Practical XI: Law of Parallelogram Part-2

Physics Experiment Demonstration:
OBJECT: To determine the resultant of two vectors(forces) using Law of Parallelogram Method
Physics Practical XI material: bit.ly/2LbiOsQ
Physics Practical XII material: bit.ly/2INgERR
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[@Yuvyadav123]

How tremendously u explaine everything. It was also taught in every scl but student's does not have enough time to remember it. It is very helpful for who are going to give practal tommarow. Excellent

[@baisakshipradhan6770]

Youraj Shing yeah even our teacher don't explain it so clearly like this sir.

[@tanvibhatt7472]

Who else have a practical tomorrow??🤔😂😂😂😂
Thnx bhai very helpful😇

[@neelamgarg2696]

I have my physics practical tomorrow 🤣😂

[@anashafeez27]

Meh!!😅😅😅

[@tanvibhatt7472]

Tushar Garg
Cms gn 1 student???
😂

[@tanvibhatt7472]

Anas Hafeez
Hum logon ko practical ke ek din pehle hi yeh gyan chahiye hota hai🤣🤣🤣

[@anashafeez27]

@@tanvibhatt7472 hnnnh....
Aftrrall we so soo genius😅😅😂😂😂

[@animakashyap821]

I'd skip the schl on the day of this practical and was very tensed for my exam .......But I understand totally from this video...Thanku sir💐💐

[@piyush2776]

Watch in 1.25x it will help in saving time 🙂

[@ashasmhatre1717]

Ya really

[@aashthachaubey6302]

No in 1.5 × speef

[@gauri9319]

M watching in 2x

[@hunter09835]

I just watched it 1hr before my practical exam ....one of the member of late gang😂😂

[@izbasiddique9423]

Sir such a beautiful explanation u hv done .... all the doubts are vanished.... highly appreciable hardwork done !!

[@rashmiverma6669]

Practical in 2 hours..who else in the gang?

[@ErnestGumla]

Me 😹😹

[@pulkit.singh8899]

Me

[@anuragsingh8005]

Me 😭

[@Sohambhattacharya247]

1 hr

[@ayeshabaig9516]

Me

[@divyanshi1143]

This is really very helpful.....
Now I have idea what is happening in this experiment... Otherwise my school teachers were not interested at all in explaining this to students.... 🤷‍♀

[@itsnirashree]

yea same heree bro

[@monikam9478]

🔥🔥😱😤😥😦😧😨😩😰😟😱😲😳😵😶😷😞😒😍😛😜😝😋😗😙😘😚😎😎😎

[@ayushisingh6457]

Very helpful thanku very much l had gone through so many videos but can't get the video with good explanation but then l got your video that was just awesome thanku again

[@ThePHYsicsOne]

Most welcome 😊

[@swatinaikar8248]

U saved my life😄😄😄😄

[@srashtigupta4170]

God bless you sir i am not present in this practical so i m little scare about it but ypu clear all my doubts

[@nasrausman2271]

Same is the case with me..😊

[@nehachalla4140]

Same here🙋

[@hussainabbas9060]

Thanks bud. I have my practicals tommorow i think i can pass now( coz i am sure this thing will be on my exam)

[@supermoji]

Thank you SO much sir❤

[@t_o5638]

Gud one ! Btw advertisement was 🔥 lit

[@deepchandsharma2058]

Thank you brother it helped me a lot for my practical

[@alokyadav2956]

Splendid job , this helped me in my exams . I am thankful to you.

[@ThePHYsicsOne]

Excellent

[@RajaArslan-p5z]

Detail video that clarify all doubts😊

[@kabhi.kabhi.aditi21]

Hey thanks I was so worried bcz I can't get my calculations correct but now it's easy..........and I have subscribed your channel bcz it's really useful

[@indiankitchen8090]

Thanks bhai verry usefull vidio

[@nishantsrivastava6508]

Thanks bhai kl pratical hai tumbe meri bhut help ki thank u so much 😁😁😁😁😀😀😀

[@ismaehsanulhaq4159]

Sir agr rectangular components method ka ay to b ye same yhi krna h I'm too much confused 😕

[@anubhavtomer9794]

Thanku it's really helpful me for my practical

[@sankaranganesan294]

Mast vid

[@maheensohail1541]

Cm ko gm wt me kasy convert kiya sheet pe??

