Reading Dumb Theme Park Questions | Part Two
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- เผยแพร่เมื่อ 10 เม.ย. 2022
- We're back with some of our favorite questions from Quora! You wouldn't believe some of the things people say😂
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“Should Dolly Parton become a Dollywood celebrity?”
Yes, and Walt Disney should start sponsoring Disneyland.
Too bad the Paramount parks never were sponsored by Paramount before they were acquired by Walmart.
Bruh....
@@honeywhereismysupersuit6645he’s being sarcastic
That would be so cool if he did. Maybe the ocean should sponsor seaworld too.
That first one was an actual challenge hosted by multiple Six Flags parks during Fright Fest in 2018 and 2019.
Yup
And they call themselves enthusiasts unbelievable
Yeah, I remember Darien Lake doing this challenge in 2019.
That was actually a pretty genius idea if you ask me. Guess they just missed the memo.
@@TheMrdominator1997 Do you remember stuff about what your parents have done 4 to 3 years ago? Yeah no unbelievable
3:00 25 meters
Step by step solution: Ignoring air resistance and friction, the roller coaster car problem can be solved using the conservation of energy. Gravitation Potential Energy (GPE) is the 'stored' energy that a coaster has at the top of the lift hill. Kinetic Energy (KE) is the energy of the moving coaster.
GPE = mass of the coaster car x gravitational constant (on earth it's 9.8 m/s/s) x the height
KE = 1/2 x mass of the coaster car x velocity squared.
At any given instant in time, the coaster car has a combination of GPE and KE. To simply the solution, we'll assume this is similar to a dive coaster where at the very top, 100% of the energy is GPE and 0% is KE.
We don't know the where the coaster is along the track, nor the initial height, only that at a height of 40 meters it is traveling at 10 m/s. Whatever combination of GPE and KE it had at that moment, there is a different combination of GPE and KE when the coaster car is traveling at 20 m/s. If the coaster is traveling faster, than some of he GPE was converted to KE. At both instants in time, the car has some value of KE and GPE.
Total Energy = GPE + KE
Total Energy = mgh + 1/2 m v^2
Total Energy = (mass x 9.8 x height) + (1/2 x mass x 10^2)
If the coaster is now going faster, than some of the GPE was converted to KE. The coaster has dropped by some distance and the velocity has increased to 20 m/s.
Total Energy = mg(height - drop) + (1/2 x mass x 20^2)
The total energy remains constant, so we can set the two equations equal to one another.
(mass x 9.8 x height) + (1/2 x mass x 10^2) = mass x 9.8 x (height - drop) + (1/2 x mass x 20^2)
Now we simplify the formula using algebra.
1) Mass is on both sides of the equation, so we can cancel out the mass of the coaster car.
2) I will simplify 10^2 as 100 and 20^2 as 400.
3) I will also apply the 1/2 factors to the squared velocities. (1/2 of 100 = 50 and 1/2 of 400 = 200)
The resulting simplified formula is: 9.8 x height + 50 = 9.8 (height - drop) + 200.
Distribute the 9.8 on the right side of the equation gives us: 9.8 x height +50 = 9.8 x height - 9.8 x drop + 200
Subtract '9.8 x height' from both sides results in: 50 = -9.8 x drop + 200
Subtract 200 from each side results in the equation: -150 = -9.8 x drop
Divide both sides by -9.8 results in: -150/-9.8 = drop
drop = 15 meters
The coaster's height at a velocity of 20 m/s is equal to the original height of 40 m minus the drop of 15 m = 25 meters.
Thank you lmao the angle, the mass of the train, none of that matters.
it's just 80m 😭😭 if it's 40m high and moving at 10m/s, our goal is to get to 20m/s so 10x2=20 and 40x2=80
@@dyingrabbit350 I can't tell if you're joking...
Just use suvat lol
v^2 = u^2 +2as
400=100+2gs
Assuming freefall, g=9.8m/s^2
Rearrange to get s=15.3m
40m (original height)-15.3m= *24.7m*
Same answer but probably a bit quicker
But yeah you probably explained it better and of course conservation of energy is an equally valid approach
5:39 The fact that Taylor immediately knew that the wookiee homeworld was Kashyyk makes me appreciate him even more.
