Integral of the Day 10.6.24 | Another IMPROPER Integral! | Math with Professor V

Here's your latest Integral of the Day! It's an IMPROPER INTEGRAL, and a little more manageable than my most recent upload.
Were you able to solve it? Do you also get slightly disappointed when an improper integral diverges??? Weigh in on the comment section down below. :)
If you need a refresher on the topics covered in this video, look no further:
Infinite Limits: • Infinite Limits | Calc...
L'Hospital's Rule and Indeterminate Forms: • L'Hospital's Rule | Wh...
Need more lectures and examples on Improper Integrals? I gotchu:
Evaluating Improper Integrals Part 2: • Evaluating Improper In...
OG Lecture on Improper Integrals: • Calculus 2: Improper I...
Comparison Theorem for Improper Integrals: • The Comparison Theorem...
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[@tony413chow]

Hi Professor V, thank you for your new video. I used u-sub and parts to solve the integral. I also used L'Hopital to find the limit and the final result was 2. Cheers.

[@mathwithprofessorv]

Great job! Thank you for commenting and your support. :)

[@AndrewJohnson-ur3lw]

I like these that seem to look like they have way complex figures and end up with a resultant value that is simple or a standard irrational constant.

[@mathwithprofessorv]

Yes, they can be so satisfying!

[@vincentmudimeli4430]

That wonderful professor v professor v is Vincent from soutafrica can you have life lesson on change of boundary and javobian I learn calculus from your videos I would appriatenif you go live so we can pose our questions and you help

[@KirkClarkekirkskarat]

The term sqrtt/e^sqrtt, square root t over e to the power of square root t equals zero by L'Hopitale's rule. That was great but you forgot to exponentiate the zero in the limit. The term should not be zero but e to the zero power. The entire limit should be 2 times zero equals zero. Am I correct?

[@mathwithprofessorv]

No, you’re not correct, go review L’Hospital’s rule perhaps.