Sir only one word...I don't know who u r . But u r such a amazing guy...!!! Your way of teaching is Awesome...!!! I learning this derivation since 6 months but you teach me simply One night before the exam....Thank u sir...Love from Karnataka..
Sir i think 1st draw commen tangent and then after draw normal which is perpendicular to comman tangent which is must always passes through pitch point of two gear because without comman tangent , normal can not possible and if you draw then which basis it's normal from which linw it's normal or perpendicular? Ans plz
Hi, Could you please make one video on below part ? compound planetary for different different arrangement and how we can find their respective gear ratio ?
Sir aaj mera exam hai aur hmare university me 1Q. 6marks ka hota hai aur agr aaj ye Q. 6marks keliye aya aur me likh paya to uska credit sirf apko jyega ...thanks 😊🙏
at the point of contact we draw a normal .at this point we draw two different velocity how it is possible?? as we know that at one point two velocity at different direction is impossible
Very nc job...But their is a mistake in the diagram section As u have explained M but it is written as N....N that is Class 10th concept I.e,Similar Triangles 😊
Ye sahi hai na bhai law of gearing kal exam. Ye pura prepare hoo gaya hai par jab you tube ki help se notes banata hu or jab sir dekhte hai to kehte hai ye wrong or puchte hai kaha se likha or hum kehte hai TH-cam se likha hai. Pure notes pe chokdi maar dete hai
As u know the velocity has two components vertical and horizontal. Here to calculate the velocity in horizontal direction it's horizontal component cos@ is used.
After watching many... Finally this video is helpful.. Great explanation 👍
Glad to hear that
Bahut easy se smjh Aya mere dost .... Low of gearing
Sir only one word...I don't know who u r . But u r such a amazing guy...!!! Your way of teaching is Awesome...!!! I learning this derivation since 6 months but you teach me simply One night before the exam....Thank u sir...Love from Karnataka..
Thanks... keep supporting.:)
nice
Sir ek daam ek baar me dek ke samaj me aa gaya thanks sir
Probably the best video explanation of this topic
Great content! Shared it with my friends. Amazing Explanation for the entire playlist!
Sir i think 1st draw commen tangent and then after draw normal which is perpendicular to comman tangent which is must always passes through pitch point of two gear because without comman tangent , normal can not possible and if you draw then which basis it's normal from which linw it's normal or perpendicular? Ans plz
Finally I got it.... thank you very much for helping... that's why I love internet and TH-cam...👍👍
Bahut badiya bhai, acchi koshish kari..
Nice, explanation. Thanks for the videos, please upload more such content, we are waiting to see lot more of these.
Great sir all doubts are clear now 😊
Great 👍
Sir ... ..both acche se apne smjhaaya ..... .
great video bhai❤
U r so intelligent...tq u helped a lot in my exam...nicely explained 👍👍
Finally samjh aya 👍 you just saved my exam thank you sir ☺️
😎😎😎😎really great and easy to learn bro 😎😎😎😎😎😎
Bahaut hi accha explanation....
finally i got the video which explain this topic nicely
Excellent work!
Bohot acha Bharatiy bhasha me seekhna aasan ho jaata he !!
Bahut zabardast Thank you.
Thank sir ek no bataya😍
thanks for this video.....very nice , easy explanation
Ur mobile no plz
Bahot khub...👌
The explanation provided is worth appreciating.. Better than many teacher's.. Hatts off mate
Thanks
Bhaii, Thanks 👍🔥
Totally understand..bro..!
Superb 👍
Very great explained
Bahut hi mast bhaiya
Thanks bhai.
Keep supporting :)
Thank you sir kal exam h apne achhe se samjha diya
Thank you so much. Very well explained. ✨
Simply amazing
+nahid nahid
Thanks
Nice bro..Thnx a lot..
I had forgotten how to derive this. Even thought I can't speak Hindi (?), your derivation reminded me. Thanks!
Hi,
Could you please make one video on below part ?
compound planetary for different different arrangement and how we can find their respective gear ratio ?
gd job sir....
awesome work.
please provide other topics too.
like one after another topic.
such as involute and cycloidal teeth profile after this video.