I heard that and I was moved to tears.
Kashyyyk* :)
Edwardo: “Will Trump do anything bad to Six Flags?”
Taylor in 2016: Fiesta Texas has a huge wall. Trump would have loved it!
No he did not but the Democrats almost ruined the entire industry. If 2021 wasnt near normal we would have seen a ton of themepark bankruptcies
All political developments should be primarily analyzed in terms of their effect on Six Flags.
@@MattMcIrvin lol
@@MattMcIrvin Well if so, Biden is godawful cause Six Flags changed their passes to a more expensive one with way too much less benefits a few months ago. 😅
And the answer is here!
The Don is gonna open a new six flags. Its gonna be the best six flags ever, its gonna be so Six flags that the number six will get a complex. Flags will get jealous. There's gonna be six big beautiful flags over this fantastic park. Were gonna have the best roller coasters ever. Theyll be beautiful. People will come from all over. Believe me, I know fun and this is gonna be the funnest of fun. A big beautiful six flag park with six beautiful flags, you'll see, its gonna be great. Were gonna make Six Flags great again. The greatest.
You know cedar fair could do it, but they don't like themes very much, such a shame. Theming is great. People love it, I love it, but they won't give it to us, so we're going to theme the hell out of our big beautiful Six Flags park! Its going to be incredible!
With that last question, unfortunately, that has become a growing problem at parks, especially the busier ones. Most people are faking some kind of disability, causing the special access to build a huge line, and it ruins it for people who actually need it.
And unfortunately there ARE cases where younger people would need special access
I’ve had a Wookiee burger before and I can’t say I recommend it, the meat was very chewie
LOL
These are so good, you better do a part 3 or you will be stuck on a 45 minute Vekoma SLC.
Disneyland was torn down and turned into that 45 minute Vekoma SLC
I think that first question was about Fright Fest's coffin challenge, where the prize was $300 and a season pass for whoever stayed in a coffin for 30 hours.
Concerning the Leap-the-Dips question:
Having visited Lakemont numerous times over the years, with the latest being in 2020 when the coaster when through a major refurbishment, Leap-the-Dips is night and day depending where you sit in the car. In the front row, it is smooth, perhaps one of the smoothest woodies I’ve ridden. In the back row, even though the dips are mild and the largest drop is only nine feet, there is legit airtime that will send your but crashing down into your seat.
Now, can a baby ride in a harness strapped to the parent? In theory, yes. However, that baby is still at risk of bodily harm, as even the front warrants the risk of the parent shifting mid-ride into the fixed lap-bar, thus risking injury or worse to the infant.
Obviously, the park will say no, but I am going in-length to describe this to illustrate why it is a terrible idea (in case someone takes it to heart).
Great video, you two! Looking forward to your next installment!
As someone who grew up in Houston, tearing down Disneyland would probably result in something much less valuable for Anaheim as a whole. Sure, a large tire fire might be useful to someone, but overall, it will not fill the hole well.
I worked @ AW 1985-89. I'd still buy a pass & went there until it closed in 2005. I also filmed rides going IN, coming DoWn + the whole park going away! Now it's overflow parking for the once a year event HLSR. such a pity!
As a former park security member, you usually get charged for trespassing and banned from the park
Phillip’s just like: We should just take Disneyland and PUSH IT SOMEWHERE ELSE!
Dang it you beat me to that joke
Like a piece of furniture! LOL!
Coaster Studios: Is a G rated channel for many Years
Sarah: *bleeeeeeeeep*
Today at school, I was telling one of my friends that I’m going to SeaWorld Orlando over the summer and he told me that ever coaster at SeaWorld Orlando was bad. I showed him the POV for Mako and he said “Yeah I rode that one, it was boring, all it did was go up and down.”
Im willing to bet money that they didn't even go on it
Ride I-305 or Fury and tell me they’re boring cuz they don’t flip or loop
3:54 This reminds me of The Little Prince.
