Python Programs - Armstrong Numbers

In this python programming tutorial you will learn about the Armstrong numbers in detail with different examples.
Armstrong numbers are the number of nth digit which is equal to the sum of nth power of its digit.In this tutorial we explained you how to find out whether the given number is an armstrong number or not and also we wrote the program to find out the armstrong numbers in particular range.
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[@AmulsAcademy]

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Easily explained. I searching for a great video to understand amstrong numbers program. Finally i found it. Thanks for the video mam

[@AmulsAcademy]

Glad it was helpful!

[@ahmadnadeem870]

To make it more easy, i just typecast the number to get each part separately. Means apply for loop on str(153)

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[@syedsabeer1027]

really it is true, oops till now i have been remember every given value suppurated and cubed then add, if the result is equal to input that no. is an Armstrong number. every time googling its shows like that.

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[@shaileshsarda5694]

Another alternative method to calculate the Armstrong Number:
### Get the number
n = int(input("Enter the number: "))
### Convert to string
n1 = str(n)
### String Count
count = len(n1)
### add a string to list
n1 = [int(i) for i in n1]
### find the power of each number by its count and store in D list
D = [ ]
for i in n1:
j = i ** count
D.append(j)
### Initiate the dummy variable for the addition of list
sums = 0
for num in D:
sums += num
### Driver function to check the number is Armstrong or not.
if n == sums:
print("Its Armstrong Number.")
else:
print("Not an Armstrong number.")

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[@AmulsAcademy]

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[@ravipremani6201]

Very nice tutorial, one question - is 0 also an armstrong number ?

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[@webcreationstudio7088]

value=str(154)
count=len(value)
re=0
for x in value:
temp=pow(int(x),count)
re=re+temp
ans=re


if(ans ==int(value)):
print("yes")
else:
print("not")

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[@AmulsAcademy]

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[@malaiyarasank5092]

It is a Armstrong number

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[@AmulsAcademy]

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[@johnstabbyman5704]

I came up with the following solution on my own. It seems to work
def is_armstrong(num):
tally = 0
n = len(str(num))
for i in str(num):
tally = (int(i)**n) + tally
if tally == num:
return True
else:
return False
for i in range(1001):
if is_armstrong(i) == True:
print(i)

[@aruninfotechche9174]

some simplified
def is_armstrong(num):
tally = 0
n = len(str(num))
for i in str(num):
tally = (int(i)**n) + tally
return tally == num
for i in range(1001):
if is_armstrong(i)
print(i)