you explained it better than many other videos in youtube, i had a fk headache asking why this and why that on other videos solving similar problems, but you left no questions
@@gomez2858 Try it both ways (x^2 + 0.5x - 4.2*10-8) = 0, and the solutions for x are the same as 0.5x= 4.2 *10-8, thats because the 0.5M of bromine already present is WAYYYYY off the charts compares to the bromine added, so its really the 0.5M of bromine that is doubling the mols/L.
Try it both ways (x^2 + 0.5x - 4.2*10-8) = 0, and the solutions for x are the same as 0.5x= 4.2 *10-8, thats because the 0.5M of bromine already present is WAYYYYY off the charts compares to the bromine added, so its really the 0.5M of bromine that is doubling the mols/L.
Thats why you do the chemical equation, to determine how many MOLs are in each side of the equation, and you adjust accordingly based on what you find...but beware if its twice Molarity it will also affect the solubility constant equation, as well as the final MOL amount.
you explained it better than many other videos in youtube, i had a fk headache asking why this and why that on other videos solving similar problems, but you left no questions
Thank you! This was so easy to understand with your video :)!
You've saved my brains, THANK YOU!
Thank you, perfect explanation!
Thank you very much for making this video. You really have helped me. Thank you
شكرا جدا
You didn't square root at the end, so your answer is wrong. It's 2.9x10 -4
Nope, She's right actually. I was confused at first too but she is right.
She's right you don't need to
@@hifriede8581 why tho
wdym why tho, the f u gonna square root for ?
@@gomez2858 Try it both ways (x^2 + 0.5x - 4.2*10-8) = 0, and the solutions for x are the same as 0.5x= 4.2 *10-8, thats because the 0.5M of bromine already present is WAYYYYY off the charts compares to the bromine added, so its really the 0.5M of bromine that is doubling the mols/L.
Thanks so much!
sorry pls what does ksp mean
solubility product
The common ion effect
i'm pretty sure you forgot to square x :)
Nah you don't need to
you don't need to because none of the ions have a coefficient of two
Try it both ways (x^2 + 0.5x - 4.2*10-8) = 0, and the solutions for x are the same as 0.5x= 4.2 *10-8, thats because the 0.5M of bromine already present is WAYYYYY off the charts compares to the bromine added, so its really the 0.5M of bromine that is doubling the mols/L.
What if it was 2:1
Thats why you do the chemical equation, to determine how many MOLs are in each side of the equation, and you adjust accordingly based on what you find...but beware if its twice Molarity it will also affect the solubility constant equation, as well as the final MOL amount.