They took everything inessential and made it essential.
They turned toy planes into paperclips, and stars into electricity.
And they used technology to speed up the aging process and turn children into adults faster.
1:40 I have been this guy. Skipped the gate at a Dutch theme park by possibly the most Dutch method. Stepping across a sluice. I was a teen rebel okay, I would pay now I'm an adult. Also good luck guessing the park and location of the sluice to sneak in, it's still there if you feel greedy
I know someone who entered Disneyland Paris at the same time as his brother and entered for free that way. It is definitely possible lol
I’m feeling Slagharen.
These are the questions of geniuses 🤣🤣🤣 I was impressed
2:57 It's just a simple physics question on energy and the conservation of energy (Initial Energy = Final Energy)
It seems that both Gravity Potential Energy/GPE (mass * gravity * height) and Kinetic Energy/KE (1/2 mass * velocity^2) play a part in this
Since no mass was mentioned, you can cancel that portion out.
Gravity is 9.81m/s^2, Initial Height is 40m, Initial Velocity is 10m/s and Final Velocity is 20m/s
Main Formula is: Initial GPE + Initial KE = Final GPE + Final KE, the final height coming from Final GPE
So just add in the values and you get: (9.81*40) + (1/2 10^2) = (9.81*height) + (1/2 20^2)
Solve it and round out to the nearest hundredth and you get: 442.40 = 200 + (9.81*height)
Subtract 200 from both sides: 242.40 = 9.81*height
Divide both sides by 9.81, and you have your final answer for the height at 20m/s (rounded out to 2 decimal places): 24.71m
As long as you know the formula, it won't that hard, thankful I can finally put what I learned in physics to use 😅. Just lmk if you guys need any clarifications
Cedar Point workers are very aware of how to get into the park for free. I had a coworker that worked one summer at the Point then continued to go for free *years* after. Apparently there's a worker entrance that once you know you know 😉 If stopped he would say he left his tag/pass in his locker. Always worked.
EDIT: not condoning what he did simply sharing.
Dolly Parton and Kenny Rogers each opened an amusement park. That's why we have Dollywood and Kennywood.
Islands in the stream.
Hey dude👋 we met at great adventure on the 11th and i just want to say it was a pleasure meeting you and hope you guys keep making awesome videos🤟🏼🤟🏼
I'm loving that Levi shirt. 🔥🔥🔥
"What if you strap them to your chest? In one of those baby sacs?" IM LAUGHING UNCONTROLLABLY🤣
I love the reaction to the Doritos question 😭😭😭😭
4:49 as someone who has ridden leap the dips, you actually get some of the scariest airtime EVER if you sit in the back. Also, they used to allow babies on it but don’t anymore.
These are so good
If they built a 40 minute RMC it probably would only have a 4 minute queue... at least a couple of months after launch when everybody realised it was a stupid idea. I reckon I could lap Millennium Force for 40 minutes though... or maybe something like a B&M hyper, something without twisty loopy bits
Hahaha, baby sack! Classic
Phillip sounds like the one person who likes or agreed to the shin guards on Coast Rider.
45 minute 🎢 is back to back rides on Mako without leaving the seat lol.
6:22
Toverland's 24 hour Troy challence: lemme introduce myself
I would love to see you guys reactions to final destination rollercoaster scene.
We need a part 3!
To answer the question about Leap the Dips, both my daughter's rode it at 1 year old. It was there first coaster. They seriously let me hold them on the ride. To be fair, they we're between 1 and 2 so they were probably closer to 2 years old
Great video coaster Studio ! I went to Six Flags Over Georgia and I meet Koaster kids and this is my second time meeting them!
oh my god
7:06 most amusement parks use the ADA gate (wheelchairs and disabilities) which just means that guests who aren’t capable of being apart of standby have a place to wait how long the line would normally be, they can then ride
This is the case now, but it used to be that they could indeed just hop onto the ride with no lines. I have autism and qualified for this, so the 2000s decade was super awesome for me at theme parks...
do more of these pls
Will you make a vid of the New parque Warner coaster please?
