Thank you so much ABJ sir. It's 2:17 am rn. I am here in Kota and have star faculty but wo aise padhate hai jisse subject me interest hi mar jaaye. I can't tell how grateful I am to you. Aapne Physics sambhal li.
sir 2024 mera drop year hai quki physics mera utna aacha nahi tha isiliye mera advance 2024 me AIR 18366 aaye so iss sal maine soacha and aapne senior bhaiya se salah liya to unhone aapke baare me bataya vo aapse hi padh ke IIT KGP me gaye hai thanks sir whatever you read becomes much clear.........
Sir it was hurtful seeing you so sick but still teaching to the best of your capability. I pray for your good health and well being. Your efforts are not going in vain, you have helped so many students in clearing doubts and understanding tough concepts. We get a teacher like you only once in our lifetime. I am eternally grateful to you sir 🙏
Lets take a moment to appreciate his dedication towards teaching and hard work that he is doing for all of us... Even with cold & cough he is working hard to impart education to us HATS OFF TO YOU SIR....
Sir in the last question when the induced current will flow through inductor it will create a magnetic field and it will exert force on the rod. So why have you not considered that?
sir 25:00 par jo aapne second equation likhi h wo ham energy conservation waali bhi likh sakte h na??? (Q2-q2)/2C=1/2 Li2 ????????????????????????????????????????????????????????????????????????????? please anyone reply
sir you had explained in previous class that at time = 0, current passing through inductor is 0 but in the above illustration you are considering current at t = 0 E/mur I can't understand what changed in this scenario
25:17 why sir took opposite sign of charge on opposite side.. i mean generally we take +q at place of -q 👀 it makes it look more tougher 🙂🙌 ohh i got answer syd shi h.. that in capacitance chapter charge was growing in every question.. but here charge is decaying 👀🙂 1:11:13 mereko sirf mg force dikh ra🥲 kaise solve kruu😢 1:25:37 siir you forgot to find i.. i have fiinded it out i=gm/Bl[1-cos(Blt/√m√L)]
last question me current toh find hi nahi kiya. i am assuming current will be normally found out from integration of vbl - L(di/dt) = 0 , jahan par v at a particular time ki value daal denge?
@@existential_turtle same mera bhi yahi aaya bas mene velocity wale expression ko differentiate krke NLM wale equation me put kr diya, same result obtained
For current, use that equation, Blv = L di/dt, write v = dx/dt. You will get Blx = Li. Put value of x obtained as a function of time here, to get i as a function of time.
Sir it was heart wrenching to watch you cough , i respect you dedication sir , it will remain an example for me
omg this channel is so under rated brilliant.
I am unable to put my appreciation in words for you sir..Take care of your health also sir
correction at 1:05:25 it would be R^2=4L/C instead of 4LC
Yeah
Stay safe and healthy sir..hope u will fit nd fine soon
Thank you so much ABJ sir. It's 2:17 am rn. I am here in Kota and have star faculty but wo aise padhate hai jisse subject me interest hi mar jaaye. I can't tell how grateful I am to you. Aapne Physics sambhal li.
True yaar same
same
Exactly same , Mera physics se intrest khtm ho rha tha par apne sambhal liya maine Puri 12 th ab TK aapse hi ki hai❤
kya rha result
Allen mai??😂 mai भी hoon😢
Singer me kk
Aur padhai me Mohit tyagi sir both are underrated but truly gem
Excellent lecture . Thankyou sir .
Please take care of your health.🙏🙏🙏
Hats off to u sir ❤️❤️❤️even after so much cold you are teaching with full efficiency 💕💕💕🙏
sir 2024 mera drop year hai
quki physics mera utna aacha nahi tha isiliye mera advance 2024 me AIR 18366 aaye
so iss sal maine soacha and aapne senior bhaiya se salah liya to unhone aapke baare me bataya vo aapse hi padh ke IIT KGP me gaye hai
thanks sir
whatever you read becomes much clear.........
hey , 2025 aspirant here, mind giving me your contact?
