Class 11th - Bending of a Cycle on Turning | Laws of Motion | Tutorials Point

Laws of motion - Bending of a Cycle on Turning
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Lecture By: Mr. Pradeep Kshetrapal, Tutorials Point India Private Limited

[@nashp1694]

Best physics teacher in the universe. We will always miss you sir.

[@baconpowerroblox1255]

What happened to him?

[@stylebgmi]

Fantastic explanation. Thankyou sir.

[@supreemdahal4277]

Thankyou sir, appreciated it ❤❤

[@bhuvaneshwargoram]

Fantastic explanation

[@bhuvaneshwargoram]

❤❤❤❤❤

[@shabnam_sajida]

Thanks a lot . Sir . Well explained

[@thethirdview513]

Sir figure me centripetal force ki direction bhi dikhaate to easy pad jata ... Abhi samjh nahin aa raha ki centripetal force kahan lag rha hai

[@kirtimayeepanda7674]

Towards centre

[@thethirdview513]

@@kirtimayeepanda7674 i needed @ which perticular point it is working..

[@rishabhtripathi4453]

Thank u so much sir
U are great🙏

[@kishore5311]

@Sushant Chauhan straight

[@bishalhamal2020]

Thank you sir ♥️♥️♥️

[@krishna-ng8ge]

Thank you so much sir

[@kannadachemistryradhika8699]

What's about friction?????

[@ercop215]

which is very less the the contact between tyres and road is very low
but in case of car friction will act

[@ms.lavanyathanigainathan9301]

Thank you sir...

[@riteshpanth7041]

Thank you very much sir 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏

[@Green_3.14]

Where is frictional force ?

[@sunandashukla6303]

easy to understand sir

[@alphonseerlich239]

R (uppercase) as what and the units?

[@Muna-nh6qs]

Newtons.

[@prashantverma6323]

Thanks sir

[@sohanisharma628]

Thanku sir...

[@saikumaramaan7772]

🙏🙏

[@kkpandey6458]

Sir please iska note se available kara dijiye sar please I request tutorial point

[@blakshmi2858]

Sir can you start live classes

[@prakharsatyam6259]

Ye sir expire kar gaye

[@among_AI]

He passed away 😔

[@HaamroNotes]

@@among_AI how did he die? Please reply if y know

[@namangupta1010]

sir the derivation is completely wrong but the ans is somehow correct. You have changed the definition of the contact force in your derivation, the contact force is always perpendicular to the the surface of contact .We usually bend the cycle to overcome the torque due to friction. we shift our center of mass to overcome the torque because if we go straight the frictional torque will throw us back. the contact force is perpendicular to the surface and there is a frictional force acting inwards. If you want the exact derivation I can mail you.

[@bmworld8046]

It is not normal reaction it is only reaction

[@sciencedost4903]

Can any one tell me that for 2 wheeler banking of road is necessary or not

[@Physics_Show]

@@bmworld8046 bhag chutiye

[@keyconcept1248]

We can increase θ in a certain angle which is depend on the coefficient of friction between the two surface , here N(normal reaction) =Rcosθ=mg
and Rsinθ=mv²/r =μmg

[@Vijaykumar369S]

Good sir..Thanks a lott sir

[@adhavan.a7964]

ggs my boi passed me

[@jaunpurpointtechhd3100]

Thank u sir.I also teach physics

[@rakeshsiddh9872]

Ram ram keshterpal ji

[@apurvasharma13]

Thanks sir👌

[@apurvasharma13]

@Sushant Chauhan brother r cos is on upward direction and its work done is zero 😁