Well acceleration is roughly 9,8m/s/s meaning it would take 1 second to reach that speed in a vertical drop without air resistance. In that one second you travel roughly 15-20 meters which means roughly around the 20-25 meter mark
Bro my Dads friend came over for dinner the other day. We live near Toronto, and my home park is Canada’s Wonderland. He said that he heard that they were gonna move the roller coasters to MarineLand in Niagara Falls. I was cringing so hard. Epic GP fail. He said that they would probably get more visitors down there since it’s near the U.S. even though Canada’s Wonderland is the most visited seasonal amusement park in North America. Lol.
2:58 the question cannot be answered because we don't know if the train is currently experiencing any acceleration, or the train is moving at a constant 10m/s and then some acceleration is applied at t=0. I bet this person is not in a higher-level physics class, where you will also have to account for friction and air resistance.
If I were a trolling-type physics student, I would say "this is a launch coaster where the launch is angled upwards, so I would say 45m high." I assume they're talking about acceleration due to gravity, but I feel like a good physics question would specify that.
Assuming it's the case that the car drops off the MCBR going 10m/s, we can start by saying that our desired velocity is (20m/s - 10m/s) or 10m/s. We can plug that into our equation Velocity = Acceleration * Time. Solving for time means we will have gained 10m/s in ~1.02 seconds. Now that we have time, we can then plug that into the distance function, D = (A*t^2)/2. This leaves D being ~5.10. Putting this back in context, this means that we will have gone down by ~5.1 meters to add 10m/s to our velocity, which means that if we start at 40m off the ground, we will be at 34.90m off the ground when the car reaches 20m/s.
It's clearly assumed that the coaster is in free fall down a hill. It's a conservation of energy probleml, comparing potential energy (mgh) to kinetic energy (1/2 mv^2)
The answer is 25 meters. It can be solved using the conservation of energy where the sum of the gravitational potential energy and kinetic energy at any point in time is constant. The complete solution is in my other comment.
You can tell Phillip is a member of the Home Owners Association that can’t get a good nights sleep because the Disneyland fireworks keep waking him up every night lol
1:21 that was also my concern.
Hey, nice repeatedly running into you at Hershey yesterday (along with my New Zealander friend). Bummer all the top rides were down for your visiting friends. :-(
6:32 I couldn't believe it myself but yeah, it's true, Doritos were in fact invented at Disneyland. I had to look it up but it's very true.
And they could celebrate "Life Day" in Wookieland!
The first one is real. When I went to discovery kingdom in 2018 people we’re actually doing this during fright fest.
7:10 "the next cArT"
To answer that maths (I'm British so that's the correct spelling) problem you need to know the angle of the drop and the curvature (which makes the equation a little more complicated)
The question is clearly a conservation of energy one. You're comparing the potential energy at the start (potential energy = mgh where m is mass, g is the accerlation due to gravity, a constant, and h is the height) and the kinetic energy at the start (kinetic energy = 1/2 mv^2, where m is mass and v is velocity. Because m shows up in both equations is why the question doesn't need a given mass. I'm pretty sure that's enough info to calculate it.
"Why do we stand in a 45 minute line for a 4 minute ride? This seems backwards..."
2017: *Ellen's Energy Adventure has left the chat*
2:57 - Assuming there's no resistance, 24 meters and 71 centimeters. (rounded out to whole centimeters) There you go.
very cool
Leap the dips has no restraints and some SERIOUS airtime.
Are you ever going to make new 5 year plan videos?
'' Disneyland should be torn down''.
Disneyland and knotts: I’m tired of California I’m getting in a car and driving to Oklahoma
I mean, Trump DID institute the steel tariff that is one of the causes for the price hike for coasters, at least from European manufacturers.
And the Democrats almost destroyed the entire industry with their lockdowns and mandates
He also dismantled pandemic prevention programs within the federal govt. No guarantees that Covid wouldn't have happened had they stayed in place but those actions certainly didn't help.
@@tearingmeapartlisa1080 This, along with the culture that pushed conspiracy theories over science, is why the U.S. has 4% of the world’s population but suffered nearly 30% of the world’s CoVID deaths. And that’s despite having some of the best CoVID medical responses on Earth.
