When multiplying the mass with acceleration to find the force, why was the acceleration of gravity used? Do we always use that value for these types of questions?
I'm given a similar problem but in US units. It states the liquid weighs 29 pounds per cubic foot. I've replaced the 1000 in the equation with 29, and replaced the gravity from 9.8 to 32.2; everything else is the same, but my answer is wrong. Are there other steps for dealing with non-metric units?
Im not workimg in kg per m. I did the same problem for a parallelogram tank and never had to use 9.8 constant. I just used f=pv = density x volume, the dw=f x distance whwre distance equals height minus y (or x, whatever)
Wow thank you! I have yet to hear this problem explained so concisely, you are incredible!
Thank you. Glad it helped.
Two To TEAN
Thanks for the slow and thorough explanation!!
You're welcome. Glad the video helped.
3 years later, and this video is still helping people out. Thank you!
You’re welcome. Glad it helped.
Anyone else get ASMR vibes from his voice 😂 Great video!
Thank you.
Thank so much, this video was super helpful! You explained everything really well!
Thank you. Glad it helped.
I'm not understanding why the integral would be from 2 to 10 rather than 0 to 8 if all the water is being pumped out.
It’s from water closest to the top which is 2 to water farthest from top which is 10.
Why did you multiply the weight by x and dx. Isn't the formula of the work just equal to the integral of force times dx? why did you multiply by x?
It’s the distance.
When multiplying the mass with acceleration to find the force, why was the acceleration of gravity used? Do we always use that value for these types of questions?
Because it’s in metric.
I'm given a similar problem but in US units. It states the liquid weighs 29 pounds per cubic foot. I've replaced the 1000 in the equation with 29, and replaced the gravity from 9.8 to 32.2; everything else is the same, but my answer is wrong. Are there other steps for dealing with non-metric units?
Don’t include the 32.2. Below is a video I did similar to what you are asking.
th-cam.com/video/dHw-_5kXaNA/w-d-xo.html
Thank you so much
You’re welcome.
Im not workimg in kg per m. I did the same problem for a parallelogram tank and never had to use 9.8 constant. I just used f=pv = density x volume, the dw=f x distance whwre distance equals height minus y (or x, whatever)
👍
very seductive voice