I have watched and liked each video. Excellent presentations on differential amplifiers, there are not alot of great resources on internet and you have explained all so clearly. Nice work.
At 4:58 Why can you say that the source of the differential pair is at ground. I know that in a symmetrical Differential Amplifier (symmetric load) you can show that the potential above the current source is constant (only in differential mode) so you can replace it with a voltage source which will be a path to ground in small signal analysis. But this current mirror load is not symmetrical so the same argument can't be applied here. What is the argument for closing the path to ground in small signal analysis?
Can someone explain to me please what exactly is the Vbias? Do i have to connect a voltage source or can i simply just connect it to a different point in my circuit?
If I'm not mistaken, the rationale is that if ro is >> RD, then only RD needs to be considered. However, I don't know if your subscript "3" and "1" is indicative of something other than the ro covered in previous lectures...
Superb explanation mam. Highly appreciate you for making this resource accessible to everyone.
I have watched and liked each video. Excellent presentations on differential amplifiers, there are not alot of great resources on internet and you have explained all so clearly. Nice work.
You’re generosity and knowledge is greatly appreciated. So thankful to have access to you’re lectures
Thank you very much. you saved me from hating electronics all my life
Thanks. I am glad you liked the explanation.
Thank you so much for all your help. I know these aren't popular topics, but are so helpful for the bunch of out there who study it!
Good explanation - Thank you! from California.
Very good explanation. It helped me a lot! Thank you from Portugal! :)
Thanks a lot Ma'am. Please continue with your lectures.
very good explanation...
At 4:58
Why can you say that the source of the differential pair is at ground. I know that in a symmetrical Differential Amplifier (symmetric load) you can show that the potential above the current source is constant (only in differential mode) so you can replace it with a voltage source which will be a path to ground in small signal analysis.
But this current mirror load is not symmetrical so the same argument can't be applied here.
What is the argument for closing the path to ground in small signal analysis?
Exactly
Thanks very much! One question, why is the current through M2 in the opposite direction?
because i = gm*vgs with vgs = vid/2 for M1 and vgs = -vid/2 for M2. So the current source is in opposite direction
Can someone explain to me please what exactly is the Vbias? Do i have to connect a voltage source or can i simply just connect it to a different point in my circuit?
Thanks a lot you're like a supergirl.
Very good. just one thing. Can you make the notes sheet or your letter a little bit bigger?
HOW YOU ARRIVE AT THE OUTPUT VOLTAGE OF TRANSISTOR 2 AS VDD- VGS3
Thank you!
THE BEST!!!
what if none of the transistors match? The current wont be i/2
why don't consider the resistance ro3 and ro1 in small signal?
If I'm not mistaken, the rationale is that if ro is >> RD, then only RD needs to be considered. However, I don't know if your subscript "3" and "1" is indicative of something other than the ro covered in previous lectures...
thanks
Why does she have a dude as her profile pic?
Too small figures for smartfon!