@@abhijeetchoudhary6279 no
SIr,
1:05:15 mai R square= 4L/C hoga na.....
ab to ap budhe hogye honge
@@NEET-eb3ve Bruhh
bro how was ur jee result?
@@ishanaryan3177 tu jaankar kya krlenga
Out of the world teaching
Are you from another planet?
ee is gola ka nahee hai
Sir ,take good care of your health🙏🙏🙏....
Sir I make mistakes, by getting distracted and then I regret but repeat same after few days.
Plz guide
By what u get distracted brother?? 😕
@@akshitkanwat5102 garls
Don’t get distracted then 😃
@@akshitkanwat5102 everything.
😮Ok😊@@blackjackal9506
Sir's knowledge, understanding, way of expalnation is next level.... I dont have words to appreciate sir
Sir it was hurtful seeing you so sick but still teaching to the best of your capability. I pray for your good health and well being. Your efforts are not going in vain, you have helped so many students in clearing doubts and understanding tough concepts. We get a teacher like you only once in our lifetime. I am eternally grateful to you sir 🙏
Sir, I salute you Sir, I salute you for your hard work❤
respect , sir is teaching even in bad health
1:05:22 critical damping will be
R^2= 4L/C*
not 4LC
Lets take a moment to appreciate his dedication towards teaching and hard work that he is doing for all of us...
Even with cold & cough he is working hard to impart education to us
HATS OFF TO YOU SIR....
Iss baar exhaust ho gya ekdam sir mai to is topic kochodunga
Best explaination on lc oscillation
respect sir for your dedication you are the best 💥💥💥💥🙏🙏🙏🙏
for last question current is: i = mg/ lB { 1 - cos(Blt/sqrt mL) }
Differentiate velocity expression (dv/dt) and put it in nlm equation
You can also put v in Li=vBl and integrate. Same answer
😞 sir please take care of your health ☺️🙂😊 best teacher ❤️
Accha hua yeh channel zyada logon ko nhi pta competetion km hota hai 😅
3:26 9:43 13:40 17:02 25:53 29:42 31:03 37:44
current in circuit in last ques = mg/Bl(1- cos(blt/(mL)^(0.5)))
49:40 56:27 1:03:06 1:06:07 1:10:52 1:17:23 1:21:00 1:25:22
for current at any time t:
Solve vBl = L(di/dt) to get:
i = Blx/L
from this you get:
i = (mg / Bl) .{ 1 - cos(( Bl / √mL )t) }
Superb Dedication.
Best physics teacher 👌🙌😍😍😍
Sir you are god of physics
your dedication is at the another level thank you sir
Kya question tha ek no.
52:11 it's 2023 and nta has removed damped oscillation for jee mains 2024
Apna kam kar samjha. Jyada gyaan Dene ki jarurat nahi hai chomu..
@@srijantiwari8152Bhai aap revision karne aaye ho yaa fir aapka bhi syllabus meri tarah peeche hai?
@@srijantiwari8152 tu kr bhai apna kaam
doosro ke comment section me reply krke doosro ko hi apna kaam krne ke liye khta hai lol
Is damped lc removed?
@@anjaliingle7756 no gurl it isnt
Good lecture ❤
Is Damped LC oscillation is deleted from jee mains 2025 ??
Sir u won our heart
Best inspiration for us❤😢
Thank you sir for this amazing lecture
sir ye jo 29:43 pe jo result aaya hai vo resonanace frecuancy wala hi hai kya alternating current me ka result wala jaesa
last question was just wow sir
1:25:45 Sir Apna hi itna layak bana hai 🥺❤️❤️🫡
sir at 24:46 can u explain it again how u wrote negative sign
Bcz q is decreasing that's why he put -ve sign
dq=FQ-iQ= some negative value so to make it positive he put -ve sign
Or a Separate Playlist is to be made for this Unit
Thank You Sir😊
Awesome as always 🥳
Sir get well soon
Sir in the last question when the induced current will flow through inductor it will create a magnetic field and it will exert force on the rod. So why have you not considered that?
1:20:12, but it's released so how it has initial velocity?