+Manjeet OK...sure
Nice explanation 👍
Thanks u...sir..👌👌👍
बहुत बहुत धन्यवाद आपका
thank you sir👍...✍️
MastBhai
Good video sir, I need a video related calculate gear module according gear tangential force
Thank you sir🙏
You're welcome 👍
Very nice
how can you draw normal to a point.as far as i know you gotta draw a tangent through the point of contact first and then normal to the tangent
Yes .....I had the same question....kuchvi samajha raha hai banda
Great
+SPARSH SADHU THANKS
Nice bro
suppp awesome sir , plz add sir new video of gear example
+Jay Solanki
Thanks,
Sure examples ke bhi video aaenge
+Jay Solanki
Your video is ready watch it
And don't forget to comment.
Nice
Thanks bro!
sir ap Jo bhi video banate hai kisi topic se related. to video ke last me usse related questions bhi Jo exam me aate hai ko bhi bataye
Thanks for suggesting:)
2 ghante me exam hai
Wish me luck
Second try hai
Main thing is 2 ghnte phle aake dekh rha hai bhai tu video 😂
thank u vry muc sirjiiiiii
nice video #easylearningpoint
Thanks
Mast
Thakns a lot of sir
Thanks sir very nice teach
+ANUJ SAINI
Thanks
Super
thanks bro
Nyc
Thanks sir
Thanku sir....
Thnkx sir
Whick book do u refer
And very much thanks for helping
+Dashrath Meena
I have two books rs khurmi and VB bhandari.
Thanks for watching
+EASY LEARNING
And also some other local books which are normally students use.
+Dashrath Meena
Bro is video ko share karna taki dusre logo ki bhi help ho
SS ratan kesi rhegi
You should reduce amount of ads
best
Coriolis acceleration topic make it sir
Ravi Kumar sir nice video it was helpful
Thanks you so mach sir
+niraj kumar
Thanks for comment
👌👌👌👌👌
O2NP and O1MP, how are they both similar?
there is only 1 same angle which is 90.
Sir aaj mera exam hai aur hmare university me 1Q. 6marks ka hota hai aur agr aaj ye Q. 6marks keliye aya aur me likh paya to uska credit sirf apko jyega ...thanks 😊🙏
Exam kaisa hua?
Accha gya pr badluck law of gearing nhi pda 😑
at the point of contact we draw a normal .at this point we draw two different velocity how it is possible?? as we know that at one point two velocity at different direction is impossible
Yeah right,how is it possible?
Very nc job...But their is a mistake in the diagram section As u have explained M but it is written as N....N that is Class 10th concept I.e,Similar Triangles 😊
👍
Sir plz ek what's app grup bna dijiye
thanks
Aman Wadte
Thanks for watching
Tnx u sir
Ye sahi hai na bhai law of gearing kal exam. Ye pura prepare hoo gaya hai par jab you tube ki help se notes banata hu or jab sir dekhte hai to kehte hai ye wrong or puchte hai kaha se likha or hum kehte hai TH-cam se likha hai. Pure notes pe chokdi maar dete hai
Is video me maine kuchh bate bhi boli hai vo bhi likhani chahie....vest tarika hai video dekho and fir apke pas jo book usko padho sab samaj aa jaega
Tell me cos(alpha) where that come from ?
As u know the velocity has two components vertical and horizontal. Here to calculate the velocity in horizontal direction it's horizontal component cos@ is used.
@@nikhilpanchal8914 Thanks. It helped me actually.
Yarr bhaiii M to kahi mentioned hi nii h aur puri lacture me M hi bta rkhe ho
2 minute pe dekho
Cos to base upon hypotenious hota h na to ap perpendicular upon hypotenious ku lere ho smj ni aaya
Time batao...to me check karu
angle ke samne wali side perpendicular hoti he, so he have done correct
Annoying aads bro pura concentration kharab ho jata h , thoda kam add dala kro bhai..
Ok... Thanks
Tangent kaha hai?
…….
How to assum V1=w1×o1k
Velocity at r distance from centre of a rotating body of w rpm is given by : V = wr
Add bhut zada plz inko htao it's disturbing
Sir you should reply.
Ha bolie
achha smjh aaya but digram whi whi whi bta rhe ho to smjh nhi aa rha h
Most boring Topic in Gear designing
bhai perpendicular to draw kr le thik se .....
bhai tu padai kar le thik se🤣🤣
Improve language
Thanks bro
thank you sir
Thanks sir
thank u sir
Thanks
Thanks
Thanks