[@creavitycorner786]

Thank you so much for this helpful video 😊

[@prempatel1633]

Bahut acha video hai

[@harshitshukla2110]

This is very helpful for class 11th students

[@ravishrivastava4157]

Thnx dear sir very helpful 🙏😊😊 God bless u keep doing such work n keep making experimental helpful videos

[@pranavpina]

Really nice explanation in two parts.

[@rabyakhan1054]

If the answer of equal is zero so what I do it is correct or not..? Plz guid me

[@krishmistry2608]

9:10 how did you calculate the values? Like, how did you find Cos(62°)??

[@ravindrazade9517]

From log book

[@xcarnage8632]

cos 62 is about 1/2

[@aryannarhe9699]

use calculator

[@himanshuprajapat3184]

Wow wotttt... Great teaching style
Thanks a lot

[@samarthamin6312]

Watching while practical is going on😂😂

[@behnoshnaveed471]

What did you use thread or rubber band

[@FAISALSAPIEN]

thread, for more clarification chk part-1

[@rhemankhan9083]

His sheet per ap practical krna ka bta rhe hn is sheet ka name btaden?

[@urdupointkesath2569]

Specimen sheet or drawing sheet

[@sanatan_hi_satya_hai037]

Thank you s much sir

[@sharolsandhu3441]

what can we write for sources of error for this experiment?

[@sarfaraz.7605]

Thanks a lot teacher 👌😊😃

[@VishalSingh-sq5hd]

thank u so much sir it's very helpful

[@sahdhahmatheen9421]

Bhai this was so good . Though Icant understand my own country language , I could understand hindi more💪🏼🙃

[@FAISALSAPIEN]

Thnx for the complement

[@aayushraghuraman5023]

Thank you sir. Amazing explanation

[@hydrashafiq7964]

Awsom it is really helpful for me😊😊

[@quranicsayings]

Thank u So Muchh Sir❤

[@ramankaur2070]

Will we be given this sheet in exam?????

[@nimra6098]

Please ap 2nd year practical Mein bhe meri help kr dijiega

[@kritikasharma2734]

So nice explanation

[@ThePHYsicsOne]

Thanks and welcome

[@shadab_30]

Ye shinchan ki awaaz lag rahi hai lekin explanation bahut achha hai bhai

[@ishitanath563]

excellent videos, amazing explanation. life safer before practical exam

[@sourjyabose584]

Saver

[@sourjyabose584]

Autocorrect lol

[@joshua_dlima]

1.5x speed was perfect

[@ShakeelAhmed-yw9pw]

Very well explanation.... thanks alot for this💜💫

[@taiyabtanveer327]

You are good teacher you halp Mee in my exams thanks

[@rogerthat6395]

Awesome.... ⚡
I appreciate your hardwork.... 🙏

[@ziazakria9552]

ThanX sir😇

[@rahulkusmare1584]

Sir (to verify the law of polygon of forces by the wooden board ) ye wala bhi bataiye

[@papusingh4361]

Thank you sir

[@ThePHYsicsOne]

Welcome

[@AdamAli-oz5gp]

Sir why is there a difference in value of R' and R ?

[@ThePHYsicsOne]

Error.

[@mohdamaan7067]

Best 👍💯👍💯👍💯

[@javedsaeed4065]

Thank you for this video

[@nasrausman2271]

Bht acha padhaya bhai...

[@yashagrawal3062]

Sir jo hamne weight liya tha centre me and jo value calculation se aayi vo different kyo hai.