I worked at a cedar fair park....was 30 minutes from the end of my shift and never got my break....and angry/ aggravated hot and irritated and I cursed people over the ride speaker, and left. I was told I was banned from cedar fair parks.....park's...... but season pass went thruand I spent the summer at cedar point
2:58 80m
0:34 that's what she said
Leap the Dips has no restraints so I'd imagine no to that question.
Hey you should get coaster bot to do more step by step gides
At 3:00, not enough information given to answer. We don’t know the mass of the train, the angle of decent, the coefficient of friction between the wheels and the track, the radius of the wheels, or how many wheels there are.
First of alll, it's clearly an ideal physics problem where resistance doesn't matter. I'm too high rn to be certain but there's another commenter who said the same thing, I'm pretty sure the angle has nothing to do with it nor does the mass (everything falls at the same acceleration due to gravity, what the question is asking is irrelevant to mass).
The question is clearly a conservation of energy one. You're comparing the potential energy at the start (potential energy = mgh where m is mass, g is the accerlation due to gravity, a constant, and h is the height) and the kinetic energy at the start (kinetic energy = 1/2 mv^2, where m is mass and v is velocity. Because m shows up in both equations is why the question doesn't need a given mass. I'm pretty sure that's enough info to calculate it.
@@vancewade6251 well it’s not “clearly” an ideal physics problem, if someone asked me this I would want to know all of the information. You are right about mass canceling out in the conservation equations, but you would still need to know the mass to find the normal force in order to find the static friction force.
@@wickedsickfunkyfreshroller2037 okay maybe not clearly but it’s definitely someone asking a homework problem on quora for high school or intro college level physics which means by default it’s an idealized mechanics problem (no friction, no air resistance, etc.) and it reads to me pretty definitively that it’s a train in free fall down a hill the whole time and you’re merely comparing two points with known information during that free fall
The answer is 25 meters. It can be solved using the conservation of energy where the sum of the gravitational potential energy and kinetic energy at any point in time is constant. The complete solution is in my other comment.
Taylor, You mention Jungle Cruise at Disneyland but not Indiana Jones or Pirates?
Soooo actually July 17th, 1955 a man built a ladder over the back fence of Disneyland & charged $5 per head to get IN. So, there's THAT! Not to mention that around 20k tickets were counterfeited & ppl gate "crashed" and said they were friends of Walt's. Scammin' on the 1st day! That's Y Phillip be hatin' on Disneyland.
July 17th, 1955? That's the day I thought up the idea of the flux capacitor! no, wait...
I actually met a guy at my first visit to six flags America saying he fakes handicap stuff all the time at six flags and kings dominion. I was like yea that’s cool. Meanwhile I’m thinking yea I’m never gonna do that lmao
I know that many people fake it. Especially at busier parks, a vast majority of people who are doing it are faking it. The line for special access on some rides can be spilling far down the midway. It's ruining it for people who actually need it.
I'm pretty sure the first one is just an analogy to working at six flags as a ride op. 10 dollars an hour to be in a box and as a bonus you get a season pass when employed.
I know this isn't actually what it is about but funny to think about.
no it’s about the coffin challenge six flags did during fright fest
@@blakedorn24 Yeah I know that, I just thought it was funny how similar those two things are.
@@kryptonaight4076 oh my fault didn’t see the second part of ur comment
That first one no way
Not that it matters, since Anonymous prob didn't get the physics homework help they needed, but...
h = 40 meters + (10^2 - 20^2) / (2*9.80665) meters = *24.705 meters* (a smidge under 116 feet)
(Assuming the track is frictionless and the cars are uniform spheres in a vacuum at sea level)
4:59 I saw someone actually attempt to do this on Dark Knight and they argued with me saying she would be fine 🤦🏻♂️
Six flags actually changed their season passes. They made them more expensive.
part 3 when? :P
Six flags great America does the 30 hour coffin challenge
kewl
Well in all fairness Trumps father destroyed Coney Island
Doritos was invented at the old Mexican restaurant at Frontierland.
