc 3 that I slacked off on because it was the end of semester)

[@MaharaMsefula]

This guy should be highly recommend on you tube

[@QuocDatPhung]

Hehe thank you!

[@HappyDishHappyLife]

This is VERY well explained. Gold medal.

[@QuocDatPhung]

I'm happy that you enjoyed it!

[@AlvisKalibanda-f2x]

This is very good, he made me realize what I have been looking for for some months now. more blessings to you

[@QuocDatPhung]

Thank you very much! Please kindly subscribe and share! You can find all of my Calculus II videos here: th-cam.com/play/PLeTO6OT3-FKmuCeO97iKt_Aibx-a938JA.html

[@sun650]

Thanks so much! Great video, really helped me out for an exam :).

[@QuocDatPhung]

I'm really glad to hear that Sun! Please kindly subscribe or share! I really appreciate it.

[@tanishakatoch7064]

Thankyou this is very helpful ❤

[@QuocDatPhung]

You're welcome! I'm glad you like it! You can find the rest of my Calculus videos in this playlist: th-cam.com/play/PLeTO6OT3-FKmuCeO97iKt_Aibx-a938JA.html

[@henkoegema6390]

Well done! 😀

[@QuocDatPhung]

Thanks so much Henkoegema! You can find all of my Calculus II videos in the following link (don't forget to share and kindly subscribe!): th-cam.com/play/PLeTO6OT3-FKmuCeO97iKt_Aibx-a938JA.html

[@temwananimumba-7508]

Thank you ❤

[@QuocDatPhung]

You're welcome Temwananimumba :)!! I'm really glad you enjoyed my video! I would really appreciate if you could share with your classmates or kindly subscribe ~ you can find all of my Calculus II videos in this link: th-cam.com/play/PLeTO6OT3-FKmuCeO97iKt_Aibx-a938JA.html

[@stephenboadu1225]

you saved me sir

[@QuocDatPhung]

You're so welcome Stephen! Please kindly subscribe and share with classmates, and you can find the rest of my Calculus videos in the playlist here: th-cam.com/play/PLeTO6OT3-FKmuCeO97iKt_Aibx-a938JA.html

[@nomsaphiri9620]

do you offer personal online tutorials?

[@QuocDatPhung]

Hi Nomsaphiri! I don't offer personal online tutorials, but please feel free to ask my questions in the comments. You can find the rest of my Calculus 2 videos here: th-cam.com/play/PLeTO6OT3-FKmuCeO97iKt_Aibx-a938JA.html

[@nomsaphiri9620]

@@QuocDatPhung thankyou this is very helpful

[@vincenciussufijanhadi1287]

How if, Y = 1 - x^1/2 , and x = 0 until x= 1.
How long that curve.

[@QuocDatPhung]

Hi Vincen! Please use the formula mentioned in the video and let me know what you got!

[@quorbsky3237]

Quote that thing

[@Zainab-ft2vj]

Hi, how can I find the arc of length of a function with 2 points ( , )( , )?

[@QuocDatPhung]

Hi Zainab, can you give me an example of what you mean?

[@pratikkulkarnibodybuilding2433]

did you forget 1+ to add in last example cx formula has it and you just subtracted f(2)-f(1)?

[@QuocDatPhung]

No I did not forget. I did add +1 at 12:06. Let's see why:
The integrand 1+(1/4)y^6 - 1/2+1/(4y^6) = (1/4)y^6 + 1/2+1/(4y^6) and I wrote it correctly. Let me know if you see it now.