[@ThePHYsicsOne]

The difference b/w calculated and measured value is just because of error in measurement.(referred as human error)

[@shristypoddar4972]

What if my calculated weight is coming more than the graphical weight???
The error will be negative then

[@ThePHYsicsOne]

@@shristypoddar4972 The error can be calculated by the formula error = (|Standard Value-Observed Value|)/Standard Value. In this formula the observed value is either calculated or measured value and standard value will be 7.0 cm or 70.0 gram in equal weights or 9.0cm or 90.0 gram for unequal weights. Both the calculated and the measured value have error (human) when compared to standard value.

[@shristypoddar4972]

@@ThePHYsicsOne actually my doubt is can the error be negative??

[@ThePHYsicsOne]

@@shristypoddar4972 The error cannot be negative, only taken as positive , actually error shows the deviation of observed result from the actual result.

[@pcvlogger5721]

Sir aap video kue nhi Dal rhy

[@AbhishekMishra-et6ke]

thank you Bhai ...ache s smajh a gya 😉

[@qyqlakholakho8720]

Thanks a lot great

[@sivarajsiva9624]

This was extremely helpful..

[@Whynot176]

Thankyou so much sir

[@pramodkumarsinha7614]

very nice sir ji

[@jafarsafety7594]

Nice explanation

[@Lovergreat9422]

LAJAWAB A1 EXPLAINATION

[@anushmn2768]

really helpful and cool. thankyou

[@crypticliar]

Tysm

[@rashidmurad3755]

Love you sir

[@hazel_hehe]

Thank you brother

[@PiyushSharma-uu3tn]

Apne cos 55 ki value kaise nikali

[@asifzaheer5688]

Koi mjhe koi or website bta de js pr pracyicals hooo.

[@obaidrahman129]

Thnxxx! Sir

[@babluvrskama6064]

Thank you sir it is very Important

[@Abhishek-lt4ep]

Pura samaj aa Gaya sir

[@oversoulevi5715]

Thnx sir pratical in 2 hour

[@ThePHYsicsOne]

All the best

[@saurabhchauhan293]

Sir ur pronunciation of angle is really nice at 1:45 🤣🤣

[@shabbirzaki6456]

Sir apan ne Jo plane mirror se points trace kiye uska kya kaam

[@ThePHYsicsOne]

with the help of the point we have tracked and trace "Y" shape on our sheet

[@shabbirzaki6456]

@@ThePHYsicsOne
Thanx Sir

[@prajwalpraju8192]

U explained neatly but video is not that much of clear

[@ThePHYsicsOne]

Do watch in 720HD

[@llawliet7362]

Thanku sirji...

[@rishisaha2655]

Very well explained
Thanks a lot.

[@samarthyachaturwedi5486]

Your welcome dear.....

[@vibhumalik1089]

i was actually amazing!👍

[@GauravKumar-ew1ec]

Thank u sir.

[@abhishekanand5526]

A very-very thnxx to u sir!!
🙏🙏🙏
U just nailed it...

[@chromophone8796]

Thanks

[@sagarverma5129]

Thanks it was helpful

[@ThePHYsicsOne]

Glad it helped

[@shivsin.kakhandaki3065]

How to calculate of cos?

[@ThePHYsicsOne]

use calc.

[@rehanzahoor8567]

nice sir very useful.

[@navbhaskar1294]

Thanks sir..

[@AftabAlam-ts6dt]

Txxx sir g

[@kushagragupta4381]

How do we find the value of cos 55 at 8:57

[@aayushminti]

Take approximate value of cos 53, which is equal to 3/5 or 0.6

[@kushagragupta4381]

@@aayushminti but if we got angle like 85 then?

[@aayushminti]

@@kushagragupta4381 you won't don't worry, if you get then your lab assistant will provide you with a book for reference as well

[@kushagragupta4381]

@@aayushminti thanks a lot dear, it had been concerning me!

[@vipindahiya8726]

Thnks brooo

[@nimbapatil9198]

Nice

[@jyotisatidasani8996]

thanks sir
very useful

[@yashagarwal762]

Me too

[@DeepakKumar-fe2xo]

Nice teaching sir

[@gaytriyadav1262]

Thanks sir

[@dheerajreddy4236]

I am have practical exam this week.. Who are having practical exam this week