Nice
0:14
At knotts berry farm I’ve seen lots of people faking disabilities
30 hours in a coffin for $300 is easy money.
Sometimes I wonder, what goes on in peoples head😂
You didn't know that?!?! Seriously?!?! Read The Doritos Wiki you, you, ignore Amos es. And for a really deep Disney dive... Back in the 1960's, inside Casa De Fritos was a huge diorama of a mountain with a mine. (Like a BIG model train layout.) At the front was a coin acceptor. You'd drop in a nickel and you would hear audio of "The Frito Kid" shouting down into the mine to a guy named "Klondike" with something like "Hey Klondike, more Fritos. The best corn chips made!" Klondike would reply:" The freshest too! Crisp, salted, golden brown Fritos! Good anytime! (or another similar exchange.) Then, a bag of Fritos would ascend a miniature conveyor belt "up from the mine". Very surreal. Yeah. Doritos were in fact, invented at Disneyland.
With the one about the came i saw a famoy of 5 at disney world all on scoters to skip the line rise of the resister
Im ment resistence
1:28 wont be open anymore soon
KE=PE+KE'
1/2mv^2=mgh+1/2(20)^2
1/2(10)^2=9.81h+1/2(20)^2
h = 55.29 meters
You're welcome to everyone who was wondering.
And also... Taylor, this is physics not math LOL!
Pretty sure the height should be lower than the original if you gain speed, we're not using LSM's in the equation
@@Silacide if you loose speed, it means you're increasing the height (h). In this case, you go from 40m/s to 20m/s, so you are losing speed and gaining height.
@@aaroncaso5455 You need to read the question again my man, you don't go from 40m/s to 20m/s you go from 10m/s at *40m* to 20m/s at *a certain height*
@@Silacide aaaahhhh my mistake I'll redo it
you can’t answer that question for sure without the friction and air resistance knowledge
The answer is 25 meters. It can be solved using the conservation of energy where the sum of the gravitational potential energy and kinetic energy at any point in time is constant. The complete solution is in my other comment.
There is not enough info to solve the physics question. I’d need to know if there is friction and if the 10 m/s is constant
It's assumed the train is in free fall down a hill. It's a conservation of energy problem. There's plenty of information to answer it. Also this is mechanics here, there's never friction
0:30 if we are talking about KD then
30 inches tall to ride Leap The Dips with an adult...let that sink in
I’m pretty sure you don’t have sufficient information to complete the physics question because while gravity is 9.8m/s you need to account for friction and the slope of the coaster and eeeverything else so it’s impossible but theoretically 1 second if it it’s just referring to gravity
We should take Disneyland and PUSH it somewhere else!
You brainwashed, anti-Disney bots are creeping out the coaster community. Take your nonsense elsewhere.
7:02 yep, it also includes mental stuff like ADHD
Wait, I legit have that! I could I have used the disability line all along?!
@@alexlents4689 ye like at the start of corona. Don’t do what I said. You probably need a doctors note or to show them the meds
The one math question is annoying because sure I can calculate its speed using the acceleration of gravity but without the length, and weight of the train its not accurate, not to mention air resistance, drop angle, and friction.
I don't think that physics question I even possible, there isn't enough information.
2:56 h = 24.7 m
I hope ur watching this Anon
Are you sure it's possible? I don't think there is enough information to fund exactly what the question was.
@@maxhagenauer24 We have to assume no friction, etc. But this answer is correct!
@@claytonkeating4570 It could be at any angle, are we assuming it dropped down vertically? How do you solve this?
@@maxhagenauer24 angle doesn’t matter. It’s a conservation of energy problem. Potential + Kinetic at the beginning = Potential + Kinetic at the end, just solve for end height
@@claytonkeating4570 So if it's drop was 1 degree, it would be the same speed as if it was 90 degrees? How is this?
Next video idea: Reacting to creators who profit off of tragedies!!! *Looks in mirror*
wat
no no no don't shake the baby. 1 year olds I don't know do they die when you shake them?
lol
Their childhood was ruined when they said “Disney should be turned into something more useful”