THANKYOU SIR! 🙏
you are god for me sir ji😍
sir 25:00 par jo aapne second equation likhi h wo ham energy conservation waali bhi likh sakte h na???
(Q2-q2)/2C=1/2 Li2
?????????????????????????????????????????????????????????????????????????????
please anyone reply
sir ye mene pehle socha tha but 39:00 par aapne kara diya
Thank you sir ❤
Best Wishes..
happy teachers day sir
Thank you sir 🙏🙏🙏
sir comparison karke tho sab kuch aassan hogya
last ques was good
At 1.05.52 R²=4L/C not 4LC
0:03 1:07:50
Very helpful sir
sir you had explained in previous class that at time = 0, current passing through inductor is 0 but in the above illustration you are considering current at t = 0 E/mur I can't understand what changed in this scenario
Current will be E/R at steady state and sir has considered t=0 to be steady sate in that problem
Thank You So Much Sir
33:09 what if value of Root(LC) is even. Then the results are not generalised
How?.., I don't find any logic in your question
@@llight4619 these type of facinating questions were asked by so called toppers of class for desturbing avg people
You are calling me avg🥺@@manishm1__
If value is even........ Still we can get the result by same.... Putting value...... Energy will still be conserved...... Nothing changes
This question deserved to be on quora or reddit
But not here
1:00 1:09:00
Jee mains SESSION 1 29 JANUARY 2024 SHIFT 1 DIRECT QUESTION ASKED ON LC OSCILLATION DONT MISS THIS
?Is damped lc circuit deleted from jee portion
take care sir thank you
9:15 59:02 1:17:00
thank you sir
thank you sirr........
25:17 why sir took opposite sign of charge on opposite side.. i mean generally we take +q at place of -q 👀
it makes it look more tougher 🙂🙌
ohh i got answer syd shi h.. that in capacitance chapter charge was growing in every question.. but here charge is decaying 👀🙂
1:11:13 mereko sirf mg force dikh ra🥲
kaise solve kruu😢
1:25:37 siir you forgot to find i..
i have fiinded it out
i=gm/Bl[1-cos(Blt/√m√L)]
What percentile you get?
@@darakhshayasmeen selection hua ya nhi
Damping deleted hai na ?
11:00
jee main date out bro
done thanks sir
sir 1:00:50 pe jo aap likh rahe hain usko aapne kahan pe samghaya aap batayenge please
Shm
last question me current toh find hi nahi kiya. i am assuming current will be normally found out from integration of vbl - L(di/dt) = 0 , jahan par v at a particular time ki value daal denge?
for current at any time t:
Solve vBl = L(di/dt) to get:
i = Blx/L
from this you get:
i = (mg / Bl).{ 1 - cos(( Bl / √mL )t) }
@@existential_turtle same mera bhi yahi aaya
bas mene velocity wale expression ko differentiate krke NLM wale equation me put kr diya, same result obtained
sir ap last question me current ka expression nikalna bhul gye
Ac esme me padaoge ???
Sir how many lectures to go in this chapter
L C occilation 2022 adv question
1:26,kya kya chal raha h aaj kal🤣🤣
kya hua saale
thanks
Sir please take care of yourself
Thank you sir 😈
Advance ani assalu ee video neee chudale 🚫🚫🚫
Take care of ur health 🌼🌼🌼🌼⛱️⛱️☔⚡💧🌧️🌦️
Sir why 12 lecture of EMI is private ???????🤔🤔🤔🤔🤔🤔🤔
No
Sir modern kab se hoga sir
Sir modern physics kab start hoga??
ac ,emw ..
Sir this should be L11 ?
I guess
1:05:22
Sir please sheets chahiye groups me add karu
sir in last question what is the current
For current, use that equation, Blv = L di/dt, write v = dx/dt. You will get Blx = Li. Put value of x obtained as a function of time here, to get i as a function of time.
sir advance wale course mai nahi ho woh kyu puch lenge
best💯
31:00
Thank you sir
💥
🙏🙏
😀
Startt